Hi Akshay,
Try this:
table(cut(xht,breaks=seq(0,10,by=2)))
Jim
On Sat, Sep 8, 2018 at 8:26 PM akshay kulkarni wrote:
>
> dear members,
> I am facing difficulties in plotting histograms
> in R in Linux CLI.
>
> Is there a function in R which produces a table of freq
On 08/09/2018 6:25 AM, akshay kulkarni wrote:
dear members,
I am facing difficulties in plotting histograms
in R in Linux CLI.
Is there a function in R which produces a table of frequency distribution in
figures rather than plot that distribution?
Something like
e the ().
>
> Many thanks
> Regards
>
>
>
> Sent from my Samsung device
>
>
> Original message
> From: Thierry Onkelinx
> Date: 24/04/2017 3:43 p.m. (GMT+00:00)
> To: abo dalash
> Cc: "r-help@R-project.org"
> Subject: Re
This can be easily done in base R.
The solution below is pedestrian, transparent and explicit. Thus it's easy to
debug and validate(!) each step.
Prepare:
(1) Save your Excel spreadsheet as a text file with tab-separated values.
(2) Initialize a 128 * 128 matrix to hold your results. It should ha
Dear Mustafa,
I'd recommend the packages readxls to import the data, tidyr to transform
the data into long format and dplyr to select the data.
1. read the data into R with read_excel()
2. transform sheet 1 into a long format with gather(). The result is one
row for each patient / drug combinatio
On 11/14/2016 12:44 PM, Bert Gunter wrote:
(Sheepishly)...
Yes, thank you Hervé. It would have been nice if I had given correct
soutions. Fixed = TRUE could not have of course worked with ["a"]
character class!
Here's what I found with a 10 element vector each member of which is a
1e5 length
Here is another variant, v3, and a change to your first example
so it returns the same value as your second example.
> set.seed(1001)
> x <- sapply(1:100,
function(x)paste0(sample(letters,rpois(1,1e5),rep=TRUE),collapse = ""))
> system.time(v1 <- lengths(strsplit(paste0("X", x, "X"),"a",fixed=TRUE
(Sheepishly)...
Yes, thank you Hervé. It would have been nice if I had given correct
soutions. Fixed = TRUE could not have of course worked with ["a"]
character class!
Here's what I found with a 10 element vector each member of which is a
1e5 length string:
> system.time((lengths(strsplit(paste0
Hi,
FWIW using gsub( , fixed=TRUE) is faster than using gsub( , fixed=FALSE)
or strsplit( , fixed=TRUE):
set.seed(1)
Vec <- paste(sample(letters, 500, replace = TRUE), collapse = "")
system.time(res1 <- nchar(gsub("[^a]", "", Vec)))
# user system elapsed
# 0.585 0.000 0.586
Chuck, Marc, and anyone else who still has interest in this odd little
discussion ...
Yes, and with fixed = TRUE my approach took 1/3 as much time as
Chuck's with a 10 element vector each element of which is a character
string of length 1e5:
> set.seed(1001)
> x <- sapply(1:10, function(x)paste0(
On Mon, 14 Nov 2016, Marc Schwartz wrote:
On Nov 14, 2016, at 11:26 AM, Charles C. Berry wrote:
On Mon, 14 Nov 2016, Bert Gunter wrote:
[stuff deleted]
Hi,
Both gsub() and strsplit() are using regex based pattern matching
internally. That being said, they are ultimately calling .Intern
> On Nov 14, 2016, at 11:26 AM, Charles C. Berry wrote:
>
> On Mon, 14 Nov 2016, Bert Gunter wrote:
>
>> Yes, but it need some help, since nchar gives the length of the
>> *entire* string; e.g.
>>
>> ## to count "a" 's :
>>
>>> x <-(c("abbababba","bbabbabbaaaba"))
>>> nchar(gsub("[^a]","",x)
On Mon, 14 Nov 2016, Bert Gunter wrote:
Yes, but it need some help, since nchar gives the length of the
*entire* string; e.g.
## to count "a" 's :
x <-(c("abbababba","bbabbabbaaaba"))
nchar(gsub("[^a]","",x))
[1] 4 6
This is one of about 8 zillion ways to do this in base R if you don't
wan
Yes, but it need some help, since nchar gives the length of the
*entire* string; e.g.
## to count "a" 's :
> x <-(c("abbababba","bbabbabbaaaba"))
> nchar(gsub("[^a]","",x))
[1] 4 6
This is one of about 8 zillion ways to do this in base R if you don't
want to use a specialized package.
Just for
?nchar in the base R should also help...
On Mon, Nov 14, 2016 at 2:26 PM, Ismail SEZEN wrote:
>
> > On 14 Nov 2016, at 11:44, Ferri Leberl wrote:
> >
> >
> > Dear All,
> > Is there a function to count the occurences of a certain character in a
> string resp. in a vector of strings?
> > Thank yo
> On 14 Nov 2016, at 11:44, Ferri Leberl wrote:
>
>
> Dear All,
> Is there a function to count the occurences of a certain character in a
> string resp. in a vector of strings?
> Thank you in advance!
> Yours, Ferri
>
library(stringr)
?str_count
_
Dear All,
Is there a function to count the occurences of a certain character in a string
resp. in a vector of strings?
Thank you in advance!
Yours, Ferri
__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/
Hi all,
I understand this is not a data frame but an individual variable from the
data frame which is a list. Since, I need to work on this particular
variable I just added here as a sample data.
Jim, your code solved the purpose.Thanks!
Regards,
Srivathsan
On Wed, Jul 20, 2016 at 4:29 PM, Ulr
What you show cannot be a data.frame. Using what you gave, this should help
you along:
x <- c(11,15,12,25, 11,12, 15,25, 134,45,56, 46, 45,56, 15,12,
66,45,56,24,14,11,25,12,134)
table(x)
On Wed, 20 Jul 2016 at 11:44 Jim Lemon wrote:
> Oops, didn't translate that function correctly:
>
> has_val
Oops, didn't translate that function correctly:
has_values<-function(x,values) {
if(is.list(x)) {
return(sum(unlist(lapply(svlist,
function(x,values) return(all(values %in% x)),values
}
}
Jim
On Wed, Jul 20, 2016 at 7:18 PM, Jim Lemon wrote:
> Hi sri,
> Maybe something like this?
>
>
Hi sri,
Maybe something like this?
has_values<-function(x,values) {
if(is.list(x)) {
return(sum(unlist(lapply(svlist,
function(x,values) return(all(values %in% x)),c(11,12)
}
}
svlist<-list(a=c(11,15,12,25),
b=c(11,12),
c=c(15,25),
d=c(134,45,56),
e=46,
f=c(45,56),
g=c(15,12),
h
It seems very unlikely that what you quote can be a data frame. It could
be a list I suppose. Can you clarify?
On 19/07/2016 11:59, sri vathsan wrote:
Hi,
I have a data frame like below.
11,15,12,25
11,12
15,25
134,45,56
46
45,56
15,12
66,45,56,24,14,11,25,12,134
I want to identify the freque
Hi,
I have a data frame like below.
11,15,12,25
11,12
15,25
134,45,56
46
45,56
15,12
66,45,56,24,14,11,25,12,134
I want to identify the frequency of pairs/triplets or higher that occurs in
the data. Say for example, in above data the occurrence of pairs looks like
below
item No of occurrence
On Sep 9, 2015, at 11:52 AM, Nick Petschek wrote:
> Hi,
>
> I want to run frequency tables for multiple categorical variables, ideally
> one in %, and the other as a count, and am unsure how to proceed. I would
> like my output to be the following:
>
> | favorable | unfavorable | neutral
Hi,
I want to run frequency tables for multiple categorical variables, ideally
one in %, and the other as a count, and am unsure how to proceed. I would
like my output to be the following:
| favorable | unfavorable | neutral
Q1 | 80% | 10%| 10% |
Q2 | 70% |
2015 5:16 PM
> To: Sarah Goslee; agrima seth
> Cc: r-help
> Subject: Re: [R] Frequency count of terms only in a given column in R
>
> Dear Agrima
>
> As well as Sarah's seven possibilities an eighth occurs to me: you have
> not yet read it into R in the first place. If
Dear Agrima
As well as Sarah's seven possibilities an eighth occurs to me: you have
not yet read it into R in the first place. If that is the case you may
be able to use read.table to get it into a data frame with columns
corresponding to your words.
?read.table may be your friend here.
On 2
Hi,
On Fri, Aug 28, 2015 at 7:49 AM, agrima seth wrote:
> i have a text file with data of the given format:
>
> white snow
> lived snow
> in snow
> lived place
> in place
> a place
> called place
> as place
That doesn't specify the format. I can think of at least seven things
that could be:
a ch
i have a text file with data of the given format:
white snow
lived snow
in snow
lived place
in place
a place
called place
as place
here i have to find the frequency of the terms only in the first column
(i.e.)
white - 1
lived- 2
in -2
a-1
called - 1
as -1
Could you please guide me how to do the
Hi,
>From the dscription, looks like you need ?rle()
vec1 <- c(111, 106, 117, 108, 120, 108, 108, 116, 116, 113)
res <- rle(vec1)$lengths
names(res) <- rle(vec1)$values
res[res>1]
#108 116
# 2 2
length(res[res>1])
A.K.
On Thursday, November 21, 2013 10:12 AM, b. alzahrani
wrote:
If you just need a count of how many of each number you can just use
table().
> tmp <- c(111,106,117,108,120,108,108,116,113)
> table(tmp)
tmp
106 108 111 113 116 117 120
1 3 1 1 1 1 1
On Thu, Nov 21, 2013 at 9:10 AM, b. alzahrani wrote:
>
> hi guys
>
> Assume I have this data
Thanks, got it.
**
Bander Alzahrani, r
*
Date: Thu, 21 Nov 2013 09:14:11 -0600
Subject: Re: [R] frequency of numbers
From: deter...@umn.edu
To: cs_2...@hotmail.com
CC: r-help@r-project.org
If
hi guys
Assume I have this dataframe:
v3$number_of_ones
[1] 111 106 117 108 120 108 108 116 116 113
Is there any command in r that gives me the frequency of these numbers (how
many each number is repeated e.g. the number 108 repeated 2 and 111 repeated
one an so on)
I have around 10^6 numb
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
> Behalf
> Of Sridhar Iyer
> Sent: Saturday, June 01, 2013 2:57 PM
> To: r-help@r-project.org
> Subject: [R] Frequency count of Boolean pattern in 4 vectors.
>
> I need to do this on very large data
I need to do this on very large datasets ( > a few million data points). So
seeking help in figuring out an implementation of the task.
Input 4 vectors which contain values as 0 or 1. (as integers, not boolean
bits)
vec_A = ( 0, 1, 0, 0, .. 1, 0, 1, 0) etc
vec_B = (0,0,1,1.)
vec_C, vec_D
Hi Angelo,
you might have a look at this
http://lmdvr.r-forge.r-project.org/figures/figures.html?chapter=06;figure=06_15;theme=stdBW;code=right
Cheers
Am 23.04.2013 12:42, schrieb Angelo Scozzarella Tiscali:
> Hi, friends.
> I'd like to illustrate the relationship between two categorical variable
Hi, friends.
I'd like to illustrate the relationship between two categorical variables with
a block chart (a three-dimensional bar chart) with the height of the blocks
being proportional to the frequencies.
Is there a way to do it with R?
Thanks in advance
Angelo
[[alternative HTML ver
Thanks Rui,
It is very useful indeed.
Bests,
Niklas
2013/2/26 Rui Barradas
> Hello,
>
> I'm not sure I understand, do you want to treat BCC, CBC and CCB as the
> same? If so try
>
> w2 <- apply( y , 1 , function(x) paste0(sort(x) , collapse = "" ))
>
> table(w2)
>
>
> Hope this helps,
>
> Rui Ba
Hello,
I'm not sure I understand, do you want to treat BCC, CBC and CCB as the
same? If so try
w2 <- apply( y , 1 , function(x) paste0(sort(x) , collapse = "" ))
table(w2)
Hope this helps,
Rui Barradas
Em 26-02-2013 13:58, Niklas Fischer escreveu:
Hi again,
Thanks for Anthony about the
Hi again,
Thanks for Anthony about the links on reproducible codes.
Thanks for Rui about ordering when rows are intact.
One more question
Here is your code.
x <-
cbind(
sample( LETTERS[1:6] , 100 , replace = TRUE ) ,
sample( LETTERS[1:6] , 100 , replace = TRUE )
Hello,
I disagree with the way you've sorted the matrix, like this all A's
become first, then B's, etc, irrespective of the respondents. Each row
is a respondent, and the rows should be kept intact, but with a
different ordering. To this effect, use order():
z <- y[order(y[,1], y[,2], y[,3])
in the future, please provide R code to re-create some example data :)
read
http://stackoverflow.com/questions/5963269/how-to-make-a-great-r-reproducible-examplefor
more detail..
# create a data table with three unique columns' values..
# treat these values just like letters
x <-
cbind(
Thanks a lot. Is count command in package COUNT? I'm having a hard fine to fine
this package.
Thanks again:)
Best,Farnoosh Sheikhi
Cc: R help
Sent: Tuesday, October 23, 2012 2:07 PM
Subject: Re: [R] frequency
Hi,
Try this:
dat1<-read.table(t
3
A.K.
From: farnoosh sheikhi
To: arun
Cc: R help
Sent: Tuesday, October 23, 2012 5:29 PM
Subject: Re: [R] frequency
Thanks a lot. Is count command in package COUNT? I'm having a hard fine to fine
this package.
Thanks again:)
Best,Farnoosh S
l=TRUE)
#ID Visit response
#1 x a1 2
#2 x a2 2
#3 x a2 2
#4 x a1 2
#5 x a1 2
#6 y b1 3
#7 y c23 3
#8 y b33 3
A.K.
From: farnoosh sheikhi
To: arun
Sent: Tuesday, October 23,
uot;,all=TRUE)
# ID1 visit response
#1 x a1 2
#2 x a2 2
#3 y b1 3
#4 y c23 3
#5 y b33 3
A.K.
- Original Message -
From: farnoosh sheikhi
To: "r-help@R-project.org"
Cc:
Sent: Tuesday, October 23, 2012 3:14 PM
Subject: [R]
Are the data in a data frame? Is it the first letter of the id that
defines unique ID's or something else?
Depending on your answers:
?substring
?table
?with
may be useful, as in with(yourdata,table(substring(ID,1,1)))
... or not, if you meant something else.
-- Bert
On Tue, Oct 23, 2012 at
Hello,
I have a data as follow:
ID Visit
xa1
xa2
yb1
yc23
yb33
I want to look at frequency of visit for ID and create a new column as response
.
For example my response would be 2 for x and 3 for y.
I think I need to write a loop, but I don't know how.
I really appreciate your help.
Thanks
;,x)))
> res3<-within(as.data.frame(res2),{Freq<-as.numeric(Freq)})
> head(res3)
> # Var1 Freq
> #1 0-51
> #2 5-106
> #3 10-152
> #4 15-202
> #5 20-256
> #6 25-302
>
>
> A.K.
>
>
>
>
>
>
>
>
> - Orig
s.numeric(Freq)})
head(res3)
# Var1 Freq
#1 0-5 1
#2 5-10 6
#3 10-15 2
#4 15-20 2
#5 20-25 6
#6 25-30 2
A.K.
- Original Message -
From: jcrosbie
To: r-help@r-project.org
Cc:
Sent: Tuesday, October 16, 2012 7:37 PM
Subject: [R] frequency table with custom bands
-30 2
A.K.
- Original Message -
From: jim holtman
To: jcrosbie
Cc: r-help@r-project.org
Sent: Tuesday, October 16, 2012 8:52 PM
Subject: Re: [R] frequency table with custom bands
?cut
try this:
> seq1 = seq(0, 95, by = 5)
> seq2 = seq(100, 1000, by = 100)
> Band
?cut
try this:
> seq1 = seq(0, 95, by = 5)
> seq2 = seq(100, 1000, by = 100)
> Bands = c(seq1, seq2)
> Prices = sample(1:1000, 200, replace=F)
> table(cut(Prices, breaks = Bands))
(0,5] (5,10] (10,15] (15,20] (20,25]
(25,30] (30,35] (35,40]
1 2
I would like to create a frequency table with custom bands.
seq1 = seq(0, 100, by = 5)
seq2 = seq(100, 1000, by = 100)
Bands = c(seq1, seq2)
Prices = sample(1:1000, 200, replace=F)
How would I go about find the frequency of prices within each band?
--
View this message in context:
http:/
Or perhaps faster but less general:
rowSums(mydata != 0)
Michael
On Tue, Mar 6, 2012 at 12:56 PM, Sarah Goslee wrote:
> A reproducible example would be helpful, but lacking that
> here's some untested code. If your data frame has NA values,
> those will also need to be dealt with.
>
> apply(myd
A reproducible example would be helpful, but lacking that
here's some untested code. If your data frame has NA values,
those will also need to be dealt with.
apply(mydata, 1, function(x)sum(x != 0))
Sarah
On Tue, Mar 6, 2012 at 12:03 PM, mari681 wrote:
> I feel this is a very easy thing but I'
I feel this is a very easy thing but I've never done it before and it is
getting frustrating.
I have a big data.frame (1445846 rows, 15 col)
that looks like this:
V1 V2 V3 V4 V5
1home sisterbrother chair 0
2cat
After that, you might consult the source code for distance() in ecodist.
That function was specifically written to make it easy for people to
add new dissimilarity/similarity metrics, and I think you'll find it helpful
(even if you just extract the bit you need rather than expand the whole
function
Set,
This is the same post as your "Similarity Matrix" post.
I'm not trying to be a smart ass here, but ... ?Can you fit a square peg in
a round hole?... yes, but it doesn't mean it belongs there.
I suggest you get a piece of paper and a pencil and figure out 1) what you
are trying to do and w
On 12/04/2011 08:21 PM, set wrote:
Hello R-users,
I've got a file with individuals as colums and the clusters where they occur
in as rows. And I wanted a table which tells me how many times each
individual occurs with another. I don't really know how such a table is
called...it is not a frequenc
Hello R-users,
I've got a file with individuals as colums and the clusters where they occur
in as rows. And I wanted a table which tells me how many times each
individual occurs with another. I don't really know how such a table is
called...it is not a frequency tableMy eventual goal is to mak
Hi,
I think you can try the function rep().
Example:
# this means rep 1 once, 2 twice and 3 three times
> rep(c(1,2,3), c(1,2,3))
[1] 1 2 2 3 3 3
# this means rep "A", "B", "C", until it reaches length of 10
> rep(c("A","B","C"), length.out = 10)
[1] "A" "B" "C" "A" "B" "C" "A" "B" "C" "A"
you
I think something like this is what you are looking for, but to be
honest, I don't quite understand what you are looking for: can you
actually write out the desired result:
tapply(df$x, df$Var, table)
where df is the name of your data.
df <- structure(list(Var = c(201L, 201L, 201L, 201L, 202L, 2
Hello everybody
I am new on R
I have some problem when i try to obtain frequency table
which script do I need to write in R in order to obtain the frecuency of a
value per repetition
You could see my example
Var. rep x I need to obtain these
2011
Hi,
This was a terrific suggestion. I'm no expert in R, but I managed to find and
read the axis command to do the following.
x=c(rep(2,14),rep(4,13),rep(6,11),rep(8,4),rep(10,3),rep(12,2),14,16,18)
stripchart(x,method="stack",pch=21,at=0,bg="lightblue",col="blue",offset=.5,cex=1.5,xlab="Bag
B"
Hi,
either upscale the circles (increase cex) or narrow your plot, as in
x11(3,5)
stripchart(x,method="stack",pch=21,at=0,bg="lightblue",col="blue",offset=.5,cex=1.5,xlab="Bag
B",frame.plot=FALSE,axes=FALSE)
there's a trade off between 'closing the gap' and having all your ticks
readable, so just
Hi David,
you can use base 'stripchart'
stripchart(rbinom(100,size=10,p=.3),method="stack",pch=21,at=0,bg="lightblue",col="blue",offset=.5,cex=1.5,xlim=c(0,10))
and set 'pch' as you wish, e.g. as in
example(points)
hth.
Am 08.02.2011 08:27, schrieb David Arnold:
> Hi,
>
> We were wondering ho
David Arnold wrote:
> We were wondering how we could make a stacked frequency diagram such as
> this one:
>
> http://msemac.redwoods.edu/~darnold/math15/liz.pdf
See the ‘dots’ function in the ‘TeachingDemos’ package or the ‘dotPlot’ (not
to be confused with ‘dotplot’) function in the ‘BHH2’ pac
Hi,
We were wondering how we could make a stacked frequency diagram such as this
one:
http://msemac.redwoods.edu/~darnold/math15/liz.pdf
We don't necessarily need the shaded "balls", other characters would be fine,
such as stacks of x's.
David
__
R-
Hi Liliana,
Try
> table(factor(x, levels = 0:10))
0 1 2 3 4 5 6 7 8 9 10
0 2 0 6 0 2 2 1 0 1 6
Also, see ?factor.
HTH,
Jorge
On Tue, Nov 23, 2010 at 10:29 PM, Liliana Pacheco <> wrote:
> Hi R users
> I want to make a table of frequencies to show how many times the numbe
Hi R users
I want to make a table of frequencies to show how many times the numbers
form 0 to 10 appear in a vector.
For example, if the vector is:
> x
[1] 5 10 3 5 10 10 3 6 10 1 10 3 7 1 10 3 6 9 3 3
In this case I want a table that will show that the zero has frequency 0,
the o
Thanks Dimitris,
It works nicely!
Regards,
Olga
On Thu, 2010-08-26 at 11:55 +0200, Dimitris Rizopoulos wrote:
> one way is the following:
>
> mylist <- list(x1 = c("A","A","A","B","C","Z","Y"),
> x2 = c("D","D","E","E","F","Z","X"),
> x3 = c("A","A","A","B","Y","Z"))
> newlist <- c("
one way is the following:
mylist <- list(x1 = c("A","A","A","B","C","Z","Y"),
x2 = c("D","D","E","E","F","Z","X"),
x3 = c("A","A","A","B","Y","Z"))
newlist <- c("A","B","C","D","E","F")
tab <- t(sapply(mylist, function (x)
table(factor(x, levels = newlist
tab[tab == 0] <- NA
tab
Dear all,
I have a list that contains 3 sublists( x1, x2, x3)
mylist<-list(x1=c("A","A","A","B","C","Z","Y"),x2=c("D","D","E","E","F","Z","X"),x3=c("A","A","A","B","Y","Z"))
mylist
$x1
[1] "A" "A" "A" "B" "C" "Z" "Y"
$x2
[1] "D" "D" "E" "E" "F" "Z" "X"
$x3
[1] "A" "A" "A" "B" "Y" "Z"
I also ha
Please, reply to the r-help and not only to me personally. That way
others can can also help, or perhaps benefit from the answers.
You can use strplit to remove the last part of the strings. strplit
returns a list of character vectors from which you (if I understand
you correctly) only want to sel
Hi:
Here are a couple of ways to render a basic 2D table. Let's call your input
data frame dat:
> names(dat) <- c('samp', 'sequen')
> ssTab <- as.data.frame(with(dat, table(samp, sequen)))
> ssTab # data frame version
samp sequen Freq
1 111abc1
2 1079abc1
3 5576abc1
4
Your problem is not completely clear to me, but perhaps something like
data <- data.frame(
a = rep(c(1,2), each=10),
b = rep(c('a', 'b', 'c', 'd'), 5))
library(plyr)
daply(data, a ~ b, nrow)
does what you need.
Regards,
Jan
On Wed, Aug 25, 2010 at 4:53 PM, rtsweeney wrote:
>
> Hi all,
>
Hi all,
I have read posts of heat map creation but I am one step prior --
Here is what I am trying to do and wonder if you have any tips?
We are trying to map sequence reads from tumors to viral genomes.
Example input file :
111 abc
111 sdf
111 xyz
1079 abc
1079 xyz
1079 xyz
55
Hi:
There's always prop.table:
I read in your data as a data frame d. Since prop.table() expects a
matrix/array
as input,
> prop.table(as.matrix(d), 2)
V2 V3V4
[1,] NaN 0.53846154 0.3636364
[2,] NaN 0.15384615 0.000
[3,] NaN 0.07692308 0.2727273
[4,] NaN 0.23076923 0.36
, 2010 1:09 PM
To: r-help@r-project.org
Cc: n.via...@libero.it
Subject: Re: [R] frequency
On 06-May-10 17:06:26, n.via...@libero.it wrote:
>
> Dear list,
> Im trying to do the following operation but im not able to do it
> This is my table:
> 1 2 3
> 1 0 7 4
&
For completeness.
On Thu, May 6, 2010 at 8:03 PM, Joris Meys wrote:
> Table <- matrix(ncol=3,nrow=4,c(0,0,0,0,7,2,1,3,4,0,3,4))
>
> # one way
> t(t(Table)/colSums(Table))
>
> # another way
> apply(Table,2,function(x){x/sum(x)})
>
> Take in mind that your solution is wrong. If you divide 0 by 0,
On 06-May-10 17:06:26, n.via...@libero.it wrote:
>
> Dear list,
> Im trying to do the following operation but im not able to do it
> This is my table:
> 1 2 3
> 1 0 7 4
> 2 0 2 0
> 3 0 1 3
> 4 0 3 4
>
> what i would like to do is
>
> divide each row values wit
Dear list,
Im trying to do the following operation but im not able to do it
This is my table:
1 2 3
1 0 7 4
2 0 2 0
3 0 1 3
4 0 3 4
what i would like to do is
divide each row values with the corresponding column' sum,namely:
1 2
Thanks Robin. I used the following line, which got my table looking
correct.
Wind_freq_speed <- t(table(cut(Wind_Dir_vec, 0:36), cut(Wind_Speed_vec,
seq(0, to=60, by=10
Unfortunately, the rosavent function produced a wind rose diagram that
repeats my frequency data 6 times throughout the 360
> but I need to incorporate the speed values and have a table like the
> following:
> 1 2 3 4 5 6 36
> 0-9
> 10-19
> 20-29
> 30-39
> 40-49
> 50+
> The final table will be used in the rosavent function to produce a wind rose
> diagram just like in this exampl
Hello,
I'm trying to make a table like windfreq.dat in the rose diagram example of
the climatol package.
It looks like:
N NNE NE ENEE ESE SE SSES SSW SW WSWW
WNW NW NNW
0-3 59 48 75 90 71 15 10 11 14 20 22
22 24 15
Hi all,
I created the following script to make a frequency count for
multi-dimenstioanl array. There is no problem with the results except
for the NA values which returns 0.
Now, I don't want NA to return 0 but to return as NA. This is because
I'm dealing with gridded data in which the NODAT
Hi,
I have a dataset like this:
Specieslength (cm)
A 12.4
B 45
A 34.6
C 73
C 24.5
D 4.5
..
I'm trying to obtain a barplot with the class length in x (fixed classes, 5
cm) and the number of
On Dec 11, 2009, at 10:48 PM, Kim Jung Hwa wrote:
Thank you David and Ista for your suggestions. I got the latex part.
But, this may be stupid, I got the html code using following
command, how
can I make use of it? Thanks anyways.
On my computer just copying that to a text editor and ope
Thank you David and Ista for your suggestions. I got the latex part.
But, this may be stupid, I got the html code using following command, how
can I make use of it? Thanks anyways.
temp<-xtable(summary(Orange))
print(temp, type="html")
Treeage circumference
1 3:7 M
There are a variety of packages that help format output using either
LaTeX or html. I've grown to prefer the latex() function in the Hmisc
packages, but you might also be interested in xtable (can output
either to LaTeX or html), R2html, or prettyR.
-Ista
On Fri, Dec 11, 2009 at 6:55 PM, Kim Jung
On Dec 11, 2009, at 6:55 PM, Kim Jung Hwa wrote:
library(datasets)
Orange
summary(Orange)
> library(xtable)
> xtable(summary(Orange))
% latex table generated in R 2.10.1 by xtable 1.5-6 package
% Fri Dec 11 21:39:50 2009
\begin{table}[ht]
\begin{center}
\begin{tabular}{rlll}
\hline
& Tree
Hi All,
I'm a SAS user but I'm very much interested in learning R.
I use ODS system in SAS to make nice frequency tables. Is it possible to
export the output of table() [in TABULAR FORM]? So, that I can use those
directly for publications? Thank you.
# R Code:
library(datasets)
Orange
summary(Or
try
sort (table(MAT), decreasing=T)
if MAT is your matrix
I think this is what you want. though if you want to sort by the first
occurrence then it is a different story.
Nikhil
On 2 Nov 2009, at 1:35PM, Val wrote:
V1 v2 v3 v4
569 10
347 10
46 10 18
On Nov 2, 2009, at 2:49 PM, Jorge Ivan Velez wrote:
Hi Ashta,
Yes, it is possible. Here is a suggestion:
# Data set
x <- read.table(textConnection("v1 v2 v3 v4
569 10
347 10
46 10 18"), header = TRUE)
closeAllConnections()
# Table
res <- table(data.matrix(x))
Hi Ashta,
Yes, it is possible. Here is a suggestion:
# Data set
x <- read.table(textConnection("v1 v2 v3 v4
569 10
347 10
46 10 18"), header = TRUE)
closeAllConnections()
# Table
res <- table(data.matrix(x))
f <- sort(res, decreasing = TRUE)
data.frame(value = na
Thank you Jorge and
> res <- table(unlist(x))
> res[order(res, decreasing = TRUE)]
> # 10 4 6 3 5 7 9 18
> # 3 2 2 1 1 1 1 1
This one works fine for me. Is it possible to transpose it?
I tried t(res[order(res, decreasing = TRUE)]), but it did not work!
I want the result like this
: r-help@r-project.org
Subject: [R] Frequency
BAYESIAN INFERENCES FOR MILKING TEMPERAMENT IN CANADIAN HOLSTEINS
Hi All,
I have a data set "x" with several variables. Sample of the data is shown
below
V1 v2 v3 v4
569 10
347 10
46 10 18
I want the freq
Hi Val,
Here is a suggestion:
res <- table(unlist(x))
res[order(res, decreasing = TRUE)]
# 10 4 6 3 5 7 9 18
# 3 2 2 1 1 1 1 1
HTH,
Jorge
On Mon, Nov 2, 2009 at 1:35 PM, Val <> wrote:
> BAYESIAN INFERENCES FOR MILKING TEMPERAMENT IN CANADIAN HOLSTEINS
>
> Hi All,
>
> I have a da
BAYESIAN INFERENCES FOR MILKING TEMPERAMENT IN CANADIAN HOLSTEINS
Hi All,
I have a data set "x" with several variables. Sample of the data is shown
below
V1 v2 v3 v4
569 10
347 10
46 10 18
I want the frequency of each data point sorted by their occ
Julius -
Both mag and i are vectors, but of different lengths.
R interprets the statement mag>=i as "return a vector the
same length as mag and i whose elements compare the
corresponding elements of the two vectors." The error
message is due to the fact that mag and i are of different
lengt
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