Thanks a lot Rui and Jeff
Yes including labels=c() in scale_linetype_manual() was the hint.
Sibylle
-Original Message-
From: Rui Barradas
Sent: Thursday, July 18, 2024 6:50 PM
To: sibylle.stoec...@gmx.ch; r-help@r-project.org
Subject: Re: [R] ggplot two-factor legend
Às 17:43 de 18
Às 17:43 de 18/07/2024, Rui Barradas escreveu:
Às 16:27 de 18/07/2024, SIBYLLE STÖCKLI via R-help escreveu:
Hi
I am using ggplot to visualise y for a two-factorial group (Bio: 0 and
1) x
= 6 years. I was able to adapt the colour of the lines (green and red)
and
the linetype (solid and dashed
Às 16:27 de 18/07/2024, SIBYLLE STÖCKLI via R-help escreveu:
Hi
I am using ggplot to visualise y for a two-factorial group (Bio: 0 and 1) x
= 6 years. I was able to adapt the colour of the lines (green and red) and
the linetype (solid and dashed).
Challenge: my code produces now two legends. One
uld like the additionally differentiate the
two lines (groups) in the linetype.
Sibylle
-Original Message-
From: Jeff Newmiller
Sent: Thursday, July 18, 2024 6:13 PM
To: sibylle.stoec...@gmx.ch; SIBYLLE STÖCKLI via R-help ;
r-help@r-project.org
Subject: Re: [R] ggplot two-factor
If I follow your question, you want redundant aesthetics. Ggplot normally
notices correlated aesthetic mapping variables and merges the legends, so the
most likely answer is that your data are not fully correlated in all rows. I
have also seen this where data are drawn from different dataframes
Hi
I am using ggplot to visualise y for a two-factorial group (Bio: 0 and 1) x
= 6 years. I was able to adapt the colour of the lines (green and red) and
the linetype (solid and dashed).
Challenge: my code produces now two legends. One with the colors for the
group and one with the linetype for th
Kind regards
Sibylle
-----Original Message-
From: R-help On Behalf Of SIBYLLE STÖCKLI via
R-help
Sent: Saturday, December 16, 2023 12:16 PM
To: R-help@r-project.org
Subject: [R] ggplot 3-dimensions
Dear R-user
Does anybody now, if ggplot allows to use two x-axis including two
dimension
e angel of the x-axis. However, I was able to change
the first x-axis (BB...), but not the second one (Voegel). Maybe this
would solve the problem.
- If not, is there another possibility to fix the number of subplots per
line?
Kind regards
Sibylle
-----Original Message-
From: R-help On Beha
Às 10:29 de 24/11/2023, sibylle.stoec...@gmx.ch escreveu:
Dear R-user
Does anybody now, if ggplot allows to use two x-axis including two
dimensions (similar to excel plot (picture 1 in the pdf attachmet). If yes,
how should I adapt my code? The parameters are presented in the input file
(attachm
rd Giguère
> Sent: Friday, November 24, 2023 3:14 PM
> To: sibylle.stoec...@gmx.ch; r-help@r-project.org
> Subject: RE: [R] ggplot adjust two y-axis
>
> You could also use more simply facet_wrap(~ Studien_Flaeche).
> Charles-Édouard
>
> -Message d'origine-
> De : Char
0,2500), labels =
> c(0,500,1000,1500,2000,2500))
>
> -Message d'origine-
> De : sibylle.stoec...@gmx.ch
> Envoyé : 24 novembre 2023 11:27
> À : 'Charles-Édouard Giguère' ; r-help@r-project.org
> Objet : RE: [R] ggplot adjust two y-axis
>
> Dear Charles-Edoua
ère' ; r-help@r-project.org
Objet : RE: [R] ggplot adjust two y-axis
Dear Charles-Edouard
Thanks a lot. Yes indeed barplot sounds excellent.
Unfortunately, the scale of the smaller axis is fixed, even If I am able to
draw to axes. The idea is to expand the scale to the scale to the second
axis
-
From: Charles-Édouard Giguère
Sent: Friday, November 24, 2023 3:57 PM
To: sibylle.stoec...@gmx.ch; r-help@r-project.org
Subject: RE: [R] ggplot adjust two y-axis
Hi,
I don't know the axis mecanism well enough in ggplot but using the original
barplot function you can add an axis on the r
2))
axis(4, at = c(0, 5, 10), labels = c(0,50,100))
-Message d'origine-
De : sibylle.stoec...@gmx.ch
Envoyé : 24 novembre 2023 09:27
À : 'Charles-Édouard Giguère' ; r-help@r-project.org
Objet : RE: [R] ggplot adjust two y-axis
Dear Charles-Edouard
Thanks a lot.
So no
You could also use more simply facet_wrap(~ Studien_Flaeche).
Charles-Édouard
-Message d'origine-
De : Charles-Édouard Giguère
Envoyé : 24 novembre 2023 09:11
À : sibylle.stoec...@gmx.ch; r-help@r-project.org
Objet : RE: [R] ggplot adjust two y-axis
Hi Sibylle,
For that kind of
--
De : R-help De la part de
sibylle.stoec...@gmx.ch
Envoyé : 24 novembre 2023 05:52
À : r-help@r-project.org
Objet : [R] ggplot adjust two y-axis
Dear R-users
Is it possible to adjust two y-axis in a ggplot differently?
- First y axis (0-60)
- Second y axis (0-2500)
### Figure 1
ggplot(Fig1,ae
Dear R-users
Is it possible to adjust two y-axis in a ggplot differently?
- First y axis (0-60)
- Second y axis (0-2500)
### Figure 1
ggplot(Fig1,aes(BFF,Wert,fill=Studien_Flaeche))+
geom_bar(stat="identity",position='dodge')+
scale_y_continuous(name="First Axis", sec.axis=sec_axis(trans=~.*
Hi John,
This should do what you want. I've changed your data.frame name for my own
convenience to "dat1".
###===
dat1 <- data.frame(
Time = c("Age.25","Age.35","Age.45","Age.55"),
Medians = c(128.25,148.75,158.5,168.75)
)
# create segments data.frame
Hi John,
I'm not sure how to do this with ggplot, but:
Time<- c("Age.25","Age.35","Age.45","Age.55")
Medians<-c(128.25,148.75,158.5,168.75)
> is.character(Time)
# [1] TRUE - thus it has no intrinsic numeric value to plot
> is.numeric(Medians)
# [1] TRUE
# coerce Medians to factor and then plot aga
I am trying to plot four points, and join the points with lines. I can plot the
points, but I can't plot the points and the line.
I hope someone can help my with my ggplot code.
# load ggplot2
if(!require(ggplot2)){install.packages("ggplot2")}
library(ggplot2)
# Create data
Time <- c("Age.
data frame?
Best regards
Petr
> -Original Message-
> From: Rui Barradas
> Sent: Monday, May 16, 2022 1:53 PM
> To: PIKAL Petr ; r-help@r-project.org
> Subject: Re: [R] ggplot pointrange from other df and missing legend
>
> Hello,
>
> In the code below the legen
Hallo all
Here are the data from dput
test <- structure(list(Sample = c("A", "A", "A", "A", "A", "A", "B",
"B", "B", "B", "B", "B", "C", "C", "C", "C", "C", "C"), SSAtype = c("one",
"one", "one", "two", "two", "two", "one", "one", "one", "two",
"two", "two", "one", "one", "one", "two", "
Hello,
And with annotate, the warning goes away.
ggplot(jjdata, aes(x=x, y=y))+
geom_point(size=2,shape=1)+
annotate(
"text",
x=3, y=7.5,
label="R^{2} == 0.23",
parse = TRUE
)
Hope this helps,
Rui Barradas
Às 20:04 de 29/01/2022, Rui Barradas escreveu:
Hello,
Here is
Hello,
Here is a way.
ggplot(jjdata, aes(x=x, y=y))+
geom_point(size=2,shape=1)+
geom_text(x=3, y=7.5, label=expression(paste(R^2 == '0.23')))
Hope this helps,
Rui Barradas
Às 19:32 de 29/01/2022, Sorkin, John escreveu:
Can you help me create text that has a superscript 2?
I am trying
Hello List,
I use ggplot to draw a stack bar chart. but I error message. please look it
below:
> ggplot(s8_plot, aes(fill=GTresult, y=cases, x=gc_label) +
+ geom_bar(position="stack", stat="identity"))
Error: Mapping should be created with `aes()` or `aes_()`.
GTresult and gc_label are chara
Thank you Jeff. This solves my problem.
On 2021-08-28 21:54, Jeff Newmiller wrote:
Maybe you will find that coord_cartesian( ylim=c(-30,30) ) works
better since it doesn't filter out data before rendering.
On August 28, 2021 6:45:11 PM PDT, p...@philipsmith.ca wrote:
I am preparing a time serie
Maybe you will find that coord_cartesian( ylim=c(-30,30) ) works better since
it doesn't filter out data before rendering.
On August 28, 2021 6:45:11 PM PDT, p...@philipsmith.ca wrote:
>I am preparing a time series plot using the ggplot function. It includes
>an area plot outlined at its edges w
I am preparing a time series plot using the ggplot function. It includes
an area plot outlined at its edges with a line plot. For some reason the
line plot, drawn with geom_line(), has some broken portions where the
line does not appear, although the filled geom_area() part of the plot
is shown
Avi
-Original Message-
From: R-help mailto:r-help-boun...@r-project.org> > On Behalf Of Kai Yang via R-help
Sent: Thursday, August 26, 2021 11:53 AM
To: R-help Mailing List mailto:r-help@r-project.org> >
Subject: [R] ggplot error of "`data` must be a data frame, or other o
indeed load more packages …
From: John C Frain
Sent: Thursday, August 26, 2021 3:17 PM
To: Kai Yang
Cc: r-help@r-project.org; Avi Gross
Subject: Re: [R] ggplot error of "`data` must be a data frame, or other object
coercible by `fortify()`, not an S3 object with class rxlsx"
ta frame or
> something it can change into a data.frame. What you gave it probably is an
> object meant to represent an EXCEL file or something. You may need to
> extract a data.frame (or tibble or ...) from it before passing that to
> ggplot.
>
> Avi
>
> -Original Message
)
>
> As the message states, it expects that argument to be a data frame or
> something it can change into a data.frame. What you gave it probably is an
> object meant to represent an EXCEL file or something. You may need to
> extract a data.frame (or tibble or ...) from it before passing
it can change into a data.frame. What you gave it probably is an
> object meant to represent an EXCEL file or something. You may need to
> extract a data.frame (or tibble or ...) from it before passing that to
> ggplot.
>
> Avi
>
> -Original Message-
> From: R-help
m it before passing that to ggplot.
Avi
-Original Message-
From: R-help On Behalf Of Kai Yang via R-help
Sent: Thursday, August 26, 2021 11:53 AM
To: R-help Mailing List
Subject: [R] ggplot error of "`data` must be a data frame, or other object
coercible by `fortify()`, not an S3
om: R-help On Behalf Of Kai Yang via R-help
Sent: Thursday, August 26, 2021 11:53 AM
To: R-help Mailing List
Subject: [R] ggplot error of "`data` must be a data frame, or other object
coercible by `fortify()`, not an S3 object with class rxlsx"
Hello List,
I got an error message when I
ust 26, 2021 11:53 AM
To: R-help Mailing List
Subject: [R] ggplot error of "`data` must be a data frame, or other object
coercible by `fortify()`, not an S3 object with class rxlsx"
Hello List,
I got an error message when I submit the code below ggplot(eth, aes(ymax=ymax,
ymin=y
The class of 'eth' must be incorrect. You could try 'as.data.frame' or
possibly 'as.list' to convert 'eth' to an acceptable form.
On Thu, Aug 26, 2021, 11:53 Kai Yang via R-help
wrote:
> Hello List,
> I got an error message when I submit the code below
> ggplot(eth, aes(ymax=ymax, ymin=ymin, xma
eth is not a dataframe but of the class rxlsx. You'll need to convert eth
into a dataframe.
ir. Thierry Onkelinx
Statisticus / Statistician
Vlaamse Overheid / Government of Flanders
INSTITUUT VOOR NATUUR- EN BOSONDERZOEK / RESEARCH INSTITUTE FOR NATURE AND
FOREST
Team Biometrie & Kwaliteitszorg /
Hello List,
I got an error message when I submit the code below
ggplot(eth, aes(ymax=ymax, ymin=ymin, xmax=4, xmin=3, fill=ethnicity)) +
geom_rect() + coord_polar(theta="y") + xlim(c(2, 4) )
Error: `data` must be a data frame, or other object coercible by `fortify()`,
not an S3 object wit
+
geom_rect() +
coord_polar(theta="y") +
xlim(c(2, 4)) +
scale_fill_discrete( labels = eth$label) +
theme(axis.ticks = element_blank(),
axis.text = element_blank())
Only one of the two above is actually needed, and you can experiment.
I can send you personally an attachm
Got it.Thank you.
On Friday, August 13, 2021, 03:03:26 PM PDT, Bert Gunter
wrote:
It's dput() *not* dupt() . ?dput tells you how to use it (as usual).
Bert Gunter
"The trouble with having an open mind is that people keep coming along
and sticking things into it."
-- Opus (aka Berkel
It's dput() *not* dupt() . ?dput tells you how to use it (as usual).
Bert Gunter
"The trouble with having an open mind is that people keep coming along
and sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
On Fri, Aug 13, 2021 at 2:48 PM Kai Yang via
Hello John,
I put my testing data below. I'm not sure how to use dupt() function. would you
please give me an example?
Thanks,
Kai
|
ethnicity |
individuals |
| Caucasian | 36062 |
| Ashkenazi Jewish | 4309 |
| Multiple | 3193 |
| Hispanic | 2113 |
| Asian. not specified | 1538 |
| Chinese | 1
Would you supply some sample data please? A handy way to supply sample
data is to use the dput() function. See ?dput. If you have a very
large data set then something like head(dput(myfile), 100) will likely
supply enough data for us to work with.
On Thu, 12 Aug 2021 at 11:45, Kai Yang via R-help
Hello List,
I use the following code to generate a donut plot.
# Compute percentages
eth$fraction = eth$individuals / sum(eth$individuals)
# Compute the cumulative percentages (top of each rectangle)
eth$ymax = cumsum(eth$fraction)
# Compute the bottom of each rectangle
eth$ymin = c(0, head(eth$yma
Til: r-help@r-project.org; tr...@gvdnet.dk; r-help mailing list
Emne: Re: [R] ggplot complicated ylab
Perhaps [1] has some useful ideas?
[1]
https://stackoverflow.com/questions/13223846/ggplot2-two-line-label-with-exp
ression
On December 16, 2020 5:02:59 AM PST, tr...@gvdnet.dk wrote:
>Dear fr
Perhaps [1] has some useful ideas?
[1]
https://stackoverflow.com/questions/13223846/ggplot2-two-line-label-with-expression
On December 16, 2020 5:02:59 AM PST, tr...@gvdnet.dk wrote:
>Dear friends - I need an ylab on 2 lines -
>
>Here is what I want:
>
>exp <- expression(paste("Cumulative Na-Cl
Dear friends - I need an ylab on 2 lines -
Here is what I want:
exp <- expression(paste("Cumulative Na-Cl balance ","\n",
"and (red) ",Delta,HCO[3]^"-"," mmol"))
So if exp was OK ylab(exp) would work - but the "\n" doesn't seem to do
anything and it all comes on one lin
Hello,
If you want a predetermined number of colors, discretise the data and
use scale_color_manual. In the code below I first compute another vector
z, with a different range, 0 to 2. (In my first mail it was 0 to 1.)
g <- function(x, a = 0, b = 1){
(b - a)*(x - min(x))/(max(x) - min(x)) +
Hi
Maybe scale_colour_manual?
Cheers
Petr
> -Original Message-
> From: R-help On Behalf Of April Ettington
> Sent: Tuesday, August 25, 2020 11:39 AM
> To: Rui Barradas
> Cc: r-help@r-project.org
> Subject: Re: [R] ggplot 3-color gradient scales
>
> Is there a
Is there a way to set it to 3 color categories instead of a gradient? Like
if the color is based on the numbers in a dataframe column, can I make it
so anything >1.2 is red, <0.8 is blue, and anything in the middle is green?
On Mon, Aug 24, 2020 at 6:28 PM April Ettington
wrote:
> Thank you so
Thank you so much!
On Mon, Aug 24, 2020 at 5:33 PM Rui Barradas wrote:
> Hello,
>
> Note that the midpoint argument can make a big difference. In the code
> below try commenting out the line where the default is changed.
>
>
> f <- function(x){
>(x - min(x))/(max(x) - min(x))
> }
>
> librar
Hello,
Note that the midpoint argument can make a big difference. In the code
below try commenting out the line where the default is changed.
f <- function(x){
(x - min(x))/(max(x) - min(x))
}
library(ggplot2)
df1 <- iris[3:5]
names(df1)[1:2] <- c("x", "y")
df1$z <- ave(df1$y, df1$Species
Check out scale_colour_gradient2()
On August 23, 2020 8:12:06 PM PDT, April Ettington
wrote:
>Currently I am using these settings in ggplot to make a gradient from
>red
>to blue.
>
>geom_point( aes(x, y, color=z) ) +
>scale_colour_gradient(low = "red",high = "blue") +
>
>z is a ratio, and curren
Currently I am using these settings in ggplot to make a gradient from red
to blue.
geom_point( aes(x, y, color=z) ) +
scale_colour_gradient(low = "red",high = "blue") +
z is a ratio, and currently I am able to identify which have high and low
values, but I'd really like to be able to distinguish
Hello,
Inline.
Às 17:18 de 08/06/20, Neha gupta escreveu:
I am still waiting for someone to respond.
If someone want to help other, they do not need a special platform for it.
Thank you, yet again for not helping.
1. You have waited 41 minutes.
2. You have not posted data and code.
3. Rea
On Mon, 8 Jun 2020 at 18:25, Neha gupta wrote:
> I am still waiting for someone to respond.
>
>
Please read this guide about asking questions and try again on the correct
mailing-list.
https://www.r-project.org/posting-guide.html
Regards
Martin
[[alternative HTML version deleted]]
I am still waiting for someone to respond.
If someone want to help other, they do not need a special platform for it.
Thank you, yet again for not helping.
Regards
On Mon, Jun 8, 2020 at 5:41 PM Bert Gunter wrote:
> Largely off topic here. RStudio has Help forums on ggplot and other of its
>
Largely off topic here. RStudio has Help forums on ggplot and other of its
R software products. Post there.
Or on stats.stackexchange.com perhaps for questions about how to visualize
statistical data.
See the posting guide linked below for what is ON topic here.
Bert Gunter
"The trouble with havi
I have a model NN, which has 10 piece of data in 10 folds of test (ts) data
such as 0.1, 0.5, 0.3 etc.
And another model SVM, which also have this type of information. I usually
visualize it like:
boxplot (NN, SVM)
I have two questions?
(1) I want to ask how can I visualize them via ggplot?
(2)
f Ivan Calandra
> Sent: Thursday, April 30, 2020 12:28 PM
> To: r-help@r-project.org
> Subject: Re: [R] ggplot get rid of unused/empty facets
>
> Dear Petr,
>
> This is not a ggplot2 solution, but you could just remove the NA rows and
> drop the levels of vzorek:
> met2 <
Dear Petr,
This is not a ggplot2 solution, but you could just remove the NA rows
and drop the levels of vzorek:
met2 <- met[complete.cases(met), ]
met2$vzorek <- droplevels(met2$vzorek)
But I guess you already thought about that...!
Ivan
--
Dr. Ivan Calandra
TraCEr, laboratory for Traceology an
Dear all
I seek some help how to remove unused facets in ggplot
Here is my code
p <- ggplot(met, aes(x=datum, y=lsp))
p+geom_point(size=5)+geom_line()+facet_grid(.~vzorek)
As you can see, there are some empty facets. Is there any reasonably simple
way how to automatically get rid of empty facets
On Thu, Apr 2, 2020 at 6:10 PM PIKAL Petr wrote:
> Dear all
>
> I am not sure, but I believe that in past it was possible to add smoothing
> lines in ggplot even if some group did not have enough points to perform
> calculation (although I did not find any version which could deliver it).
>
> Her
Dear all
I am not sure, but I believe that in past it was possible to add smoothing
lines in ggplot even if some group did not have enough points to perform
calculation (although I did not find any version which could deliver it).
Here is the code and data
library(ggplot2)
p <- ggplot(test, aes(
Great it works. Thank you so much Eric.
Cheers,
Mayooran
-Original Message-
From: Eric Berger
Sent: Monday, 25 November 2019 11:22 PM
To: Thevaraja, Mayooran
Cc: r-help
Subject: Re: [R] ggplot inside of the function
Hi Mayooran,
If you define the following function
f <- functio
Hi Mayooran,
If you define the following function
f <- function(m,v) { sprintf("Norm(mu=%.1f, var=%.1f)",m,v) }
Then you can modify the setting of Prob as follows
Prob <- plyr::rename(Prob_df,
c("p_1"=f(mu1,var1),"p_2"=f(mu2,var2),"p_3"=f(mu3,var3)))
The lesson here is that wherever you set a
Hello Folks
I am working some R package development. When I was using ggplot
inside of the function, I need to get the output graph's legend must be
corresponding to the input parameters numerical value (need to be automatically
changed when we input different parameters). Theref
Hello,
You must use a categorical variable in 'fill'.
Example: (I also set the fill colours to something else.)
ggplot(data = datax, aes(x = x, y = y, fill = factor(fac))) +
geom_bar(stat = "identity", color = "black",
position = position_dodge()) +
theme_minimal() +
scale_fil
Hello to all,
how can I can set both y as character to get the bars beside like
example 1 and use scale_y_continuous
And an additional question: why are the bar colors of x-axes = 8 turned
datax= data.frame("fac"=c(c(rep(1,10),c(rep(2,10,"x"=c(c(1:10,c(1:10))),
"y"=c(89,69,46,57
Thanks for the answer.
Il gio 19 lug 2018, 01:04 Jim Lemon ha scritto:
> Hi Francesca,
> This looks like a fairly simple task. Try this:
>
> fpdf<-read.table(text="PASP SUBJC
> 0 0
> 4 1
> 0 0
> 8 0
> 4 0
> 0 1
> 0 1",
> he
Hi again,
Sorry, forgot this line:
fpdf$PASPpos<-fpdf$PASP > 0
just after reading in the data frame.
Jim
On Thu, Jul 19, 2018 at 9:04 AM, Jim Lemon wrote:
> Hi Francesca,
> This looks like a fairly simple task. Try this:
>
> fpdf<-read.table(text="PASP SUBJC
> 0 0
> 4 1
Hi Francesca,
This looks like a fairly simple task. Try this:
fpdf<-read.table(text="PASP SUBJC
0 0
4 1
0 0
8 0
4 0
0 1
0 1",
header=TRUE)
# get the number of positive PASP results by group
ppos<-by(fpdf$SUBJC,fpdf$PASPpos,su
On Wed, 18 Jul 2018, Francesca wrote:
Dear R help,
I am new to ggplot so I apologize if my question is a bit obvious.
Or perhaps not, as this is the "R-help" mailing list, not the
"Ggplot-help" mailing list. Fortunately for you, what you really need to
learn is R, and then ggplot will be
Hello,
Your request is not entirely clear.
What kind of a graph do you want? A bar graph with a bar of the fraction
of positive levels of PASP per each level of SUBJC?
You need to be more specific.
Also, please post data like this:
# post the output of this command in your next mail
dput(hea
Dear R help,
I am new to ggplot so I apologize if my question is a bit obvious.
I would like to create a plot where a compare the fraction of the values of a
variable called PASP out of the number of subjects, for two groups of subject
codified with a dummy variable called SUBJC.
The variable
On March 12, 2018 11:59 PM, Richard M. Heiberger wrote:
> It looks like your V3 is a factor.
>
> testing_ggplot <- data.frame(
>
> V1=factor(c(256, 256, 256, 272, 272, 272)),
>
> V2=c("Disabled", "Disabled", "Enabled", "Disabled", "Enabled", "Enabled"),
>
> V3=681:686)
>
thanks for the exp
It looks like your V3 is a factor.
testing_ggplot <- data.frame(
V1=factor(c(256, 256, 256, 272, 272, 272)),
V2=c("Disabled", "Disabled", "Enabled", "Disabled", "Enabled", "Enabled"),
V3=681:686)
library(ggplot2)
ggplot(testing_ggplot, aes(V2,V3 )) + geom_boxplot() +
facet_wrap( ~ V
Hi,
I was wondering if someone could give me a hint or two. I'm having problems
generating ggplot2 boxplots . The plot that is has dots but no boxplots. Below
is the dataset
> testing_ggplot
V1V2 V3
1 256 Disabled 688.61
2 256 Disabled 698.63
3 256 Disabled 700.02
4 256
I get the same result as Eric withR version 3.4.2 (2017-09-28)
Platform: x86_64-pc-linux-gnu (64-bit)
Running under: Ubuntu 17.04
It looks like you have "tidyverse" loaded so I tried it with just ggplot2
loaded and with tidyverse loaded.
On Wednesday, November 8, 2017, 4:16:14 AM EST, Eri
Thanks,
I think, I found the problem. It seems to related locale setting.
If I start with 'LANG=C R' everything's good.
--
Zeki Çatav
zekicatav.com
On Nov 8, 2017 1:56 PM, "John Kane" wrote:
I get the same result as Eric with
R version 3.4.2 (2017-09-28)
Platform: x86_64-pc-linux-gnu (64-bit)
I was not able to reproduce this problem. I tried two environments
1. Ubuntu 14.04.5 LTS, R version 3.4.2 (same R version as yours)
2. Windows 10, same R version
On Wed, Nov 8, 2017 at 9:50 AM, Zeki ÇATAV wrote:
> Hello,
> I've an error recently.
>
> ggplot(data = mtcars, aes(x= wt, y= mpg)) +
Hello,
I've an error recently.
ggplot(data = mtcars, aes(x= wt, y= mpg)) + geom_line()
Error: Found object is not a stat.
> sessionInfo()
R version 3.4.2 (2017-09-28)
Platform: x86_64-pc-linux-gnu (64-bit)
Running under: Ubuntu 16.04.3 LTS
Matrix products: default
BLAS: /usr/lib/openblas-base/li
> On Nov 2, 2017, at 10:03 AM, Ed Siefker wrote:
>
> I don't really understand. I mean, I understand the solution is
> print(ggplot(...)). But why is that required in a function and not at
> the console?
The REPL design of the interactive console is offered the user as a
convenience, but I ag
On 02/11/2017 1:03 PM, Ed Siefker wrote:
I don't really understand. I mean, I understand the solution is
print(ggplot(...)). But why is that required in a function and not at
the console?
Shouldn't I be able to rely on what I do at the console working in a
script? Is this inconsistent behavior
FAQ 7.22
Open the file indicated by
system.file("../../doc/FAQ")
and scroll down to 7.22
On Thu, Nov 2, 2017 at 1:03 PM, Ed Siefker wrote:
> I don't really understand. I mean, I understand the solution is
> print(ggplot(...)). But why is that required in a function and not at
> the console?
>
I don't really understand. I mean, I understand the solution is
print(ggplot(...)). But why is that required in a function and not at
the console?
Shouldn't I be able to rely on what I do at the console working in a
script? Is this inconsistent behavior by design?
On Thu, Nov 2, 2017 at 11:54
> On Nov 2, 2017, at 9:27 AM, Ed Siefker wrote:
>
> I have a function:
>
> myplot <- function (X) {
>d <- plotCounts(dds2, gene=X, intgroup="condition", returnData=TRUE)
>png(paste("img/", X, ".png", sep=""))
>ggplot(d, aes(x=condition, y=count, color=condition)) +
>geom_poi
Hi
You have to print it.
just add
print(all ggplot stuff)
inside the function.
Cheers
Petr
> -Original Message-
> From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of Ed Siefker
> Sent: Thursday, November 2, 2017 5:27 PM
> To: r-help
> Subject: [R] ggplot
I have a function:
myplot <- function (X) {
d <- plotCounts(dds2, gene=X, intgroup="condition", returnData=TRUE)
png(paste("img/", X, ".png", sep=""))
ggplot(d, aes(x=condition, y=count, color=condition)) +
geom_point(position=position_jitter(w=0.1,h=0)) +
scale_y_log10
Yes, I did. I should have posted the results here.
"~./5" works, but "~.-3" does not. Multiplication and division should
work; I am wondering how I should present the plus and the minus in this
context.
Thanks,
John
2017-10-17 2:47 GMT-07:00 Eric Berger :
> Hi John,
> Why not just try both and
Hi John,
Why not just try both and see which one makes sense?
On Tue, Oct 17, 2017 at 12:24 PM, John wrote:
> Hi,
>
>I have a question on ggplot2 with the second axis, but I don't think one
> needs to know ggplot2 package in order to answer this question.
>
>In this example,
> https://r
Hi,
I have a question on ggplot2 with the second axis, but I don't think one
needs to know ggplot2 package in order to answer this question.
In this example,
https://rpubs.com/MarkusLoew/226759
since the transformation of the second axis is given by y1=y2*5,
#
p <- p + scale_y_con
>1. get the order of the labels right
You need to order your labels in the Land factor correctly when you create it
with the factor function, which was (not) done here but rather before you used
dput to generate this code.
>2. Why I need to reference "breaks" and "labels" completely?
Read the
Hi All,
I would like to do the following pie chart using ggplot from an official
data source (
http://www.deutscheweine.de/fileadmin/user_upload/Website/Service/Downloads/Statistik_2016-2017-neu.pdf
, Tab 8, Page 14):
-- cut --
cat("# weinimport_piechart.R\n")
# -- Input -
Dear Greg,
Make sure that your x variable (Betas) is categorical. That is required for
geom_boxplot().
And please do read the posting guide.
Best regards,
ir. Thierry Onkelinx
Instituut voor natuur- en bosonderzoek / Research Institute for Nature and
Forest
team Biometrie & Kwaliteitszorg / t
Hi all;
When I run the following program substantially I have "Warning message:
position_dodge requires non-overlapping x intervals"
How I can overcome this problem.
Regards,
Greg
p <- ggplot() + geom_point(data=a, aes(x=Betas, y=Traits, color=
Super.Pathway), shape=15, size=4)
p <- p + guide
> On Mar 20, 2017, at 4:42 AM, Troels Ring wrote:
>
> Dear friends - here is an example of something that I find annoying
>
> library(ggplot2)
> DDF <- data.frame(x=x<-seq(1,10),y=x^2)
> G <- ggplot(data=DDF,aes(x=x,y=y)) + geom_point()
> GG<-G+ylab(expression(paste("Total ",CO[2]," halved")))
Dear friends - here is an example of something that I find annoying
library(ggplot2)
DDF <- data.frame(x=x<-seq(1,10),y=x^2)
G <- ggplot(data=DDF,aes(x=x,y=y)) + geom_point()
GG<-G+ylab(expression(paste("Total ",CO[2]," halved")))
GG
GG+annotate("text",x=5,y=50,label=expression(paste("Total ",CO[
Dear useRs:
I am having difficulty understanding how to make a legend in ggplot when I only
want certain geoms to be indicated, in the presence of nested groups. An
example:
require(tidyverse)
dat <- tibble(X=rep(seq(4),3),
# fake data
Y=c(-1.11, -0.46, 0.02,
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