Hi:
Is this what you're after?
fout - function(x) {
lim - median(x) + c(-2, 2) * mad(x)
x[x lim[1] | x lim[2]]
}
apply(datafr1, 2, fout)
$var1
[1] 17.5462078 18.4548214 0.7083442 1.9207578 -1.2296787 17.4948240
[7] 19.5702558 1.6181150 20.9791652 -1.3542099 1.8215087
Hi Dennis and R-users
Thank you for more help. I am pretty close, but challenge still remain is
forcing the output with different length to output dataframe.
x - data.frame(apply(datafr1, 2, fout))
Error in data.frame(var1 = c(-0.70777998321315, 0.418602152926712,
2.08356737154810, :
I think it was suggested that you save your output to a 'list' and
then you will have it in a format that can accept variable numbers of
items in each element and it is also in a form that you can easily
process it to create whatever other output you might need.
On Fri, Mar 18, 2011 at 7:24 AM,
Thanks, Jim for the idea.
I tried with save as list. I can not write to a table with write.table, I
could not find a function that is write.list or equivalent. Even if it is
list I think it would be difficult to post-processing than as table.
outx- as.list(apply(datafr1, 2, fout))
write.table
On Mar 18, 2011, at 10:53 AM, Ram H. Sharma wrote:
Thanks, Jim for the idea.
I tried with save as list. I can not write to a table with
write.table, I
could not find a function that is write.list or equivalent. Even if
it is
list I think it would be difficult to post-processing than as
The easiest thing is to use 'save' so that you write the object out as
binary. If you don't need 'text', then save/load is the way to
operate with the data.
On Fri, Mar 18, 2011 at 10:53 AM, Ram H. Sharma sharma.ra...@gmail.com wrote:
Thanks, Jim for the idea.
I tried with save as list. I can
I wish has simpler solution, apprently simple problem ! thanks for help.
On Fri, Mar 18, 2011 at 10:04 AM, jim holtman jholt...@gmail.com wrote:
I think it was suggested that you save your output to a 'list' and
then you will have it in a format that can accept variable numbers of
items in
Dear R community members
I have been struggling on this simple question, but never get appropriate
solution. So please help.
# my data, though I have a large number of variables
var1 - rnorm(500, 10,4)
var2 - rnorm(500, 20, 8)
var3 - rnorm(500, 30, 18)
var4 - rnorm(500, 40, 20)
datafr1 -
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