Use a grid search to get the starting values in which case you
will likely be close enough that you won't run into problems
even without derivatives:
attach(fldgd)
grid - expand.grid(Vr = seq(0,.3,.1), Vm = seq(.45, 1, .05),
alpha = seq(1,2,.25), lamda = seq(1,2,.25))
ss - function(p)
I'm crossposting to the ESS-help mailing list which is slightly
more appropriate here. [This may be a rare case where
crossposting seems to make much sense.]
PD == Peter Dalgaard [EMAIL PROTECTED]
on 25 Sep 2005 19:40:45 +0200 writes:
PD Seth Falcon [EMAIL PROTECTED] writes:
On
This works if you omit the deriv() step.
Use R's options(error=dump.frames) and debugger(). This gives
Browse[1] rhs
[1] 0.433 0.4272571 0.3994105 0.3594037 0.3270730 0.3104752 0.3000927
[8] 0.2928445 0.2874249 0.2831787
attr(,gradient)
VrVm alphalamda
Hi Duncan,
thanks again for your comments.
I dug around in the libxml code and the Web to verify that
validation is indeed only possible in libxml when one uses
DOM (i.e. xmlTreeParse()).
Using DOM is not an option for me, so I need to validate the xml parts
I'm interested in within my
Hi,
I was wondering if it is possible to get the
rowindices without using the function which because
I don't have a restriction criteria. Here's an example
of what I mean:
# take 10 randomly selected instances
iris[sample(1:nrow(iris), 10),]
# output
Sepal.Length Sepal.Width Petal.Length
try this:
dat - iris[sample(1:nrow(iris), 10), ]
dat
match(rownames(dat), rownames(iris))
I hope it helps.
Best,
Dimitris
Dimitris Rizopoulos
Ph.D. Student
Biostatistical Centre
School of Public Health
Catholic University of Leuven
Address: Kapucijnenvoer 35, Leuven, Belgium
Tel:
Tnx very much Dimitris,
your code does what I need. I've just adapted it to my needs (e.g., I
don't deal with scalar functions), and so solved my problem.
Given this, is there a way to use the deriv function in the base
package, within this context (variable length vector of indipendent
.
I am looking for a histogram or box plot with the adding normal
distribution curve
I think that must be possible, but I am not able to find out how to do.
Regards Knut
__
R-help@stat.math.ethz.ch mailing list
gRoovers,
Can the size of figures be controlled from within a noweb document
without resorting to editing the \includegraphics sections in the .tex
file?
Can the figure widths be set in the environmental declarations at the
start?
Can they be set within the \begin{figure} environment?
JC
Hi
answered hundered times.
Dear R people:
I would like to superimpose a normal curve on a histogram.
x-rnorm(150)
h-hist(x,breaks=15)
xhist-c(min(h$breaks),h$breaks)
yhist-c(0,h$density,0)
xfit-seq(min(x),max(x),length=40)
yfit-dnorm(xfit,mean=mean(x),sd=sd(x))
Le 25.09.2005 14:34, Knut Krueger a écrit :
.
I am looking for a histogram or box plot with the adding normal
distribution curve
I think that must be possible, but I am not able to find out how to do.
Regards Knut
Hi Knut,
There are a lot of ways to do that, let x be your data (assume
On 9/25/05, Horacio Montenegro [EMAIL PROTECTED] wrote:
Hi Spencer and Robert,
I have found the same behaviour, but only for lme4
and Matrix after the 0.96 release. lme4 0.95-10 and
Matrix 0.95-13 releases gave sensible results. This
could be an introduced bug, or a solved bug - you
On Mon, 26 Sep 2005, Toni Viúdez wrote:
Hi everybody:
Could anybody help how I solve the next problem?.
I'm doing interpolation maps of tropospheric ozone of my region, and after
create it using IDW, and kriging methods, I want from shapefiles (*.shx,
*.shp, *.dbf, *.sbx *.sbn ) create
Dear R-users,
I have the following data
x - runif(300,min=1,max=230)
y - x*0.005 + 0.2
y - y+rnorm(100,mean=0,sd=0.1)
y - y%%1 # --- modulo operation
plot(x,y)
and would like to recapture the slope (0.005) and intercept(0.2). I wonder if
there are any clever algorithms to do this. I was
Dear All,
I write to ask for information regarding the error message:
Error: symbol print-name too long.
I am afraid that I can't include any code to help with any further diagnosis
of the problem as the code is far too long to be of any use, and I have not
been able to re-create the problem
Dimitris,
I'm new to R programming, and I'm trying to learn the proper way to do
certain things. E.g., I had a piece of code with explicit iteration to
apply some computations to a vector. It was pretty slow. I found a way
to utilize R's built-in vectorization and it was sped up considerably.
Hi,
my name is Giacomo.
I would like to know how to create a Trend variable in a regression using R.
Thank you for your help.
My best regards,
Giacomo
-
[[alternative HTML version deleted]]
Dear all,
I wonder if I can put together a histogram where one bin contains all the
values that are larger than a certain specified value.
Example:
I have values ranging from 0 to 40 and I want 10 bins from 0 to 10, i.e. for
the intervals [0,1), [1,2) , ..., [9,10). And then I want one last bin
-BEGIN PGP SIGNED MESSAGE-
Hash: SHA1
When you uncomment the two lines, your document
becomes two nodes
spectrum
...
spectrum
spectrum
...
/spectrum
XML requires that there be a single top-level node.
And so the parser throws an error saying
Extra content at the end of the
Randall,
thanks for your comments; however, you have to take into account what
is the purpose of the function here! The goal is to approximate
*partial* derivatives numerically, using in fact the definition of the
partial derivatives. If you recall this definition I hope that you can
see why
Florian Defregger wrote:
Dear all,
I wonder if I can put together a histogram where one bin contains all the
values that are larger than a certain specified value.
Example:
I have values ranging from 0 to 40 and I want 10 bins from 0 to 10, i.e. for
the intervals [0,1), [1,2) , ...,
I am exploring the use of loess for oceanographic applications and would
like to plot the locations (longitude and latitude) points where the models
(salinity~temperature*longitude*latitude,parametric=temperature) are
fitted. Chambers and Hastie(1993) explains the locations are nodes of a
k-d
Dimitris,
On Monday 26 September 2005 07:16, Dimitris Rizopoulos wrote:
Randall,
thanks for your comments; however, you have to take into account what
is the purpose of the function here! The goal is to approximate
*partial* derivatives numerically, ...
I hope it is more clear now.
Yes.
-BEGIN PGP SIGNED MESSAGE-
Hash: SHA1
You aren't giving us much to go on, so I can only
make a very wild guess. Check that your file
doesn't have a stray ` character in it.
R will start reading from that point on and try
to make this an internal symbol. If it doesn't
find the closing
Le 26.09.2005 16:15, Sundar Dorai-Raj a écrit :
Florian Defregger wrote:
Dear all,
I wonder if I can put together a histogram where one bin contains all the
values that are larger than a certain specified value.
Example:
I have values ranging from 0 to 40 and I want 10 bins from 0 to 10,
Dear R-users,
Is anyone aware of any function/package for generating a random vector from
a joint distribution defined by an independent graph? Or I have to work it
out myself?
Thanks.
Jinfang
--
Jinfang Wang, Associate Professor
Chiba University, Japan
First a warning: loess in R is only loosely related to loess in S, being
derived from a C implementation (by the same authors).
In R I don't think you can do this. Those details are never exposed, and
are hidden in an undocumented C/Fortran workspace.
On Mon, 26 Sep 2005, Carlisle Thacker
The Statistical Computing and Statistical Graphics Sections of the ASA
are co-sponsoring a student paper competition on the topics of
Statistical Computing and Statistical Graphics. Students are
encouraged to submit a paper in one of these areas, which might be
original methodological research,
Petr Pikal schrieb:
Hi
answered hundered times.
Dear R people:
I would like to superimpose a normal curve on a histogram.
x-rnorm(150)
h-hist(x,breaks=15)
xhist-c(min(h$breaks),h$breaks)
yhist-c(0,h$density,0)
xfit-seq(min(x),max(x),length=40)
Hello,
In the Unix environment, I open a window by x11(). May I specify the
position of this window by specifying the position of the top left of
the window as in Windows environment? Or some other parameters can be
used to do that?
Thank you,
Shengzhe
On 26-Sep-05 nwew wrote:
Dear R-users,
I have the following data
x - runif(300,min=1,max=230)
y - x*0.005 + 0.2
y - y+rnorm(100,mean=0,sd=0.1)
y - y%%1 # --- modulo operation
plot(x,y)
and would like to recapture the slope (0.005) and intercept(0.2).
I wonder if there are any
Knut Krueger [EMAIL PROTECTED] writes:
Petr Pikal schrieb:
Hi
answered hundered times.
Dear R people:
I would like to superimpose a normal curve on a histogram.
x-rnorm(150)
h-hist(x,breaks=15)
xhist-c(min(h$breaks),h$breaks)
yhist-c(0,h$density,0)
Le 25.09.2005 17:30, Knut Krueger a écrit :
Petr Pikal schrieb:
Hi
answered hundered times.
Dear R people:
I would like to superimpose a normal curve on a histogram.
x-rnorm(150)
h-hist(x,breaks=15)
xhist-c(min(h$breaks),h$breaks)
yhist-c(0,h$density,0)
Hi,
I do not know the intercept and slope.
And you have to know them in order to do something like:
ix-(y 0.9*(x-50)/200
I am right?
cheers
(Ted Harding) wrote:
On 26-Sep-05 nwew wrote:
Dear R-users,
I have the following data
x - runif(300,min=1,max=230)
y - x*0.005 + 0.2
y -
On Mon, 2005-09-26 at 17:45 +0200, Shengzhe Wu wrote:
Hello,
In the Unix environment, I open a window by x11(). May I specify the
position of this window by specifying the position of the top left of
the window as in Windows environment? Or some other parameters can be
used to do that?
Hi,
I am fairly new to GAM and started using package mgcv. I like the
fact that optimal smoothing is automatically used (i.e. df are not
determined a priori but calculated by the gam procedure).
But the mgcv manual warns that p-level for the smooth can be
underestimated when df are
Dear R community,
I am looking for an R package or other software to study hidden
Markov models. I need to be able to incorporate multivariate
emissions and covariates for the transition probabilities. The msm
package seems almost perfect for my purpose, but I do not think it
allows
On Mon, 26 Sep 2005, Denis Chabot wrote:
But the mgcv manual warns that p-level for the smooth can be
underestimated when df are estimated by the model. Most of the time
my p-levels are so small that even doubling them would not result in
a value close to the P=0.05 threshold, but I have one
I am attempting to read in a SAS 9.1 data file. After starting R I
change to the directory containing the sas data file and use the dir
command to confirm that it is there. Then I run the following R-code:
library(foreign)
sashome - /Program Files/SAS/SAS 9.1
test-read.ssd(file.path(sashome),
Marc Schwartz (via MN) wrote:
I don't believe so. In general, under Unix/Linux, the Window Manager
determines window positioning upon startup unless the application
overrides this behavior. Some applications let you specify application
window positioning via command line 'geometry'
On Mon, Sep 26, 2005 at 09:27:56AM +0200, Martin Maechler wrote:
I'm crossposting to the ESS-help mailing list which is slightly
more appropriate here. [This may be a rare case where
crossposting seems to make much sense.]
PD == Peter Dalgaard [EMAIL PROTECTED]
on 25 Sep 2005
Hello all,
1. Does Matrix 0.98-7 fix any of this?
2. Assuming no, how does one acquire Matrix 0.95-13?
Cheers, and thank you kindly in advance,
Hank
On Sep 26, 2005, at 9:05 AM, Douglas Bates wrote:
On 9/25/05, Horacio Montenegro [EMAIL PROTECTED] wrote:
Hi Spencer and Robert,
I
Romain Francois schrieb:
Do you want that :
h-hist(x,breaks=10,freq = TRUE)
xfit-seq(min(x),max(x),length=40)
yfit-dnorm(xfit,mean=mean(x),sd=sd(x))
lines(xfit,yfit * 150 * (h$breaks[2]-h$breaks[1]))
Right thats what I want ... but does it make sense to fit the line with
a try and
On 26-Sep-05 Witold Eryk Wolski wrote:
Hi,
I do not know the intercept and slope.
And you have to know them in order to do something like:
ix-(y 0.9*(x-50)/200
I am right?
cheers
Although I really knew them from the way you generated the data,
I pretended I did not know them.
Read
On Mon, 26 Sep 2005, Martin Henry H. Stevens wrote:
Hello all,
1. Does Matrix 0.98-7 fix any of this?
2. Assuming no, how does one acquire Matrix 0.95-13?
It is in the Archive on CRAN, e.g.
http://cran.r-project.org/src/contrib/Archive/M/Matrix_0.95-13.tar.gz
Cheers, and thank you kindly
Ted,
I agree with you that if you unwrap the data you can use lm.
And you can separate the data in the way you describe. However, if you
have thousands of such datasets I do not want to do it by looking at
the graph.
Yes the scatter may be larger as in the example and range(y) may be
larger
On Mon, 26 Sep 2005, Dean Sonneborn wrote:
I am attempting to read in a SAS 9.1 data file. After starting R I
change to the directory containing the sas data file and use the dir
command to confirm that it is there. Then I run the following R-code:
library(foreign)
sashome - /Program
On 26-Sep-05 Witold Eryk Wolski wrote:
Ted,
I agree with you that if you unwrap the data you can use lm.
And you can separate the data in the way you describe. However, if you
have thousands of such datasets I do not want to do it by looking at
the graph.
Yes the scatter may be larger
Emilio,
The depmix package on cran has multivariate distributions and the
possibility of (linear) covariates on the parameters.
If you have questions about its use feel free to contact me,
best, ingmar visser
On 9/26/05 6:29 PM, Dr. Emilio A. Laca [EMAIL PROTECTED] wrote:
Dear R community,
x=runif(100,0,40)
hist(x, breaks=c(0,1,2,3,4,5,6,7,8,9,10,40))
Is this what you had in mind?
Francisco
From: Florian Defregger [EMAIL PROTECTED]
To: r-help@stat.math.ethz.ch
Subject: [R] histogram - one bin for all values larger than a certain value
Date: Mon, 26 Sep 2005 15:36:21 +0200
Dear
Hi,
R-2.1.1
OS: OpenBSD-current (3.8) on i386
Compiler:gcc version 3.3.5 (propolice)
Thread model: single
configure \
--with-readline \
--with-tcltk \
--with-tcl-config=/usr/local/lib/tcl8.4/tclConfig.sh \
--with-tk-config=/usr/local/lib/tk8.4/tkConfig.sh \
--with-libpng \
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R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
Duncan On 9/9/2005 7:41 PM, Paul MacManus wrote:
I need to run qbeta on a set of 500K different parameter
pairs (with a fixed quantile). For most pairs qbeta finds
the solution very quickly but for a substantial minority
of the cases qbeta is very slow. This occurs
Hi, there.
I have two questions about using R to create boxplots.
1. The function boxplot() plots the outliers. How can I label the exact
values arount these outlier points? Does R have an option allow me to
do that?
2. How can I put two boxplots in one x-y axis?
Thanks.
Yulei
Why is R recognizing dates like this?
Chris Buddenhagen, Botany Department, Charles Darwin Research Station, Santa
Cruz,Galapagos. Mail: Charles Darwin Foundation, Casilla 17-01-3891 Avenida
6 de Diciembre N36-109 y Pasaje California Quito, ECUADOR
Duncan,
Thank you for your help. I am pleased to say your 'very wild guess' was
exactly correct. Can't believe I missed it!
Carl
- Original Message -
From: Duncan Temple Lang [EMAIL PROTECTED]
To: Carl Anderson [EMAIL PROTECTED]
Cc: r-help@stat.math.ethz.ch; [EMAIL PROTECTED]
Sent:
Chris Buddenhagen wrote:
Why is R recognizing dates like this?
Recognizing and showing are different things. Which are you complaining
about? What are you doing to cause these to be recognized/shown?
Duncan Murdoch
__
R-help@stat.math.ethz.ch
Dear Yulei,
On Sep 26, 2005, at 6:56 PM, Yulei He wrote:
Hi, there.
I have two questions about using R to create boxplots.
1. The function boxplot() plots the outliers. How can I label the exact
values arount these outlier points? Does R have an option allow me to
do that?
You can use
On Mon, 2005-09-26 at 20:34 +0800, John Charles Considine wrote:
gRoovers,
Can the size of figures be controlled from within a noweb document
without resorting to editing the \includegraphics sections in the .tex
file?
yes,
Sweave sets graphics widths to 0.8\textwidth by default. To
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