Hello,
I have two classifications. How can I compare the overall-accuracy of these
classifications to each other?
Is there a possibility within R to test if the achieved overall-accuracy
for the classifications are differing significantly?
Additionaly, are the McNemar-Test and Broker-Test
Cashorali, Tanya wrote:
Hi,
I'm trying to do a surface plot using the wireframe function.
Everything is working beautifully except that I want to be able to
re-scale it a LOT so that I can fit ~145 labels on the x-axis or y-axis.
I've tried using zoom, scales, aspect, .. nothing seems to
Anyone who responds to Berton, please, CC me: I am also interested.
Best,
Philippe Grosjean
Berton Gunter wrote:
Folks:
A question for R users on Macs. AFAIK, R's Tcl/TK tools allow one to build
GUI interfaces to R's functionality across all platforms. My question: How
well do the TK
Hello everybody,
I need to read a file with a header (EDF files, recorded
electroencephalogram signals) that has fixed byte positions for each
field of its header.
These fields have no separator between them, for example:
8 ascii name of the patient10ascii start time of the recording4
ascii
See ?read.fwf, and also the `R Data Import/Export Manual' that ships with
every copy of R.
Also, you can do in R in the way you describe for Octave with connections
and readChar (again, see the manual).
On Tue, 14 Mar 2006, Gael de Lannoy wrote:
Hello everybody,
I need to read a file with
On Tue, 14 Mar 2006, Prof Brian Ripley wrote:
So this is most likely a bug in package nlme. However, we need a
reproducible example to be able to do anything about it, and without even
the traceback() we cannot be sure that it is in nlme.
Please follow the bug-reporting procedure.
It does
Uwe Ligges wrote:
Arnau Mir Torres wrote:
Hello.
I am an nxn data frame in the variable frame.
I want to make a contour plot with it. That is, I want to plot a square
of dimensions [1,n]x[1,n] with the gray level of square [i,i+1]x[j,j+1]
equal to frame[i,j].
How can I make it?
Hello!
I'm trying to forecast the UK exchange rate. To estimate my model I use
ar() function. However, I can't get a forecast of the exchange rate
using the function forecast().
Regards,
Julija Kackina
[[alternative HTML version deleted]]
Spencer == Spencer Graves [EMAIL PROTECTED]
on Mon, 13 Mar 2006 15:37:16 -0800 writes:
Spencer Hi, Paul, Tolga, Ravi, et al.: What about using
Spencer splines to compute both derivatives and integrals?
That seems good and pretty obvious to me, and for that reason there
have been
Arnau Mir Torres wrote:
Uwe Ligges wrote:
Arnau Mir Torres wrote:
Hello.
I am an nxn data frame in the variable frame.
I want to make a contour plot with it. That is, I want to plot a square
of dimensions [1,n]x[1,n] with the gray level of square [i,i+1]x[j,j+1]
equal to
PhGr == Philippe Grosjean [EMAIL PROTECTED]
on Tue, 14 Mar 2006 09:30:26 +0100 writes:
PhGr Anyone who responds to Berton, please, CC me: I am
PhGr also interested. Best,
(but then you do read R-help, and I disagree with Berton that
this should be answered in private only)
Hello all,
I'm trying to calculate the Maximum likelihood of individuals to get the
ancestry.
I mixd 3 populations 15 generations in proportion of 20% 20% 60% when each
population
sorce have diferent genome (0 1 and 2) with frequencies for each one.
So now i have individuals looks like 0 0 2 1 1
Hello.
In the file list.txt, I have the name of n files in data frame format. I
want to make an image for each file and save the images in pdf format.
To do this, I do the following:
llista = scan(file=list.txt,what=list(nom=))
for (file.name in llista[[1]]){
mgcv::pcls will do this, but there are other packages for quadratic
programming as well. Simon
On Tue, 7 Mar 2006, Domenico Vistocco wrote:
Is there a function in R for constrained linear least squares?
I used the matlab function LSQLIN: my aim is to obtain
non-negative regression
Arnau Mir Torres wrote:
Uwe Ligges wrote:
Arnau Mir Torres wrote:
Hello.
I am an nxn data frame in the variable frame.
I want to make a contour plot with it. That is, I want to plot a
square of dimensions [1,n]x[1,n] with the gray level of square
[i,i+1]x[j,j+1] equal to
On Tue, Mar 14, 2006 at 12:55:47PM +0100, Arnau Mir Torres wrote:
All the outputs names are file.name.pdf but I want to put a different
name for each graphic.
you can use paste() to put together the command:
file =foo
system( paste(mv Rplots.pdf , file, .name.pdf, sep='') )
cu
On 3/14/2006 6:55 AM, Arnau Mir Torres wrote:
Hello.
In the file list.txt, I have the name of n files in data frame format. I
want to make an image for each file and save the images in pdf format.
To do this, I do the following:
llista = scan(file=list.txt,what=list(nom=))
for
On Tue, Mar 14, 2006 at 01:03:22PM +0100, Philipp Pagel wrote:
On Tue, Mar 14, 2006 at 12:55:47PM +0100, Arnau Mir Torres wrote:
All the outputs names are file.name.pdf but I want to put a different
name for each graphic.
you can use paste() to put together the command:
file =foo
Hi,
I'am trying to generate a PS Graphic under Windows with a fixed location via
postscript(file=C:\\test.ps)
But I always become the error:
unable to start device PostScript
can not open 'postscript' file argument 'c:\test.ps'
There must be a very simple thing, that I make wrong.
Thanks in
Sigbert Klinke wrote:
Hi,
I'am trying to generate a PS Graphic under Windows with a fixed location via
postscript(file=C:\\test.ps)
But I always become the error:
unable to start device PostScript
can not open 'postscript' file argument 'c:\test.ps'
There must be a very simple
Sigbert Klinke [EMAIL PROTECTED] writes:
Hi,
I'am trying to generate a PS Graphic under Windows with a fixed location via
postscript(file=C:\\test.ps)
But I always become the error:
unable to start device PostScript
can not open 'postscript' file argument 'c:\test.ps'
There must
Sigbert Klinke wrote:
Hi,
I'am trying to generate a PS Graphic under Windows with a fixed location via
postscript(file=C:\\test.ps)
But I always become the error:
unable to start device PostScript
can not open 'postscript' file argument 'c:\test.ps'
There must be a very simple
Hi everybody,
I'm currently working with time series: do you know if
there's something like stl(package stats, seasonal
decomposition of time series by loess) working also
with objects of class irts?
Thanks
Alessandro
__
R-help@stat.math.ethz.ch
Thanks, Gabor Thomas.
Apologies, but I used an example that obfuscated the question that I wanted to
ask.
I really wanted to know how to have extra arguments in functions that would
allow, per the example code, for something like a counter to be incremented.
Thomas's suggestion of using
There are two ways to do that: one is to use mapply as Thomas
showed and the other is to iterate over an index rather than over
the data itself. Here is a rather lame example using + but hopefully
it conveys the idea of the two possibilities:
# 1
x - y - 1:4
mapply(+, x, y)
# 2
sapply(seq(along
One solution is to convert an irregular time series into a regular one,
interpolating missing values. Obviously, it is only acceptable if the
number of missing items is low. See ?regul in pastecs, for instance.
Best,
Philippe Grosjean
alessandro carletti wrote:
Hi everybody,
I'm currently
Version 0.2 of the package LDheatmap is now on CRAN. The main function
LDheatmap produces a graphical display, as a heat map, of measures of
pairwise linkage disequilibria between SNPs. Users may optionally
include the physical locations or genetic map distances of each SNP on
the plot.
The
The 2nd Edition of my book (with Jiahui Wang) Modeling Financial Time Series
with S-PLUS has recently been published by Springer-Verlag. The 2nd Edition
is updated to cover S-PLUS 7 and S+FinMetrics 2.0. I have also created a
website for the 2nd Edition, which can be found at
Dear expeRts,
I am trying to wrap up a package utilities (for my internal use). After
adding a function datNAtreat that uses mapply, R CMD check gives WARNINGs
for S3 generic/method consistency, checking replacement functions
and checking foreign function calls, all of which are accompanied by
Sorry, just pressing the send button brought the solution :-)
The problem has nothing to do with any programming issues, but rather with
confusion about directories to use R CMD from.
Regards, Ulrike
-- Forwarded Message ---
From: Ulrike Grömping [EMAIL PROTECTED]
To:
Hi,
I am trying to use optim to solve a heavy calibration problem. I supply
the parameters in vector form. But before entering my target
The call is simply:
optim(par = parameters, fn = SumLSQ, method = Nelder-Mead)
the function SumLSQ is simply:
SumLSQ-function(parameters,
Peter Dalgaard wrote:
Do you have write permissions there?
(Possibly a silly question, but must be asked...)
No. Thanks a lot Sigbert
__
R-help@stat.math.ethz.ch mailing list
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PLEASE do read the
Pascal A. Niklaus wrote:
Hi all,
When trying to amend a graphic with a text, I run into the following problem:
text(10,10,First line\nSecond line,pos=2)
works. However, because I have a plotmath expression, I tried:
text(10,10,expression(First line with[subscript]*\nsecond
Zebouni, Stephane (Exchange) wrote:
Hi,
I am trying to use optim to solve a heavy calibration problem. I supply
the parameters in vector form. But before entering my target
The call is simply:
optim(par = parameters, fn = SumLSQ, method = Nelder-Mead)
the
Hi,
On Mar 14, 2006, at 3:05 AM, Martin Maechler wrote:
I think for Berton's question, the only necessary step is
JFox 1) Install X11.app from Apple Install disks (this is a
JFox must if you want to use any tcltk-based package with R.app).
The initial step is to make sure that the tcl/tk
Hi,
I was just trying to figure out how to beautify the output of my
bwplot-output. Altogether I figured most of the things out on my own. The
one thing which puzzles me though are the symbols for the outliers.
I can easily change the form of the median symbol by using pch but I
don't know how
On Tue, 14 Mar 2006, John McHenry wrote:
Thanks, Gabor Thomas.
Apologies, but I used an example that obfuscated the question that I
wanted to ask.
I really wanted to know how to have extra arguments in functions that
would allow, per the example code, for something like a counter to be
Hi,
I was just trying to figure out how to beautify the output of my
bwplot-output. Altogether I figured most of the things out on my own. The
one thing which puzzles me though are the symbols for the outliers.
I can easily change the form of the median symbol by using pch but I
don't know how
From: Thomas Lumley
On Tue, 14 Mar 2006, John McHenry wrote:
Thanks, Gabor Thomas.
Apologies, but I used an example that obfuscated the question that I
wanted to ask.
I really wanted to know how to have extra arguments in
functions that
would allow, per the example code, for
Here is what I get using str(parameters):
num [1:120] 0.2000 -0.0166 0.0934 -0.0300 -0.3219 ...
again, it doesn't even get into the objective function - I checked that
Many thanks
Stephane
-Original Message-
From: Uwe Ligges [mailto:[EMAIL PROTECTED]
Sent: 14
Dear all,
in the first paragraph in Section 4.3.2 of the R Data Import/Export
Manual, it is written 'We havew tested...'. Most likely it should be
'We have tested...'
It is just such a minor thing that I was unsure whether to submit a bug
report.
I use now R 2.2.1 on Win32 but I guess this is
On 3/14/06, Thomas Lumley [EMAIL PROTECTED] wrote:
On Tue, 14 Mar 2006, John McHenry wrote:
Thanks, Gabor Thomas.
Apologies, but I used an example that obfuscated the question that I
wanted to ask.
I really wanted to know how to have extra arguments in functions that
would allow,
vincent david wrote:
Hi,
I was just trying to figure out how to beautify the output of my
bwplot-output. Altogether I figured most of the things out on my own. The
one thing which puzzles me though are the symbols for the outliers.
I can easily change the form of the median symbol by
Hello I've checked through previous postings but don't see a fully
equivalent problem-just a few hints.
I have been trying to set a new method for the existing function table
or as.data.frame.table for my class tfSites.
Taking out all the useful code and just returning the input class I get
On 3/14/2006 10:58 AM, Rau, Roland wrote:
Dear all,
in the first paragraph in Section 4.3.2 of the R Data Import/Export
Manual, it is written 'We havew tested...'. Most likely it should be
'We have tested...'
It is just such a minor thing that I was unsure whether to submit a bug
hi,friends,
we all know that moran's I index and Geary'C index can be used to test
spatial autocorrelation in both the area data and point data, but i only can
find something on how to calculate on the data of area, and can't find the
methods to perform it on the point data, could anybody give me
Hi:
Does anyone know how to run a test of trends for repeated measurements
in R?
Thanks
Graciela
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide!
I tried the following ordered logistic regression in R:
mod1 - polr(altitude~sp + wind_dir + wind_speed + hr, data=altioot)
But when I asked The summary of my regression I got the folloing error message:
summary (mod1)
Re-fitting to get Hessian
Error in optim(start, fmin, gmin, method =
---sorry to repost I sent it as HTML last time---
Hello I've checked through previous postings but don't see a fully
equivalent problem-just a few hints.
I have been trying to set a new method for the existing function table
or as.data.frame.table for my class tfSites.
Taking out all the useful
On 3/14/06, Sundar Dorai-Raj [EMAIL PROTECTED] wrote:
vincent david wrote:
Hi,
I was just trying to figure out how to beautify the output of my
bwplot-output. Altogether I figured most of the things out on my own. The
one thing which puzzles me though are the symbols for the outliers.
My thanks to all who replied. Your advice and links were very helpful.
Kind regards,
-- Bert
Bert Gunter
Genentech
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide!
On Tue, 14 Mar 2006, Gabor Grothendieck wrote:
On 3/14/06, Thomas Lumley [EMAIL PROTECTED] wrote:
It is probably worth pointing out here that the R documentation does not
specify the order in which lapply() does the computation.
I suspect that a huge amount of application code takes
Insightful is in need of a statistician/research scientist interested in
researching and developing mixed models. There is a strong computational
component to the work. The person would be responsible for developing
S-PLUS/R packages, first focusing on mixed models (frailty in particular),
and
On 3/14/06, Thomas Lumley [EMAIL PROTECTED] wrote:
On Tue, 14 Mar 2006, Gabor Grothendieck wrote:
On 3/14/06, Thomas Lumley [EMAIL PROTECTED] wrote:
It is probably worth pointing out here that the R documentation does not
specify the order in which lapply() does the computation.
I
On Tue, 14 Mar 2006, Gabor Grothendieck wrote:
On 3/14/06, Thomas Lumley [EMAIL PROTECTED] wrote:
On Tue, 14 Mar 2006, Gabor Grothendieck wrote:
On 3/14/06, Thomas Lumley [EMAIL PROTECTED] wrote:
It is probably worth pointing out here that the R documentation does not
specify the order in
Erez Shabo shaboerez at gmail.com writes:
Hello all,
I'm trying to calculate the Maximum likelihood of individuals to get the
ancestry.
I mixd 3 populations 15 generations in proportion of 20% 20% 60% when each
population
sorce have diferent genome (0 1 and 2) with frequencies for each
Hello again,
I'm still confused how this is supposed to work. Especially the symbol for
the outliers still puzzle me. This is what I do:
bwplot (points ~ general[,1] | groups,
layout = c(1, 3),
scales = list(x = list(at = seq(10, 100, by=5), labels=seq(10, 100,
by=5),
On 3/14/06, Thomas Lumley [EMAIL PROTECTED] wrote:
On Tue, 14 Mar 2006, Gabor Grothendieck wrote:
On 3/14/06, Thomas Lumley [EMAIL PROTECTED] wrote:
On Tue, 14 Mar 2006, Gabor Grothendieck wrote:
On 3/14/06, Thomas Lumley [EMAIL PROTECTED] wrote:
It is probably worth pointing out here
Hello.
I have a vector of length 2771 but it has only 87 different values.
How can I obtain them?
Thanks,
Arnau.
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide!
On Tue, 2006-03-14 at 18:45 +0100, Arnau Mir wrote:
Hello.
I have a vector of length 2771 but it has only 87 different values.
How can I obtain them?
Thanks,
Arnau.
If you just want the unique values themselves, you can use:
unique(vector)
For example:
v
[1] b b c a a a c c c c
Hi, Vincent,
You need to add
par.settings = list(plot.symbol = list(pch = 2, col = blue, cex = 2))
to your bwplot call. Just change the values for pch, col, cex,
etc. to suit your needs. The plot.symbol setting determines the symbol
for the outliers. As Deepayan noted, it's not documented in
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] Behalf Of Arnau Mir
Sent: Tuesday, March 14, 2006 12:45 PM
To: r-help@stat.math.ethz.ch
Subject: [R] different values of a vector
Hello.
I have a vector of length 2771 but it has only 87 different values.
?unique
Arnau Mir wrote:
Hello.
I have a vector of length 2771 but it has only 87 different values.
How can I obtain them?
Thanks,
Arnau.
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do
Dear R Users,
I have some data that is very similar in form to a 3D image - ie univariate
data on a regular 3D grid. I keep this as a 3D numeric array in R with
attributes describing the sampling points along the 3 dimensions.
I would like to interpolate this onto a new regular 3D grid that I
Here's my contribution to R.
When R interacts with external programs (MySQL, cURL, etc.), it often
requires a pasted string that is sent to these programs. For readability
reasons, it is often preferable to have complex commands (SQL for example)
spread on several lines. However, the normal paste
Hello,
I have some stupid problems managing date data.
I have a colomn date, which I converted from a character representation:
for example:
a=26/02/06
date=strptime(a,format=%d/%m/%y)
For one part of the analysis, I'm interested only in the month and the
year, so I did:
Hi,
that was it! I managed to set me parameters properly using:
trellis.par.set(...
What I still not quite understand though is how to use:
par.settings = ...
I cant use it in the bwplot-command itself - this throws a error. Whereas
using it in a:
panel = function (...){...
enviroment
Hi-
General question:
I have written a function that performs a permutation test. I use the
function sample to randomize my data, then I call on another function
I wrote to analyze the randomized data. This process repeats n
times-- 10, 100 or whatever.
The function applied to the randomized
Does anyone know of an implementation in R of the Hodges-Lehmann
nonparametric difference between two groups? I am interested in the
estimate of the difference and the CI or significance of that difference. I
did some quick searching and didn't see it, but I may not have been looking
for the
Emilie Berthiaume wrote:
I tried the following ordered logistic regression in R:
mod1 - polr(altitude~sp + wind_dir + wind_speed + hr, data=altioot)
You might also try
library(Design) # also requires Hmisc package
mod1 - lrm()
mod1
summary(mod1)
anova(mod1)
Frank Harrell
But when I
vincent david wrote:
Hi,
that was it! I managed to set me parameters properly using:
trellis.par.set(...
What I still not quite understand though is how to use:
par.settings = ...
I cant use it in the bwplot-command itself - this throws a error.
What error? What version of
I am not sure I clearly understand what you want, but getting the string
returned by your multi.line.paste() function is straightforward using
gsub():
gsub(\n, ,
SELECT *
FROM estimates a, newtable b
WHERE a.Ticker=b.Ticker
AND a.Fiscal_Year=b.Fiscal_Year
AND a.EPSb.EPS
AND
if(any(is.nan(...)))... ##repeat
However,
1) Have you tried RSiteSearch('permutation test',restr='function') to see
what's already there?
2) I suspect that there are better ways to do this. In particular,
generating all random whatevers at once is way more efficient than repeated
calls;
2) It
On 3/14/06, natalia norden [EMAIL PROTECTED] wrote:
Hello,
I have some stupid problems managing date data.
I have a colomn date, which I converted from a character representation:
for example:
a=26/02/06
date=strptime(a,format=%d/%m/%y)
For one part of the analysis, I'm interested only in
Hello Phillipe
1-You are right that for a simple example as the one I provided, paste and
gsub give the same result.
2-For a more complex case, where let's say, I'd like to include a variable
in my SQL statement, the multi.line.paste command is essential.
variable -1.9
multi.line.paste(
SELECT *
On Wed, 15 Mar 2006, zhijie zhang wrote:
hi,friends,
we all know that moran's I index and Geary'C index can be used to test
spatial autocorrelation in both the area data and point data, but i only can
find something on how to calculate on the data of area, and can't find the
methods to
Lapointe, Pierre wrote:
Hello Phillipe
1-You are right that for a simple example as the one I provided, paste and
gsub give the same result.
2-For a more complex case, where let's say, I'd like to include a variable
in my SQL statement, the multi.line.paste command is essential.
variable
You use tune function to find optimal parameters needed for particular
classification algorithm. I had more experience with tune.svm but, I
would try first to put parameters covering the whole possible range of
each variable (in which algorithm do not crash), for example c(4^-2,
4^-1, 4^0, 4^1,
On Tue, 2006-03-14 at 14:07 -0500, Sean Davis wrote:
Does anyone know of an implementation in R of the Hodges-Lehmann
nonparametric difference between two groups? I am interested in the
estimate of the difference and the CI or significance of that difference. I
did some quick searching and
Package gstat allows 3D interpolation. It doesn't accept
a 3D array directly; you'll have to provide it as
x1 y1 z1 obs1
x2 y2 z2 obs2
etc, e.g. by using expand.grid. Or, you may want to try
out the classes provided by package sp, which allow for
more than 2 dimensions in case of points and
On Tue, 14 Mar 2006, Sean Davis wrote:
Does anyone know of an implementation in R of the Hodges-Lehmann
nonparametric difference between two groups? I am interested in the
estimate of the difference and the CI or significance of that difference. I
did some quick searching and didn't see it,
Hi,
if I plot a normal distribution like this:
d-density(rnorm(1))
plot(d)
how can I highlight the area below the graph in a certain interval,
say x=1,2? I understand that I should use polygon, but I have not
found the right way to give the result that I want.
Thanks a lot!
Georg
How about,
d-density(rnorm(1))
plot(d)
wvs - which(d$x 1 d$x 2)
polygon(d$x[c( wvs[1], wvs, wvs[length(wvs)] ) ], c(0, d$y[wvs], 0), col =
bisque)
Georg Otto a écrit:
Hi,
if I plot a normal distribution like this:
d-density(rnorm(1))
plot(d)
how can I highlight the area below the
On 3/13/06, Prof Brian Ripley [EMAIL PROTECTED] wrote:
On Mon, 13 Mar 2006, Martin Maechler wrote:
JohnF == John Fox [EMAIL PROTECTED]
on Sat, 11 Mar 2006 13:29:34 -0500 writes:
JohnF Dear Deepayan, As you say, it's currently very easy
JohnF to change settings (which is what
Would anyone with experience with the map functions know how to divide
Czechoslovakia into the Czech Republic and Slovakia. They have been two
separate countries for some time now. I'm thinking about the worldhires
map database in particular.
--
Dean Sonneborn, MS
Programmer Analyst
I have a dataset with 20 columns and ~600,000 rows.
Column 1 has a number from 2-19. This number tells
me, for each row, which column has the applicable
data. (i.e. the data that I wish to use for each
individual row)
I want to create a vector that contains the data from
the value in column
Hi everyone,
I am running an ordinal probit using the Bayesian MCMCpack and I am getting an
error saying attempt for find suitable starting values failed
Here is my code:
posterior - MCMCoprobit(y ~ x1 + x2 + x3 + x4 + x5 + x6 + x7 + x8 +x9 + x10
+ x11 + x12 +x13 , beta.start=c(-10, 0.05,
From ?] note that:
When indexing arrays by '[' a single argument 'i' can be a
matrix with as many columns as there are dimensions of 'x';
the result is then a vector with elements corresponding to
the sets of indices in each row of 'i'.
so:
mm -
Hello all,
I have a data frame with year, month, species, fishing gear and catch
(Y, M, S, F, C) and I want the sum of C by Y for species A and fishing
gear trawl.
I tried things like aggregate(C[S==A F==trawl], list (Year =
Y[S==A F==trawl]), fun=sum), but it didn't worked.
To overcome
The following dummy data frame has factor Q (with 2 levels) nesting
factor P (with levels p1 and p2 nested under q1, and p3 and p4 nested
under q2), but both crossing the random variate s, which has 8
levels. The dependent measure is dv.
# The data frame:
testnest
dv s P Q
1 1
Hello,
I recently posted a question about my troubles with
importing
a lattice/trellis figure into latex.
To recap,
The figure contains 3 scatterplots, so it should have
roughly a 1:3 sort
of aspect ratio, in order to make each of the
scatterplots square.
Instead, the whole figure comes out
context grey wrote:
Hello,
I recently posted a question about my troubles with
importing
a lattice/trellis figure into latex.
To recap,
The figure contains 3 scatterplots, so it should have
roughly a 1:3 sort
of aspect ratio, in order to make each of the
scatterplots square.
Here is an example using the builtin data set, CO2, where we
aggregate uptake over Treatment for Plant equal to Qn1 and
Type equal to Quebec.
with(subset(CO2, subset = Plant == Qn1 Type == Quebec),
aggregate(list(uptake = uptake), list(Treatment = Treatment), sum))
or equivalently:
Thank you. However I don't think I understand the
response here.
In what sense do I want a nonstandard layout?
Is because I am specify aspect=1/1 in the xyplot() ?
If so, then is there some other way to cause the
scatterplot
to be rougly square? I took this out and looked at
the result
On 3/14/2006 9:29 PM, context grey wrote:
Thank you. However I don't think I understand the
response here.
In what sense do I want a nonstandard layout?
You said you want something that is wide and short (3 squares, side by
side). The standard layout would fit on a normal piece of
Hi there, I have a question regarding model comparisons that seems
simple enough but to which I cannot find an answer. I am interested in
developing a predictive model relating some measure of a tree's stem to
the total leaf area (TLA) of the tree. Predictor variables might
include, for
--- Duncan Murdoch [EMAIL PROTECTED] wrote:
The R graphics model is that the drawing surface is
established first,
then the things you draw are adjusted to fit in it.
R won't change the
shape of the display because you are drawing more
things on it.
Thanks, this comment clarifies
Hi
Can anybody please suggest me about the documentation of factanal.fit.mle()
(Not factanal()-- searching factanal.fit.mle() in R always leads to
factanal()).
Is there any function for doing principal component factor analysis in R.
Regards
Souvik Bandyopadhyay
JRF,
Dept Of Statistics
Dear R-users
My problem is the following:
1) Suppose we have the data test.txt:
Data has form: Subject age test (=binary variable)
1 0.6 0
2 2 1
3 0.9 1
...
2) I
Hi all,
I am trying to use GAM to work on some data... Are there any resources
providing hands-on tutorial/guide on how to do GAM on data in R?
Specifically, I am not sure about which model to choose, and smooth models
with which effective degree-of-freedom shall I use...
I knew there is a book
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