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Oleg Bartunov, Research Scientist, Head of AstroNet (www.astronet.ru),
Sternberg Astronomical Institute, Moscow University, Russia
Internet: oleg@sai.msu.su, http://www.sai.msu.su/~megera/
phone: +007(495)939-16-83, +007(495)939-23-83
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R-help
Hello,
is't possible to get excerptions of data frame using some contstraints,
something like q1 = q[q$V31] ?
Regards,
Oleg
_
Oleg Bartunov, sci.researcher, hostmaster of AstroNet,
Sternberg Astronomical Institute
Philipp
Regards,
Oleg
_
Oleg Bartunov, sci.researcher, hostmaster of AstroNet,
Sternberg Astronomical Institute, Moscow University (Russia)
Internet: [EMAIL PROTECTED], http://www.sai.msu.su/~megera/
phone: +007
On Thu, 1 Apr 2004, Duncan Murdoch wrote:
On Thu, 1 Apr 2004 15:38:54 +0400 (MSD), Oleg Bartunov
[EMAIL PROTECTED] wrote :
Hello,
for testing learning purposes I create X11 device and specify layout like
layout(c(1,2,3), 3, 1), so I could play with parameters and see
several plots
instead of layout.
Example:
par(bg = white) # default is likely to be transparent
split.screen(c(3,1))# split display into three screens
screen(1)
plot(1:10)
screen(2)
plot(2:20)
screen(3)
plot(3:30)
screen(1)
erase.screen()
plot(sin(40:400))
Angel
Oleg Bartunov wrote
)
return(i)
}
plot(1:10)
i-nextplot(i)
plot(2:20)
i-nextplot(i)
plot(3:30)
i-nextplot(i)
plot(sin(40:400))
i-nextplot(i)
plot(sin(4:40))
## Continue your plots
close.screen(all = TRUE)
Oleg Bartunov wrote:
interesting, it works, but still need to explicitly specify screen number
.
Regards,
Oleg
_
Oleg Bartunov, sci.researcher, hostmaster of AstroNet,
Sternberg Astronomical Institute, Moscow University (Russia)
Internet: [EMAIL PROTECTED], http://www.sai.msu.su/~megera/
phone: +007(095)939-16-83, +007(095
On Mon, 29 Mar 2004, Gabor Grothendieck wrote:
Oleg Bartunov oleg at sai.msu.su writes:
I have numeric vector z and I want to factorize it using z$breaks
Have a look
at:
?cut
Thanks for pointers, this is what I needed.
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[EMAIL PROTECTED
PROTECTED]
From: Oleg Bartunov [EMAIL PROTECTED]
I have numeric vector z and I want to factorize it using z$breaks
which I got from histograms breaks. Is there an elegant way to do this ?
I, probably, could write a loop and check if z hits into some interval
and replace z with value of z$mids
On Mon, 29 Mar 2004, Achim Zeileis wrote:
On Tue, 30 Mar 2004 00:06:39 +0400 (MSD) Oleg Bartunov wrote:
Eric,
thanks for quick reply. at first look I thought it is what I need,
but, unfortunately, it doesn't applied to original data - it
creates new data with loosing original indexes
Hi there,
I'm beginner and would like to have mailing list archive to
read it offline and don't disturb mailing list.
I'd prefer mbox format.
Regards,
Oleg
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Oleg Bartunov, sci.researcher, hostmaster of AstroNet
On Thu, 25 Mar 2004, Roger D. Peng wrote:
You can get archives of the list at the URL listed at the bottom of
this email.
Thanks !
-roger
Oleg Bartunov wrote:
Hi there,
I'm beginner and would like to have mailing list archive to
read it offline and don't disturb mailing list
, F and M, where
F means everything beginning from 'f' and M - from 'm'.
Something like cut() for numerical data.
Regards,
Oleg
_
Oleg Bartunov, sci.researcher, hostmaster of AstroNet,
Sternberg Astronomical
,fm,mf,ffm,mmf,mmm,fff))
levels(y) - substring(levels(y), 1, 1)
y
[1] f f m m f m f m m f
Levels: f m
Andy
From: Oleg Bartunov
Hello,
is't possible to specify pattern in levels ?
y=c(ff,f,m,mm,fm,mf,ffm,mmf,mmm,fff);
factor(y)
[1] ff f m mm fm mf ffm mmf mmm
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