Birgit Lemcke wrote:
Hello,
(Power Book G4, Mac OS X, R 2.5.0)
I would like to repeat the function range for 85 Vectors (V1-V85).
I tried with this code:
i-0
repeat {
+ i-i+1
+ if (i85) next
+ range (Vi, na.rm = TRUE)
+ if (i==85) break
+ }
I presume that the Vi is wrong,
Hello Jim,
thanks for your answer. At the moment I am using this code:
Range0-sapply(1:85, function(i) eval(parse(text=paste(range(V, i,
, na.rm=T), sep=
and it works really fine.
The code you sent me is also fine but how can I implement, that
missing values are TRUE?
Thanks a lot for
On 6/29/07, Birgit Lemcke [EMAIL PROTECTED] wrote:
Hello Jim,
thanks for your answer. At the moment I am using this code:
Range0-sapply(1:85, function(i) eval(parse(text=paste(range(V, i,
, na.rm=T), sep=
It is a matter of taste, but I tend to prefer:
a - list()
for (i in 1:85)
Hello,
(Power Book G4, Mac OS X, R 2.5.0)
I would like to repeat the function range for 85 Vectors (V1-V85).
I tried with this code:
i-0
repeat {
+ i-i+1
+ if (i85) next
+ range (Vi, na.rm = TRUE)
+ if (i==85) break
+ }
I presume that the Vi is wrong, because in this syntax i is not known
sapply(1:85, function(i) eval(parse(text=paste(range(V, i, ,
na.rm=T), sep=
Jacques VESLOT
INRA - Biostatistique Processus Spatiaux
Site Agroparc 84914 Avignon Cedex 9, France
Tel: +33 (0) 4 32 72 21 58
Fax: +33 (0) 4 32 72 21 84
Birgit Lemcke a écrit :
Hello,
(Power Book G4, Mac OS
Thanks that was really a quick answer.
It works but I get this warning message anyway:
1: kein nicht-fehlendes Argument für min; gebe Inf zurück (None not-
lacking argument for min; give Inf back)
2: kein nicht-fehlendes Argument für max; gebe -Inf zurück
what does this mean?
Greeting and
: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of Birgit Lemcke
Sent: 28 June 2007 10:48
To: R Hilfe
Subject: [R] Repeat if
Hello,
(Power Book G4, Mac OS X, R 2.5.0)
I would like to repeat the function range for 85 Vectors (V1-V85).
I tried with this code:
i-0
repeat {
+ i-i+1
+ if (i85
Your V1 to V85 are probably coming from a data.frame, aren't they?
If yes, and if this data.frame is named 'a', you can use 'sapply(a,range)'
Otherwise, see ?get (get(paste(V,1,sep=)) returns V1)
Christophe
On 6/28/07, Birgit Lemcke [EMAIL PROTECTED] wrote:
Hello,
(Power Book G4, Mac OS X,
you may have a vector with only NA values in it...
max(c(NA,NA), na.rm=T)
[1] -Inf
Warning message:
aucun argument pour max ; -Inf est renvoyé
Jacques VESLOT
INRA - Biostatistique Processus Spatiaux
Site Agroparc 84914 Avignon Cedex 9, France
Tel: +33 (0) 4 32 72 21 58
Fax: +33 (0) 4 32 72 21
Birgit Lemcke wrote:
Thanks that was really a quick answer.
It works but I get this warning message anyway:
1: kein nicht-fehlendes Argument f�r min; gebe Inf zur�ck (None not-
lacking argument for min; give Inf back)
2: kein nicht-fehlendes Argument f�r max; gebe -Inf zur�ck
what does
Thats not the case.
I have two vectosr with a lot of NAs, but not only NAs.
But nevertheless as i saw the results are accurate.
Birgit
Am 28.06.2007 um 15:17 schrieb Jacques VESLOT:
you may have a vector with only NA values in it...
max(c(NA,NA), na.rm=T)
[1] -Inf
Warning message:
: [R] Repeat if
Hello,
(Power Book G4, Mac OS X, R 2.5.0)
I would like to repeat the function range for 85 Vectors (V1-V85).
I tried with this code:
i-0
repeat {
+ i-i+1
+ if (i85) next
+ range (Vi, na.rm = TRUE)
+ if (i==85) break
+ }
Birgit Lemcke
Institut für Systematische Botanik
Thanks Christophe,
I received already an answer with a similar suggestion.
But thanks for your answer.
Birgit
Am 28.06.2007 um 12:34 schrieb Christophe Pallier:
Your V1 to V85 are probably coming from a data.frame, aren't they?
If yes, and if this data.frame is named 'a', you can use
Hello Patrick,
this does not work and gives following warning message:
for(i in 1:85) range(get(paste(V, i, sep=)), na.rm=TRUE)
Warning messages:
1: kein nicht-fehlendes Argument für min; gebe Inf zurück
2: kein nicht-fehlendes Argument für max; gebe -Inf zurück
This works but also with the
: 28 June 2007 15:12
To: john seers (IFR)
Cc: R Hilfe
Subject: Re: [R] Repeat if
Hello John,
I tried this code. But I got only the ranges of V1 and V2 what is easily
understandable.
Do I have to write in all 85 vectors in the first line?
V-list(a=c(V1), b=c(V2))
for ( i in 1:85 ) { # 2
Sorry Jacques and all the other helpful people!
I made a mistake because I didn´t realize that I have a vector only
containing NAs. That happened during standardization and i didn´t
check this.
I apologize for that.
Greetings
Birgit
Am 28.06.2007 um 15:17 schrieb Jacques VESLOT:
you may
Hi R list:
How can I repeat a data frame n times (with n1000),
and obtain a new data frame where all the n data frames
are binded by rows?
Thank you for your help
Kenneth
--
Using Opera's revolutionary e-mail client: http://www.opera.com/mail/
__
Maybe the function merge is what you need. Xiaohua
On 5/1/06, Kenneth Cabrera [EMAIL PROTECTED] wrote:
Hi R list:
How can I repeat a data frame n times (with n1000),
and obtain a new data frame where all the n data frames
are binded by rows?
Thank you for your help
Kenneth
--
Using
Sorry, I give a wrong answer. X
On 5/1/06, Xiaohua Dai [EMAIL PROTECTED] wrote:
Maybe the function merge is what you need. Xiaohua
On 5/1/06, Kenneth Cabrera [EMAIL PROTECTED] wrote:
Hi R list:
How can I repeat a data frame n times (with n1000),
and obtain a new data frame where
On Mon, 1 May 2006, Kenneth Cabrera wrote:
Hi R list:
How can I repeat a data frame n times (with n1000),
and obtain a new data frame where all the n data frames
are binded by rows?
Perhaps
my_df[rep(1:nrow(my_df), times=n), ]
is what you want?
--
Brian D. Ripley,
Well, I find a solution!
If DFe is a data frame and n is an integer then
DFr-data.frame(t(matrix(rep(t(DFe),n),dim(DFe)[2],dim(DFe)[1]*n)))
names(DFr)-names(DFe)
Will work!!
Maybe somebody has a more elegant solution.
Again, thank you for your help.
On Mon, 01 May 2006 11:23:14 -0500,
As I said, a very more elegant solution!
Thank you!
On Mon, 01 May 2006 11:52:44 -0500, Prof Brian Ripley
[EMAIL PROTECTED] wrote:
my_df[rep(1:nrow(my_df), times=n), ]
--
Using Opera's revolutionary e-mail client: http://www.opera.com/mail/
__
--- Henrik Bengtsson [EMAIL PROTECTED] a écrit :
Hi.
Using Rterm v2.2.1 on WinXP, is there a way to
interrupt a call like
repeat { readline() }
without killing the Command window? Ctrl+C is not
interrupting the loop:
To interupt the loop add and condition for a break
like this :
Use tryCatch; try behaves the way it does with respect to interrupts
for historical compatibility.
luke
On Sun, 8 Jan 2006, hadley wickham wrote:
On a related note, does anyone know how to exit:
repeat { try( readline() ) }
The try block captures Ctrl-C.
Hadley
Ctrl-Break works: see the rw-FAQ and README.rterm. (You'll need a return
to see a new prompt.)
It is related to your reading directly from the console, so Ctrl-C is
getting sent to the wrong place, I believe. (There's a comment from Guido
somewhere in the sources about this, and this seems
On a related note, does anyone know how to exit:
repeat { try( readline() ) }
The try block captures Ctrl-C.
Hadley
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide!
On Sun, 8 Jan 2006, Prof Brian Ripley wrote:
Ctrl-Break works: see the rw-FAQ and README.rterm. (You'll need a return
to see a new prompt.)
It is related to your reading directly from the console, so Ctrl-C is
getting sent to the wrong place, I believe. (There's a comment from Guido
Prof Brian Ripley wrote:
On Sun, 8 Jan 2006, Prof Brian Ripley wrote:
Ctrl-Break works: see the rw-FAQ and README.rterm. (You'll need a return
to see a new prompt.)
It is related to your reading directly from the console, so Ctrl-C is
getting sent to the wrong place, I believe. (There's
Hi.
Using Rterm v2.2.1 on WinXP, is there a way to interrupt a call like
repeat { readline() }
without killing the Command window? Ctrl+C is not interrupting the loop:
R : Copyright 2006, The R Foundation for Statistical Computing
Version 2.2.1 Patched (2006-01-01 r36947)
snip/snip
To whoever this may concern
I am trying to write a repeat loop and can't make out from the documentation on
the website how exactly to construct the repeat, break structure of the loop.
Below is the function sim2.dat that I am trying to create, in which firstly I
create n random uniform(0,1)
[j]F){break}
}
u[j]-k
}
u
}
- Original Message -
From: Michael Gray [EMAIL PROTECTED]
To: R-help@stat.math.ethz.ch
Sent: Tuesday, December 28, 2004 12:47 PM
Subject: [R] R: repeat loops
To whoever this may concern
I am trying to write a repeat loop and can't make out from
Hi,
I'm in this situation:
I what to generate N random numbers(integer) that are different from each
other.
One suggestion:
tabel - rep(NULL, N)
for (i in 1:N){
temp - as.integer(runif(1,1,max))
if(temp in tabel) {
repeat (?) (temp - as.integer(runif(i,i,max)))
until (?) ((temp
I what to generate N random numbers(integer) that are different from each
other.
One suggestion:
tabel - rep(NULL, N)
for (i in 1:N){
temp - as.integer(runif(1,1,max))
if(temp in tabel) {
repeat (?) (temp - as.integer(runif(i,i,max)))
until (?) ((temp in tabel) ==FALSE)
Message-
From: Ragnhild Sørum [mailto:[EMAIL PROTECTED]
Sent: Wednesday, November 12, 2003 9:26 AM
To: [EMAIL PROTECTED]
Subject: [R] repeat until function
Hi,
I'm in this situation:
I what to generate N random numbers(integer) that are
different from each
other.
One
On Wed, 12 Nov 2003, Liaw, Andy wrote:
As others already pointed out, the fast way is to use sample().
What I'd like to add is the following, which I learned from peeking at the C
code underneath sample(): To draw n samples without replacement from 1:N
(N=n), you only need a loop from 1 to
Liaw, Andy [EMAIL PROTECTED] writes:
This is obviously not efficient in high-level languages like R, but in terms
of algorithm, it is a lot more efficient than check-and-reject. IMHO this
should be described in some book, but I have not seen any book describing
it.
I'm pretty sure I have -
On Wed, 12 Nov 2003 12:00:06 -0500, Liaw, Andy [EMAIL PROTECTED]
wrote :
This is obviously not efficient in high-level languages like R, but in terms
of algorithm, it is a lot more efficient than check-and-reject. IMHO this
should be described in some book, but I have not seen any book
From: Prof Brian Ripley [mailto:[EMAIL PROTECTED]
Ripley (1987) Stochastic Simulation, pp.80-1 for one. I am
pretty sure it is Knuth's book, although I don't have that to
hand. I attribute it to
Moses Oakford (1963).
Thanks to Brian, Peter and Duncan for the info. And I have both
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