Eric,
thanks for quick reply. at first look I thought it is what I need,
but, unfortunately, it doesn't applied to original data - it
creates new data with loosing original indexes ! I want to keep indexes
of original data, but replace original data with $mids of corresponding
$breaks.
So, if I
Oleg Bartunov oleg at sai.msu.su writes:
I want to keep indexes
of original data, but replace original data with $mids of corresponding
$breaks.
Note the label= arg on cut:
cut(z,t$breaks,lab=t$mids)
__
[EMAIL PROTECTED] mailing list
On Tue, 30 Mar 2004 00:06:39 +0400 (MSD) Oleg Bartunov wrote:
Eric,
thanks for quick reply. at first look I thought it is what I need,
but, unfortunately, it doesn't applied to original data - it
creates new data with loosing original indexes ! I want to keep
indexes of original data, but
On Mon, 29 Mar 2004, Achim Zeileis wrote:
On Tue, 30 Mar 2004 00:06:39 +0400 (MSD) Oleg Bartunov wrote:
Eric,
thanks for quick reply. at first look I thought it is what I need,
but, unfortunately, it doesn't applied to original data - it
creates new data with loosing original indexes