Hey everyone,
I'm trying to create a data frame using read.geoda and a csv. document
I get an result, but the names of my columns are missing, instead I get som
randomly chosen names for the columnes. When I use read.csv everything is
working as it should.
Regards
Tanja
[[alternative
Please do not post HTML - I explained yesterday how to avoid this
nuisance.
Just use read.csv() or read.csv2() - read.geoda is only a wrapper, so if
your CSV uses ; instead of , failure will follow for obvious reasons.
Open the CSV in a text editor to see what it actually looks like, or say
Hi Dick,
Can you send us your script?
Best regards,
Thierry
ir. Thierry Onkelinx
Instituut voor natuur- en bosonderzoek / Research Institute for Nature and
Forest
team Biometrie Kwaliteitszorg / team Biometrics Quality Assurance
Kliniekstraat 25
1070 Anderlecht
Belgium
+ 32 2 525 02 51
+ 32
Dear all,
I am trying to run an ENFA using ADE package though I am stuck in this
error, and I do not understand what could be the problem.
Error in eigen(Se) : infinite or missing values in 'x'
I get the error message after the following step:
dataenfa1 - data2enfa(var,locs)
(enfa1 -
Dear list,
I'm trying to apply a function to lists of rasters, but without success.
I'm not sure if it feasible of if I should use a for loop.
Let's say a, b and c are three lists of argument to my function
1/(1-exp(-exp(-((a - b)/c (2 rasters each)
I'd like this function to be applied to
There may be a problem.
mapply(function(a, b, c) exp(a), A, B, C)
alas
exp(A[[1]])
class : RasterLayer
dimensions : 2, 2, 4 (nrow, ncol, ncell)
resolution : 0.5, 0.5 (x, y)
extent : 0, 1, 0, 1 (xmin, xmax, ymin, ymax)
coord. ref. : NA
data source : in memory
names
I try to understand the hierarchical randomization as applied in the GRTS
design.
I randomized 16 points on a square grid, see R script below. The argument
do.sample was set to FALSE, so that the result consists of a dataframe of
all 16 points instead of a GRTS sample. When plotting the order
mapply does indeed not seem to work here, further illustrated below. I do
not know why. However, in this case I think it is simpler not to use mapply
(see example at the very end).
library(raster)
Loading required package: sp
raster 2.1-3 (1-February-2013)
aa-matrix(c(2,1,3,4),nrow=2,ncol=2)
Tom Roche Sun, 10 Feb 2013 14:40:05 -0500
$ ls -alh ./METCRO3D_080101
-r--r--r-- 1 me mygroup 5.3G Jan 8 11:32 ./METCRO3D_080101
# extension used below
$ ln -s ./METCRO3D_080101 ./METCRO3D_080101.nc
...
raster('./METCRO3D_080101.nc', varname='ZF')
...
Error in .local(.Object, ...) :
On Mon, Feb 11, 2013 at 9:31 AM, Tom Roche tom_ro...@pobox.com wrote:
Tom Roche Sun, 10 Feb 2013 14:40:05 -0500
$ ls -alh ./METCRO3D_080101
-r--r--r-- 1 me mygroup 5.3G Jan 8 11:32 ./METCRO3D_080101
# extension used below
$ ln -s ./METCRO3D_080101 ./METCRO3D_080101.nc
...
All--
Does anyone know if the update from R 2.15.2 to 3.0 is likely to change
they way these binaries would need to be built? I don't think that the
NAMESPACE .First.lib changes will matter, but I don't understand the
implications of long.vectors. http://developer.r-project.org/30update.txt
On Mon, 11 Feb 2013, Tom Philippi wrote:
All--
Does anyone know if the update from R 2.15.2 to 3.0 is likely to change
they way these binaries would need to be built? I don't think that the
NAMESPACE .First.lib changes will matter, but I don't understand the
implications of long.vectors.
Hi,
I have mapped structures with a GPS (walked along their edges) and Im
now trying to make polygons from my coordinates. The GPS data are a bit
fuzzy and I want to establish the edge of the structure with a smoother
or similar. However, I have not been able to find an easy way to do this
in
Hi all:
I am using the precipitation (pr) data from rcm3-cgcm3 model. I used the
ncdf4 package to open the precipitation data. Some values are very close to
zero, for example 3*10^(-23), and there are even some negative values (like
-3*10^(-21)). Should I treat these values as zero? I don't
Dear Adrian and Rolf,
Thank you for your comments.
I am considering your comments to understand them.
I will send such questions to the package authors.
Regards,
Hiroshi Saito
On Mon, 11 Feb 2013 13:56:42 +0800
adrian.badde...@csiro.au wrote:
On 02/08/2013 01:48 PM, Hiroshi Saito wrote:
Dear list,
I am currently working on spatial autoregression modeling for my dissertation
research. I want to use regression models to identify socioeconomic/landscape
variables (15 total, var1$bat_survey - var15$bay_survey) that can affect the
presence/absence of bats (p/a$bat_survey). Since
Hi - Are there alternatives to using the raster package zonal function
for large images when using functions for the stat parameter? The
canned functions like 'mean' work well but I would like to write my own
functions to calculate standard deviation and other statistics.
I tried extract
On Mon, Feb 11, 2013 at 10:44 PM, Ned Horning horn...@amnh.org wrote:
Hi - Are there alternatives to using the raster package zonal function
for
large images when using functions for the stat parameter?
I would be interested to know as well. I have found both extract and
zonal to be
On Tue, 12 Feb 2013, Li, Han wrote:
Dear list,
I am currently working on spatial autoregression modeling for my
dissertation research. I want to use regression models to identify
socioeconomic/landscape variables (15 total, var1$bat_survey -
var15$bay_survey) that can affect the
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