i,"Y"]+150,dat[i,"Y"]+150,dat[i,"Y"]-150,dat[i,"Y"]-150,paste("Number.",i,sep=""))
}
SpP = SpatialPolygons(my.list, 1:n)
SrDf = SpatialPolygonsDataFrame(SpP, dat[1:n,])
writePolyShape(SrDf, fn="FemRutor")
Tord
From: romunov
Hi,
I want to make approximately 1 square polygons (300*300) based on
coordinates in a data frame, and make a .shp-file out of these.
The .pdf "S Classes and Methods for Spatial Data: the sp Package" by Pebesma
and Bivand contains an instruction on how to do this, and it works very well,
e.
utfile,append=T)
}
------
Hi Tord,
I think you will find the extract you require in this paper
https://beardocs.baylor.edu/bitstream/2104/3955/1/john_mcbride_phd.pdf
Search the document for Yue Cui and it will bring you to the page.
I have used the co
.
Thanks,
Tord
--
Tord Snäll
Department of Ecology
Swedish University of Agricultural Sciences (SLU)
P.O. 7044, SE-750 07 Uppsala, Sweden
Office/Mobile/Fax
+46-18-672612/+46-76-7662612/+46-18-673537
E-mail: tord.sn...@ekol.slu.se
www.ekol.slu.se/staff
esire for an answer does not ensure
that a reasonable answer can be extracted from a given body of data.
~ John Tukey
-Oorspronkelijk bericht-
Van: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] Namens Tord Snäll
Verzonden: vrijdag 14 november 2008 12:14
Aan: r-sig-geo@stat.math.ethz.ch
Onde
Dear all,
I would like legend cut-offs that are prettier that just executing
spplot(SpatialPolygonsDataFrame(karta,
as.data.frame(resdf[,c("TempEst.t","TempEst.tM1")])))
I try
spplot(SpatialPolygonsDataFrame(karta,
as.data.frame(resdf[,c("TempEst.t","TempEst.tM1")])),at=pretty())
, though wit
