Re: Source of Ge crystal for monochromator

1999-05-26 Thread Michael Tovar
> In the process of coupling one of our diffractometers with a rotating > anode X-ray source I find I need to buy a new monochromator crystal, and > collimation slits controllable in size from 1mm to 10 micron. I am > asking the pooled experience represented here for any suggestions on > wher

SiC

1999-05-26 Thread Angel Luis Ortiz Seco
Dear all, I am very interested in doing refinaments by using Rietveld method in SiC obtained by sol-gel. Howerver, I need some information about this method of processing. Could anyone tell me where I can find some referents?. Thanks you very much.

Conversion of VMS data into DOS

1999-05-26 Thread Paz Vaqueiro Rodriguez
Hi, I have some Polaris data which I have been using with VMS GSAS, but I wanted to use chemical constrains so I transferred the data (as an ASCII file) to a PC. I tranferred two datasets: xray and neutrons, and PC GSAS reads (and refines) successfully the xray dataset. I can plot the neutron da

Sol-gel SiC

1999-05-26 Thread Angel Luis Ortiz Seco
Dear all, I would like to know some referents about sol-gel applied to SiC. Could anyone help me? Thanks you very much.

Source of Ge crystal for monochromator

1999-05-26 Thread Yokochi, Alexandre
Hello everyone, In the process of coupling one of our diffractometers with a rotating anode X-ray source I find I need to buy a new monochromator crystal, and collimation slits controllable in size from 1mm to 10 micron. I am asking the pooled experience represented here for any sugge

Re: [RE: Combined neutron/x-ray refinements]

1999-05-26 Thread Andrew Wills
OK, so iff the structure can be properly described by both datasets, the main problem that we have is what to do with the esd's and chi**2. It seems that the best thing is for the refinement software to give individual values for each refinement and then an overall value (perhaps rescaled). At

RE: Combined neutron/x-ray refinements

1999-05-26 Thread P . G . Radaelli
Well, it looks like my "feeling" might have been wrong this time. The way you may want to go through the "tedious" proof is the following. 1) You construct the Aij matrix (also sometimes called the Hessian matrix) Aij=D^2chi^2/DxiDxj (D is the partial derivative sign. E-mail is