On Fri, May 24, 2013 at 10:33 AM, Paul Julian wrote:
> a = [1,2,3,4,5,6,7,8,9,10]
> b= a.reverse.reverse
Can't tell if you are trolling or if you think that's actually a good
idea. How about just doing:
a = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
b = a.dup
>
> On Friday, May 24, 2013 9:56:39 AM UTC-4,
a = [1,2,3,4,5,6,7,8,9,10]
b= a.reverse.reverse
On Friday, May 24, 2013 9:56:39 AM UTC-4, Ruby-Forum.com User wrote:
>
> a = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
> b = a + [nil]
> p a #=> [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
> p b #=> [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, nil]
>
> Is there any other Rubyist w
On 24 May 2013 16:20, Love U Ruby wrote:
> Colin Law wrote in post #1110051:
>> On 24 May 2013 14:56, Love U Ruby wrote:
>>> a = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
>>> b = a + [nil]
>>> p a #=> [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
>>> p b #=> [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, nil]
>>>
>>> Is there any othe
Colin Law wrote in post #1110051:
> On 24 May 2013 14:56, Love U Ruby wrote:
>> a = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
>> b = a + [nil]
>> p a #=> [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
>> p b #=> [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, nil]
>>
>> Is there any other Rubyist way to get the `b` array from `a` array?
4 matches
Mail list logo
