Hola,
Am I missing something or is this behavior rather peculiar:
sage: bool(sin(x) == sin(x+2*pi))
True
...however:
plot(sin(x) - sin(x+2*pi))
gives out the result:
http://aleph.sagemath.org/?c=plot%28sin%28%282%2Api%29+%2B+x%29+-+sin%28x%29%2C-100%2C100%29
2012-04-22 14:39, Duc Trung Ha skrev:
Am I missing something or is this behavior rather peculiar:
sage: bool(sin(x) == sin(x+2*pi))
True
...however:
plot(sin(x) - sin(x+2*pi))
gives out the result:
[plot showing inaccuracies of floats]
I typed this instead, and got a nice line at 0:
Thanks a lot for an explanatory reply :-)
Unfortunately I still have some comments...
I typed this instead, and got a nice line at 0:
plot(simplify(sin((2*pi) + x) - sin(x)),-100,100)
This is not working for a little bit more complicated arguments, for
instance, the second sin(x/pi)
On Sun, Apr 22, 2012 at 11:26 AM, DigDug_the_2nd
dugthemath...@gmail.com wrote:
I installed Sage on an Ubuntu 10 VM using a prebuilt binary, and it
installed it in its own environment under a folder called sage-4.8
I know this is a nice feature in general, but the problem is that my VM
already
Sage version 4.6.1 (I know it's old, new one is downloading now, but I
don't think this is a version problem.)
Given: polynomial f in x with some letters for the coefficients, and
polynomial psi of lower degree in x with constant coefficients.
Wanted: remainder of f on division by psi as
On Apr 22, 2012, at 13:23 , Michael Beeson wrote:
Sage version 4.6.1 (I know it's old, new one is downloading now, but I
don't think this is a version problem.)
Given: polynomial f in x with some letters for the coefficients, and
polynomial psi of lower degree in x with constant
Because you divided by x in your computation, the polynomial f was coerced
into the fraction field. In the fraction field, quotient is always possible
without reminder:
sage: f.parent()
Fraction Field of Multivariate Polynomial Ring in x, N, p, r, m, l over
Rational Field
You want to convert
