On Tue, Nov 18, 2008 at 7:43 PM, John H Palmieri <[EMAIL PROTECTED]> wrote:
>
> Thanks for the answers. By the way:
>
>> Infinite fields of characteristic p aren't perfect,
>
> Isn't the algebraic closure of F_p perfect? For fields of
> characteristic p, perfect should mean that every element ha
Thanks for the answers. By the way:
> Infinite fields of characteristic p aren't perfect,
Isn't the algebraic closure of F_p perfect? For fields of
characteristic p, perfect should mean that every element has a pth
root. (I agree that some infinite fields of characteristic p aren't
perfect, b
On Tue, Nov 18, 2008 at 4:30 PM, John H Palmieri <[EMAIL PROTECTED]> wrote:
>
> Does Sage know how to compute pth roots in any finite field of
> characteristic p?
There exists a finite field of char p such that Sage can compute
the p-th roots of a number:
sage: a = GF(7)(2)
sage: a.nth_root(7)
2
