Hi
What is the most elegant way of performing a SELECT DISTINCT on a
single column at the ORM level on SQLAlchemy 0.4.6?
It looks like you can do
q=session.query(Order.support_manager).distinct() in the beta
version. This is not supported in 0.4.6 though.
Thanks in advance
Best regards
Jon
Yes it appears to be a pyodbc problem, which is a shame because it's
making debugging my project incredibly difficult (and I've had even
more problems with the other MS SQL libraries like pymssql).
The bug report is here:
Done - I really hope we can get this fixed because sqlalchemy and
TurboGears is incredibly difficult to use with MS SQL Server at the
moment. I think I may be able to improve sqlalchemy if I can get the
errors propogating properly
Cheers
Jon
I have just started using Python and TurboGears with SQLAlchemy and I
think its great so far. I am working with an already-created database
and am wondering what the best way is to represent the relationships
between the recurring_task and employee_status table:
employee_statuses =
On 4 Jul, 18:03, jrpfinch [EMAIL PROTECTED] wrote:
I have just started using Python and TurboGears with SQLAlchemy and I
think its great so far. I am working with an already-created database
and am wondering what the best way is to represent the relationships
between the recurring_task
