Thank you very much .
aliased (TreeNode, row_expression) was exactly what I was looking for.
Never noticed that before.
On Tuesday, November 10, 2020 at 12:51:30 PM UTC-8 Mike Bayer wrote:
> I would need to see the table defs for "docorder" to do this completely.
>
> The parents + kids
I would need to see the table defs for "docorder" to do this completely.
The parents + kids version:
# 1. make parents cte
parents_cte = session.query(TreeNode).filter(TreeNode.name ==
"subnode4").cte("parents", recursive=True)
p2 = session.query(TreeNode).filter(TreeNode.id ==
A more complete version of the SQL to be returned as TreeNode
WITH RECURSIVE
docorder AS ( select id, rn from ...),
parents AS
(SELECT tree.id AS id, tree.parent_id AS parent_id, tree.name AS name
FROM tree
WHERE tree.name = 'subnode4'
UNION SELECT tree.id AS tree_id, tree.parent_id
I really appreciate the help.. I've been stuck a while on this.
I am including the SQL string which may help, but to elaborate
I would like to receive ORM objects that I can further operate on.
>From above, the line
print session.query(parents).all()
prints
[(9, 7,
do you know what SQL string you want? I can do this quickly if you can
send me the exact string.
On Tue, Nov 10, 2020, at 1:40 PM, kris wrote:
> The example is from adjecency_list.py example.
>
> The last three lines construct a recursive CTE to walk to the parent from a
> found
The example is from adjecency_list.py example.
The last three lines construct a recursive CTE to walk to the parent from
a found node.
I cannot figure out how to return TreeNodes vs tuples.
Thanks
from sqlalchemy import Column
from
Please provide a working and minimal mapping of your classes in question as
well as the SQL you wish to emit.
On Tue, Nov 10, 2020, at 12:07 PM, kris wrote:
>
> A little more detail..
>
> N = alias (T)
> node1 = session.query (N).filter(initial_node_filter).cte ('parents',
> recursive =
A little more detail..
N = alias (T)
node1 = session.query (N).filter(initial_node_filter).cte ('parents',
recursive = True)
parents = topnode.union (DBSession.query(N).filter (N.id ==
node1.c.parent_id)
print session.query(parents).all()
shows an array 'result'
How to force it return
Initially I tried to remain solely in ORM constructs, I only broke down and
used the SQL expressions after hitting a wall.
A little more specifically:
when I try:
session.query (part1).all ()
I receive an array of class 'sqlalchemy.util._collections.result' while I
was expecting an
I would advise against using from_statement(). the Query object supports
cte() and subqueries directly, see the example at
https://docs.sqlalchemy.org/en/13/orm/query.html?highlight=query%20cte#sqlalchemy.orm.query.Query.cte
alternatively if you are using 1.4 beta1 then you can use
I need to query over a table mapped to class T,
I usually use session.query (T), however I am using two cte's
part0 = ... cte('part0')
part1 = ... cte('part1')
11 matches
Mail list logo
