You can do something like:
q1 = session.query(\
ContactInfo.account_id.label(q1_account_id ),
ContactInfo.other_id.label(q1_otherid )
)\
.filter(..)
q2 = session.quiery(Site.account_id.label(q2_account_id)).filter(..)
_q3 =
sidenote: there are typos. that's just to illustrate. i mostly copied
that from production code.
the core concepts are:
1. `label()` the columns
2. use the `engine` (not orm) to join the queries
3. `alias` the union to search against them
4. the labeled columns in the earlier queries are now
Thanks guys, so i got it going with the hint to use an alias.
Here is what i ended up getting to work... BUT*** i am not using the
engine.execute does .all() work.. but its not recommended because im
not having a problem whats the issue?
Here is what im doing.
q3 = union(q1,q2).cte()
q =
i think the call to alias ( making it a subquery ) dropped the support for
all in my example; though that was written in .8.1 -- might be working
since .8.3 or 9
it took me a bit of trial and error to get stuff working.
awesome that it's working for you so quickly!
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