On May 22, 2008, at 5:51 PM, Jeff Putsch wrote:
Which can give me two selects using aliases:
a1 = s.correlate(None).alias()
a2 = s.correlate(None).alias()
But every attempt at using a1 and a2 in a select with a join is
failing for me.
a1.join(a2, onclause) should do it. if not, supply
On May 22, 2008, at 3:08 PM, Michael Bayer wrote:
a1.join(a2, onclause) should do it. if not, supply a full test case
and a description of the specific problem.
OK, I guess. So how do I see the SQL that gets generated?
I've tried this:
print select(from_obj=[a1.join(a2), a1.c.eid ==
I apologize for this second, longer, more detailed, post, but I
thought my first response
to the request for more descriptions was incomplete...
On May 22, 3:08 pm, Michael Bayer [EMAIL PROTECTED] wrote:
a1.join(a2, onclause) should do it. if not, supply a full test case
and a description
