;page"
= a series of unknown bytes.
The data string "pageup" satisfies the last two requirements but not
the
first. Therefore you do not return a row. Solution = use "LIKE 'page%'
At 09:14 PM 5/15/04 +0200, you wrote:
Sascha,
On 15 may 2004, at 10:48, Sascha Kueh
query to map my database, I get the expected
rows. In my case I write the following:
SELECT * FROM address WHERE last LIKE '%iur%'
Works fine for me...
Please give me more info: what OS are you using? SQLite version?
Regards,
-- Tito
On 15 may 2004, at 15:14, Sascha Kuehn wrote:
Sascha,
Sascha,
On 15 may 2004, at 10:48, Sascha Kuehn wrote:
here is my selectstatement: "SELECT * FROM WorkBook WHERE name LIKE
'%page%'"
the workbook table contains several rows where "name" contains
"pageup" and i want to get only this rows. but the selectst
is rows.
but the selectstatement doesn't work.
can somebody help me?
thanx in advance
sincerely yours
Sascha Kuehn
Applescript Developer
www.nullify.de/nullifySoftware/en/
4 matches
Mail list logo