David A O L wrote:
Im using 3.3.13, I will like if you can show a little snipped of how
to go
with something like the next..
(The following at sqlite prompt)
create table some(xthing varchar, count integer);
insert into some values("hi", 0);
insert into some values("hi there", 0);
update some
Use sqlite3_libversion(). See
http://www.sqlite.org/capi3ref.html#sqlite3_libversion for details.
Im using 3.3.13, I will like if you can show a little snipped of how to go
with something like the next..
(The following at sqlite prompt)
create table some(xthing varchar, count integer);
insert i
David A O L wrote:
That mean Im using sqlite version 2?? (Because it say database locked).
Like I know I have here sqlite3 I will search the way to print the
version
of the library used...
David,
Use sqlite3_libversion(). See
http://www.sqlite.org/capi3ref.html#sqlite3_libversion for deta
What I whant is that in // Here! I whant to update (increment, decrement,
> etc).
>
> But it say that the DB is locked...
With sqlite v2, yes. If you were using sqlite v3 you could do the
UPDATE in the SELECT callback.
That mean Im using sqlite version 2?? (Because it say database locked).
Like
On Thu, 2007-04-19 at 13:29 -0500, David A O L wrote:
> I have a very basic sql statement, mainly Im printing it...
>
> static int GuardaActividadEnArchivo(void *arg1, int argc, char **argv, char
> **azColName){
> int i;
> char *nombre, *ok, *ko, *actividad;
> nombre = ok = ko = activi
I have a very basic sql statement, mainly Im printing it...
static int GuardaActividadEnArchivo(void *arg1, int argc, char **argv, char
**azColName){
int i;
char *nombre, *ok, *ko, *actividad;
nombre = ok = ko = actividad = 0;
for (i = 0; i < argc; i++) {
printf("%s = %s ", azC
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