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Comment #3 on issue 2684 by ronan.l...@gmail.com: Deepcopy does not work on
evaluate False
http://code.google.com/p/sympy/issues/detail?id=2684
Actually, __reduce__ and __reduce_ex__ bypass the standard pickling and
copy protocols, so it would be nicer to avoid using them. However,
Comment #13 on issue 1336 by smi...@gmail.com: Arbitrary constant type
http://code.google.com/p/sympy/issues/detail?id=1336
I don't have a special combining symbol but I have a 'model' function that
absorbs all constants except for a specified 'x'. Using it on the examples
of the OP shows
Comment #14 on issue 1336 by smi...@gmail.com: Arbitrary constant type
http://code.google.com/p/sympy/issues/detail?id=1336
I moved this to the model branch.
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Comment #2 on issue 2654 by someb...@bluewin.ch: lambdify() does not
convert abs()
http://code.google.com/p/sympy/issues/detail?id=2654
It's not just adding a translation because the numpy abs ufunc is not
per default imported by
from numpy import *
we have to explicitely
from numpy
Hi,
I was browsing the code in residue_ntherory.py and found that in SymPy,
legendre_symbol can have only two values { -1, 1 } out of the possible set {
-1, 0, 1} [0].
I made the necessary change ( changed 'if' condition) and added a test for
the same [1] but haven't made a pull request yet.
See issue 1336 for an update on this.
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On Fri, Sep 16, 2011 at 1:14 AM, Hector hector1...@gmail.com wrote:
Hi,
I was browsing the code in residue_ntherory.py and found that in SymPy,
legendre_symbol can have only two values { -1, 1 } out of the possible set {
-1, 0, 1} [0].
I made the necessary change ( changed 'if' condition)
instead of `a%p` write `a % p`. Also, since this will have to be
computed again later you might as well do both at the same time:
a, r = divmod(a, p)
if not r:
return 0
if is_quad_residue(a, p):
return 1
else:
return -1
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On Fri, Sep 16, 2011 at 3:19 AM, Hector hector1...@gmail.com wrote:
On Fri, Sep 16, 2011 at 2:40 AM, Chris Smith smi...@gmail.com wrote:
instead of `a%p` write `a % p`. Also, since this will have to be
computed again later you might as well do both at the same time:
a, r = divmod(a, p)
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