I was going through the Sympy tutorial... Its given that Eq(x + 1, 4) gives
the symbolic output as :
x + 1 == 4
But when I run the given code snippet in my terminal or in the Sympy Live
Shell, it gives me the output as :
x + 1 = 4
Is this just a typo or a genuine erro
In SymPy 0.7.6.1 I'm getting:
Python 3.5.1 |Continuum Analytics, Inc.| (default, Dec 7 2015, 11:16:01)
Type "copyright", "credits" or "license" for more information.
IPython 4.0.1 -- An enhanced Interactive Python.
? -> Introduction and overview of IPython's features.
%quickref -> Quick
FYI, this is the last day to get a matching donation to NumFocus which
supports SymPy as the fiscal sponsor. You can specifically earmark your
donation to SymPy.
Jason
moorepants.info
+01 530-601-9791
-- Forwarded message --
From: NumFOCUS
Date: Thu, Dec 31, 2015 at 6:54 AM
Subje
I've just started learning Sympy. I wrote a few lines of code to perform a
inverse laplace transform on a simple 2nd order transfunction:
H(s) = 1 / ((s+p1) * (s+p2)).
The result I got from Sympy is
(e^(p1*t) - e^(p2*t))*e^-t*(p1+p2) / (p1 - p2)
Is there a way to simplify this result to the on
Hello.
Have you triez to expand 1nd then to factorize the formula ?
Le 1 janv. 2016 03:42, "Ken" a écrit :
> I've just started learning Sympy. I wrote a few lines of code to perform a
> inverse laplace transform on a simple 2nd order transfunction:
>
> H(s) = 1 / ((s+p1) * (s+p2)).
>
> The resul
