Re: [sympy] [GSOC 2012] Order term Arithmetic

2012-03-22 Thread Aaron Meurer
As discussed on IRC, I don't know what the references are. You could do a search. Or maybe someone else here will know. I think the issue might just be to complete the square, cube, ... so that the series terms are all in terms of (x - a) instead of just x. Then, you can correctly write O((x -

Re: [sympy] [GSOC 2012] Order term Arithmetic

2012-03-22 Thread Alexey U. Gudchenko
22.03.2012 09:33, Sai Nikhil пишет: currently if we are calculating the series for a function ( eg., sin(x).series(x,x0=2,n=6) ) about a point x0 = a , where a != 0 , then we are getting the expression of f(x+a) (i.e., sin(x+2).series(x,x0=0,n=6)) about x0 = 0 , as there is no proper

Re: [sympy] [GSOC 2012] Order term Arithmetic

2012-03-22 Thread Alexey U. Gudchenko
22.03.2012 09:33, Sai Nikhil пишет: currently if we are calculating the series for a function ( eg., sin(x).series(x,x0=2,n=6) ) about a point x0 = a , where a != 0 , then we are getting the expression of f(x+a) (i.e., sin(x+2).series(x,x0=0,n=6)) about x0 = 0 , as there is no proper

[sympy] [GSOC 2012] Order term Arithmetic

2012-03-21 Thread Sai Nikhil
currently if we are calculating the series for a function ( eg., sin(x).series(x,x0=2,n=6) ) about a point x0 = a , where a != 0 , then we are getting the expression of f(x+a) (i.e., sin(x+2).series(x,x0=0,n=6)) about x0 = 0 , as there is no proper support for Order term Arithmetic in sympy . I