Hello,
Has work has been done on modular reduction of `RootOf` objects? (If not, I
would like to begin implementing this functionality!) What I mean is this:
import sympy
from sympy.abc import x
f = x**3 + 2*x + 1
a = sympy.RootOf(f,0)
b = a**3
Since $f(a) = 0$ by definition it would be nice
On Wed, Nov 26, 2014 at 11:31 AM, Chris Swierczewski cswie...@gmail.com wrote:
Hello,
Has work has been done on modular reduction of `RootOf` objects? (If not, I
would like to begin implementing this functionality!) What I mean is this:
import sympy
from sympy.abc import x
f = x**3 + 2*x +
Hello,
Thanks for the quick response!
This is what I get:
...
So looks like it hasn't been implemented yet.
Right on. I'll start poking around, then.
Good question. First, I would implement RootOf.mypow(n) and see if you
can figure out how to get the answer you want. That's the hard part.
Hi Chris,
On Wed, Nov 26, 2014 at 11:56 AM, Chris Swierczewski cswie...@gmail.com wrote:
Hello,
Thanks for the quick response!
This is what I get:
...
So looks like it hasn't been implemented yet.
Right on. I'll start poking around, then.
Good question. First, I would implement
There's a decent chance this algorithm is already implemented and just
not integrated into the RootOf object, so I would search around the
polys code first.
Aaron Meurer
On Wed, Nov 26, 2014 at 12:17 PM, Ondřej Čertík ondrej.cer...@gmail.com wrote:
Hi Chris,
On Wed, Nov 26, 2014 at 11:56 AM,
Hello Aaron,
There's a decent chance this algorithm is already implemented and just
not integrated into the RootOf object, so I would search around the
polys code first.
Thanks for the tip. I've been getting to know the `rem()` and `reduce()`
functions a little more. From what I've seen so
