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Comment #5 on issue 1889 by ronan.l...@gmail.com: sympify gives an error
when a symbol 'C' is used together with a local dictionary
http://code.google.com/p/sympy/issues/detail?id=1889
It's in.
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Comment #4 on issue 1889 by Vinzent.Steinberg: sympify gives an error when
a symbol 'C' is used together with a local dictionary
http://code.google.com/p/sympy/issues/detail?id=1889
Thanks, this looks fine to me. I'll wait some tim
Comment #3 on issue 1889 by chr.schu...@gmx.de: sympify gives an error when
a symbol 'C' is used together with a local dictionary
http://code.google.com/p/sympy/issues/detail?id=1889
I finally got around to finding the problem.
It seems that global_dict and local_dict were mixed up in a call
Comment #2 on issue 1889 by asmeurer: sympify gives an error when a
symbol 'C' is used together with a local dictionary
http://code.google.com/p/sympy/issues/detail?id=1889
You can override it the normal way:
In [6]: C = Symbol('C')
In [8]: C*2
Out[8]: 2⋅C
Should we fix this to return a Sy
Comment #1 on issue 1889 by smichr: sympify gives an error when a
symbol 'C' is used together with a local dictionary
http://code.google.com/p/sympy/issues/detail?id=1889
The single letters in "COSINEQ" are classes in sympy. Although I would have
expected
your defining of vars['C'] to have
Status: New
Owner:
Labels: Type-Defect Priority-Medium
New issue 1889 by chr.schu...@gmx.de: sympify gives an error when a
symbol 'C' is used together with a local dictionary
http://code.google.com/p/sympy/issues/detail?id=1889
Hi,
I keep on getting errors when I try to sympify 'C*2' us
