Please could somebody on the eat your CAS whether you like it or not
side of the fence explain why the following idea would not work:
On Sat, 13 Nov 2010, der Mouse wrote:
Consider this hypothetical:
x86 does #define ATOMIC_OPS_USE_CAS and defines a CAS(); MI code
notices this and defines
On Tue, Nov 16, 2010 at 09:44:18AM -0800, Matt Thomas wrote:
On Nov 16, 2010, at 9:10 AM, Alan Barrett wrote:
Please could somebody on the eat your CAS whether you like it or not
side of the fence explain why the following idea would not work:
On Sat, 13 Nov 2010, der Mouse wrote:
On 2010-11-16 18:44, Matt Thomas wrote:
On Nov 16, 2010, at 9:10 AM, Alan Barrett wrote:
Please could somebody on the eat your CAS whether you like it or not
side of the fence explain why the following idea would not work:
On Sat, 13 Nov 2010, der Mouse wrote:
Consider this hypothetical:
On 2010-11-16 19:32, Eric Haszlakiewicz wrote:
On Tue, Nov 16, 2010 at 09:44:18AM -0800, Matt Thomas wrote:
On Nov 16, 2010, at 9:10 AM, Alan Barrett wrote:
Please could somebody on the eat your CAS whether you like it or not
side of the fence explain why the following idea would not work:
On
hi,
On 2010-11-16 19:32, Eric Haszlakiewicz wrote:
On Tue, Nov 16, 2010 at 09:44:18AM -0800, Matt Thomas wrote:
On Nov 16, 2010, at 9:10 AM, Alan Barrett wrote:
Please could somebody on the eat your CAS whether you like it or not
side of the fence explain why the following idea would not
FWIW, there *are* sparc implementations of the mutex vector
functions, but we had to disable them because of lossage we
we not able to (yet) track down. they mostly work, so may
be useful for at least reading.
.mrg.
On Nov 16, 2010, at 7:32 PM, Johnny Billquist wrote:
On 2010-11-17 04:25, matthew green wrote:
The (my) problem is that rwlocks must use CAS as well, and I'm starting
to think that I have to use CAS for the mutex code as well, as I can't
seem to get mutexs work reliably without using the
- hppa seems to have a mutex implemented without cas. is it broken?
FWIW, the sparc implementation is only broken on SMP.
.mrg.
On Nov 16, 2010, at 8:04 PM, Johnny Billquist wrote:
On 2010-11-17 04:52, Matt Thomas wrote:
Not true. Spinlocks must enter through mutex_spin_enter and adaptive mutexes
enter through mutex_enter. The corresponding is true for exiting as well.
The only reason mutex_vector_{enter,exit} is
