Hi, I am trying to simply create an SQLite database with Python. I find
that when I try to create a new database file, *sometimes* it lets me do it,
and sometimes it doesn't, and the only thing I am changing is the name of
the database. I am baffled as to why some names appear to work and
Dear Tutors!
I know a python list is a mutable object.
array = [1,2,3,4,5]
So I can modify any item in it.
for index in range(len(array)): array[index] *= 2
...
array
[2, 4, 6, 8, 10]
So I typed this:
for item in array: item *= 2
...
array
[1, 2, 3, 4, 5]
It confused me a little, so
János Juhász [EMAIL PROTECTED] wrote
So I can modify any item in it.
for index in range(len(array)): array[index] *= 2
...
array
[2, 4, 6, 8, 10]
So I typed this:
for item in array: item *= 2
This is equivalent to
index = 0
while index len(array):
item = array[index] #
Che M [EMAIL PROTECTED] wrote
don't. For example, this will create a brand new database on the
desktop:
conn = sqlite3.connect('C:\Documents and
Settings\user\Desktop\mydatabase.db')
But running *this*--only thing different is the database's
name--gives the
error, as shown:
conn =
Che M schreef:
Hi, I am trying to simply create an SQLite database with Python. I find
that when I try to create a new database file, *sometimes* it lets me do it,
and sometimes it doesn't, and the only thing I am changing is the name of
the database. I am baffled as to why some names
Hello tutors,
I am trying to understand the best cases in which to use for loops, list
comprehensions, generators, and iterators. I have a rather simple process that
I made initially as a for loop:
self.potdomains = []
for word in self.dictcontents:
wormwood_3 wrote:
Hello tutors,
I am trying to understand the best cases in which to use for loops,
list comprehensions, generators, and iterators. I have a rather simple
process that I made initially as a for loop:
self.potdomains = []
for word in self.dictcontents:
I think what you have is pretty clear. I can't think of a way to do this
with a single list comprehension because you add two items to the list
each time through the loop. You could use a list comp and a generator
expression, but the order of entries in the result will be different:
Tim Michelsen wrote:
How nice that the SWC gets updated and improved!
I heard from Chris Lasher at the SWC Sprint on Saturday. Turns out there
is a bug collector for SWC and this bug has been documented for some time:
http://projects.scipy.org/swc/ticket/88
Chris reported, Will have this
János Juhász wrote:
Dear Tutors!
I know a python list is a mutable object.
array = [1,2,3,4,5]
So I can modify any item in it.
for index in range(len(array)): array[index] *= 2
...
array
[2, 4, 6, 8, 10]
So I typed this:
for item in array: item *= 2
...
array
[1, 2, 3, 4, 5]
It also seems fair to do the following (if the modified list is to be used
more than once - to avoid building the modified list more than once)?
array = [item*2 for item in array] # instead of for item in array: item
*= 2
Regards,
Trilok
-Original Message-
From: [EMAIL PROTECTED]
ok, I installed XLRD and can load a xls file; it works quite well BTW. Now
it is returning Unicode objects. I need to strip that to a simple string
value. Is there a recommended way or module for handling Unicode objects?
Kirk Bailey wrote:
Ii want to read a xls file and use the data in part
Thank you Alan and Roel for the insight, and Roel thank you for all the
suggested ways to get around it. It's always nice when something goes from
making no sense to making complete sense in a snap.
Che
_
Booking a flight? Know
Noufal Ibrahim wrote:
János Juhász wrote:
Dear Tutors!
I know a python list is a mutable object.
array = [1,2,3,4,5]
So I can modify any item in it.
for index in range(len(array)): array[index] *= 2
...
array
[2, 4, 6, 8, 10]
So I typed this:
for item in array: item *= 2
...
array
Kirk Bailey wrote:
ok, I installed XLRD and can load a xls file; it works quite well BTW. Now
it is returning Unicode objects. I need to strip that to a simple string
value. Is there a recommended way or module for handling Unicode objects?
What kind of characters are in the Excel file? What
On Mon, Aug 20, 2007 at 03:14:24PM -0300, Ricardo Ar?oz wrote:
[snip]
You just work on a generated modified list.
foo = range(1,6)
for i in [x*2 for x in foo]:
do_whatever_you_want_with(i)
What about :
array = [1,2,3,4,5]
array = [i * 2 for i in array]
Good solution.
Dave Kuhlman wrote:
Consider the following:
array = [1,2,3,4,5]
array2 = array
array = [i * 2 for i in array]
array
[2, 4, 6, 8, 10]
array2
[1, 2, 3, 4, 5]
So, did you want array2 to change, or not?
Here is a solution that changes the object that
Kent Johnson wrote:
Dave Kuhlman wrote:
Consider the following:
array = [1,2,3,4,5]
array2 = array
array = [i * 2 for i in array]
array
[2, 4, 6, 8, 10]
array2
[1, 2, 3, 4, 5]
So, did you want array2 to change, or not?
Here is a solution that changes
I ran a few tests, with the following results:
1. Timing using the time module:
* Using for loop, src code:
import time
start = time.time()
for word in self.dictcontents:
self.potdomains.append(word +
wormwood_3 wrote:
I ran a few tests, with the following results:
1. Timing using the time module:
* Using for loop, src code:
import time
start = time.time()
for word in self.dictcontents:
I've got a 2D list (essentially a list of lists where all sublists are of
the same length). The sublists are polymorphic. One 2D list I commonly
work with is:
[ [datetime object, float, int, float],
[datetime object, float, int, float],
[datetime object, float, int, float] ]
I'd like to be
This looks like a job for List Comprehensions!
list = [[1, 2, 3], [4, 5, 6], [7, 8, 9]]
new_list = [item[1] for item in list]
new_list
[2, 5, 8]
looks good?
Ian
On 8/21/07, Orest Kozyar [EMAIL PROTECTED] wrote:
I've got a 2D list (essentially a list of lists where all sublists are
of
I have a particular date time format I use for making entries in various
logs I maintain, and ideally what I'd like is for my operating system
(Windows or Linux) to recognize that every time I type, say, Ctrl-'C' '1',
a Python script I wrote will execute and out will pop the current date time
in
23 matches
Mail list logo
