On Wed, Oct 5, 2011 at 1:42 PM, Dave Angel wrote:
> On 10/04/2011 11:13 PM, lina wrote:
>
>> On Wed, Oct 5, 2011 at 10:45 AM, Dave Angel wrote:
>>
>> On 10/04/2011 10:22 PM, lina wrote:
>>>
>>> On Wed, Oct 5, 2011 at 1:30 AM, Prasad, Ramit>>> *com
> w
>
>>>
SyntaxError:
On 10/01/2011 03:53 PM, R. Alan Monroe wrote:
You missed the rest of the paragraph. Don't wait for the sort to
finish, you do the swapping in the compare function.
Either I'm too dumb to understand your answer, or explained my
original problem too poorly.
Have you ever played the Rush Hour
On 2011-10-05 05:13, lina wrote:
$ python3 counter-vertically.py
^^^
File "counter-vertically.py", line 20
print item
^
SyntaxError: invalid syntax
In Python 3 print is a function: print(item)
In another message in this thread you've said:
"Sorry, I am still lac
On 10/04/2011 11:13 PM, lina wrote:
On Wed, Oct 5, 2011 at 10:45 AM, Dave Angel wrote:
On 10/04/2011 10:22 PM, lina wrote:
On Wed, Oct 5, 2011 at 1:30 AM, Prasad,
Ramit
w
SyntaxError: invalid syntax
for fileName in os.listdir("."):
if os.path.isfile(fileName) and os.path.splitext(
On Wed, Oct 5, 2011 at 10:45 AM, Dave Angel wrote:
> On 10/04/2011 10:22 PM, lina wrote:
>
>> On Wed, Oct 5, 2011 at 1:30 AM, Prasad,
>> Ramit
>> >wrote:
>>
>> But I still don't know how to get the
statistic result of each column,
>>> Thanks.
>>> try:
>>>cols = len( text[0] ) # Fi
On 10/04/2011 10:22 PM, lina wrote:
On Wed, Oct 5, 2011 at 1:30 AM, Prasad, Ramitwrote:
But I still don't know how to get the
statistic result of each column,
Thanks.
try:
cols = len( text[0] ) # Find out how many columns there are (assuming
each row has the same number of columns)
except
On Wed, Oct 5, 2011 at 1:30 AM, Prasad, Ramit wrote:
> >But I still don't know how to get the
> >statistic result of each column,
>
> Thanks.
>
> try:
>cols = len( text[0] ) # Find out how many columns there are (assuming
> each row has the same number of columns)
> except IndexError:
>ra
Please always reply-all so a copy goes to the list. I'm forwarding this
one for you.
Please answer ALL questions that we ask. You did not answer
What do you mean by "all other strings"?
On 10/4/2011 4:55 PM, Christopher King wrote:
This is (to me) vague. What do you mean by "at the top"
On 04/10/11 18:09, lina wrote:
But I still don't know how to get the
statistic result of each column,
Let's ignore the traversal of files issue for now.
Let's look at processing one file:
You want a list of totals of equal length to the number of columns.
We can find that number using len(line
On 04/10/11 17:38, lina wrote:
For file:
aaEbb
aEEbb
EaEbb
EaEbE
the expected output is
2 1 0 1
I expected
2 1 4 0 1
In the first column there is 2 E, so the output is 2 E, second column is
1 E.
But the 3rd is all E so why miss out the 4?
I'm still confused - and I thought I was gettin
Hi,
I'm a beginner at Python and I'm trying to extract some information from a
textfile where I have a lot of data.
The table looks something like this, but with many more columns and rows:
# chr Pos ID REFALT . . . . . . . . . . .
1 13645 -
>I was wondering if anyone could tell me why threading was depreciated; and
>give me a use case for the >multiprocessing : Queue function in python 2.7.
Threading was *not* deprecated Python 2.x or 3.x
http://docs.python.org/dev/py3k/library/threading.html?highlight=threading#threading
http://
I was wondering if anyone could tell me why threading was depreciated; and
give me a use case for the multiprocessing : Queue function in python 2.7.
Thanks,
-earnest
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On 10/04/2011 01:09 PM, lina wrote:
But I still don't know how to get the
statistic result of each column,
Thanks for further suggestions,
Best regards,
lina
As I said before, your current code counts across a line at a time,
while you need to count vertically. That could be done by transpo
>But I still don't know how to get the
>statistic result of each column,
try:
cols = len( text[0] ) # Find out how many columns there are (assuming each
row has the same number of columns)
except IndexError:
raise # This will make sure you can see the error while developing;
But I still don't know how to get the
statistic result of each column,
Thanks for further suggestions,
Best regards,
lina
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On Wed, Oct 5, 2011 at 12:59 AM, Marc Tompkins wrote:
> On Tue, Oct 4, 2011 at 8:48 AM, lina wrote:
>
>> if os.path.isfile(fileName) and os.path.splitext(fileName)[1]==".xpm":
>> filedata = open(fileName)
>> text=filedata.readlines()
>> for line in text[0:]:
>>
On Tue, Oct 4, 2011 at 8:48 AM, lina wrote:
> if os.path.isfile(fileName) and os.path.splitext(fileName)[1]==".xpm":
> filedata = open(fileName)
> text=filedata.readlines()
> for line in text[0:]:
> result.append({t:line.strip().count(t) for t in tokens})
>
For file:
aaEbb
aEEbb
EaEbb
EaEbE
the expected output is
2 1 0 1
In the first column there is 2 E, so the output is 2 E, second column is 1
E.
#!/bin/python
import os.path
tokens=['B','E']
for fileName in os.listdir("."):
result=[]
if os.path.isfile(fileName) and os.path.splitext(f
On Wed, Oct 5, 2011 at 12:26 AM, Dave Angel wrote:
> On 10/04/2011 12:01 PM, bob gailer wrote:
>
>> On 10/4/2011 10:07 AM, lina wrote:
>>
>>> want to do a statistic of the concurrence of E,
>>>
>>>namely,
>>>how many times the E showed up,
>>>
>>>so the first column is 1, second colum
On 10/04/2011 10:26 AM, lina wrote:
On Thu, Sep 29, 2011 at 11:28 PM, Dave Angel wrote:
(Please don't top-post. Put your remarks AFTER the part you're quoting
from the previous message)
On 09/29/2011 10:55 AM, lina wrote:
import os.path
tokens=['E']
result=[]
for fileName in os.listdir(
On 10/04/2011 12:01 PM, bob gailer wrote:
On 10/4/2011 10:07 AM, lina wrote:
want to do a statistic of the concurrence of E,
namely,
how many times the E showed up,
so the first column is 1, second column and then following.
Thanks,
I have one, which showed something like
On 10/4/2011 10:07 AM, lina wrote:
want to do a statistic of the concurrence of E,
namely,
how many times the E showed up,
so the first column is 1, second column and then following.
Thanks,
I have one, which showed something like:
tokens=['E']
result=[]
fi
On Tue, Oct 4, 2011 at 11:27 PM, Dave Angel wrote:
> On 10/04/2011 10:26 AM, lina wrote:
>
>> On Thu, Sep 29, 2011 at 11:28 PM, Dave Angel wrote:
>>
>> (Please don't top-post. Put your remarks AFTER the part you're quoting
>>> from the previous message)
>>>
>>>
>>> On 09/29/2011 10:55 AM, lina
On Thu, Sep 29, 2011 at 11:28 PM, Dave Angel wrote:
> (Please don't top-post. Put your remarks AFTER the part you're quoting
> from the previous message)
>
>
> On 09/29/2011 10:55 AM, lina wrote:
>
>> import os.path
>>
>> tokens=['E']
>> result=[]
>>
>> for fileName in os.listdir("."):
>> if
On Tue, Oct 4, 2011 at 10:03 PM, lina wrote:
>
>
> On Tue, Oct 4, 2011 at 8:51 PM, wrote:
>
>> I don't understand what you want
>>
>> Mayybe give expected output as well
>>
>
> want to do a statistic of the concurrence of E,
> namely,
> how many times the E showed up,
>
> so the first column is
On Tue, Oct 4, 2011 at 8:51 PM, wrote:
> I don't understand what you want
>
> Mayybe give expected output as well
>
want to do a statistic of the concurrence of E,
namely,
how many times the E showed up,
so the first column is 1, second column and then following.
Thanks,
I have one, which sho
I don't understand what you want
Mayybe give expected output as well
Sent from my Verizon Wireless BlackBerry
-Original Message-
From: lina
Sender: tutor-bounces+eire1130=gmail@python.org
Date: Tue, 4 Oct 2011 19:44:02
To: tutor
Subject: [Tutor] arrary stastic
___
Hi,
For a file with
aaE
aEE
EaE
I want to statically get the concurence of E,
such as for coloumn 1,
I wish it print a[0]=1, a[1]=1,a[2]=3.
Thanks for suggestions,
--
Best Regards,
lina
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