# skip 5
if count == 5:
continue # means "Jump back to the top of the looop"
It is the reason. You yourself have mentioned it right inside the code!
On 7 April 2013 09:40, Dave Angel wrote:
> On 04/06/2013 11:23 PM, Najam Us Saqib wrote:
>
>> Hi,
>>
>> Would you please help me by e
On 04/06/2013 11:23 PM, Najam Us Saqib wrote:
Hi,
Would you please help me by explaining that why " 5 " is skipped and not
printed in the following program?
Seems to me the comments say it pretty well. The continue statement
causes execution to continue at the while statement, which has th
On 04/06/2013 11:23 PM, Najam Us Saqib wrote:
Hi,
Would you please help me by explaining that why " 5 " is skipped and not
printed in the following program?
Seems to me the comments say it pretty well. The continue statement
causes execution to continue at the while statement, which has th
Hi,
Would you please help me by explaining that why " 5 " is skipped and not
printed in the following program?
Thank you.
Najam.
count = 0
while True:
count += 1
# end loop if count is greater than 10
if count > 10:
break # means "break out of the loop"
# skip 5
if c
On 07/04/2013 00:10, Soliman, Yasmin wrote:
To quote John McEnroe "You cannot be serious". Thankfully Steven
D'Aprano has already given you a roadmap to follow. I'll point out a
few things that should assist.
How can I fix this loop so that it multiplies the two intergers and if
user types
On 07/04/13 09:10, Soliman, Yasmin wrote:
How can I fix this loop so that it multiplies the two intergers and if user
types in 'quit' for either number it stops? if not it keeps going.
How would you solve this problem in real life? Right down the steps you would
do, as if you were explaining
On 07/04/13 08:00, Soliman, Yasmin wrote:
I have two questions on these simple programs:
1st why does this loop keep repeating after I enter 'Quit'?
The code you give below is not valid Python code. Please copy and paste *actual* the code
you use, do not retype it from memory. I know that it
How can I fix this loop so that it multiplies the two intergers and if user
types in 'quit' for either number it stops? if not it keeps going.
def multiply_integers(int1,int2):
print int1*int2
int1=float(input('Please enter 1st integer: '))
int2=float(input('Please enter 2nd integer: '))
On 06/04/2013 23:00, Soliman, Yasmin wrote:
I have two questions on these simple programs:
1st why does this loop keep repeating after I enter 'Quit'?
import calendar
m = raw_input(“Enter a year: “)
while m != “Quit”:
if calendar.isleap(int(m)):
print “%d is a leap year” % (int(m))
else:
On 04/06/2013 06:00 PM, Soliman, Yasmin wrote:
I have two questions on these simple programs:
>
> 1st why does this loop keep repeating after I enter 'Quit'?
>
> import calendar
> m = raw_input(“Enter a year: “)
> while m != “Quit”:
> if calendar.isleap(int(m)):
> print “%d is a leap year” %
I have two questions on these simple programs:
1st why does this loop keep repeating after I enter 'Quit'?
import calendar
m = raw_input(“Enter a year: “)
while m != “Quit”:
if calendar.isleap(int(m)):
print “%d is a leap year” % (int(m))
else:
print “%d is not a leap year” % (int(m))
2n
On 05/04/13 11:47, Mousumi Basu wrote:
s=socket.socket(socket.AF_INIT,socket.SCK_DGRM))
There is a double )) at the end of the line.
That should give a different error so I assume this is
not cut 'n paste code, but just in case I thought
I'd point it out...
s.bind(('172.18.2.11',8032))
Be
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