On 09/07/14 02:44, Robert Nanney wrote:
#!/usr/bin/python
#list_test2.py
list1 = [1, 8, 15]
list2 = [2, 9, 16]
list3 = [[3, 4, 5, 6], [10, 11, 12, 13], [17, 18, 19, 20]]
list4 = [7, 14, 21]
one_list = zip(list1, list2, list3, list4)
first_round = [one_list[x][y] for x in range(len(list3)) for
On 09/07/14 06:58, Alan Gauld wrote:
list1 = [1, 8, 15]
list2 = [2, 9, 16]
list3 = [[3, 4, 5, 6], [10, 11, 12, 13], [17, 18, 19, 20]]
list4 = [7, 14, 21]
I'm thinking something like
result = []
for L in (list1,list2,list3):
if isinstance(L,list)
result += L
else:
On 09.07.2014 08:16, Alan Gauld wrote:
On 09/07/14 06:58, Alan Gauld wrote:
list1 = [1, 8, 15]
list2 = [2, 9, 16]
list3 = [[3, 4, 5, 6], [10, 11, 12, 13], [17, 18, 19, 20]]
list4 = [7, 14, 21]
I'm thinking something like
result = []
for L in (list1,list2,list3):
if isinstance(L,list)
Hello All,
I have the following code. The idea is to have one list that contains
all of the items from the different iterable types and maintain the
order of the items.
Python 2.7.6 |Anaconda 2.0.0 (x86_64)| (default, May 27 2014, 14:58:54)
#!/usr/bin/python
#list_test2.py
list1 = [1, 8, 15]
