...@lists.runrev.com] On Behalf
Of hh via use-livecode
Sent: Wednesday, December 26, 2018 7:58 PM
To: use-livecode@lists.runrev.com
Cc: hh
Subject: Re: Image Remove Perimeter White Space
Here is a pure LC Script handler from one of my "early" images stacks.
For large images this may become p
Here is a pure LC Script handler from one of my "early" images stacks.
For large images this may become pretty slow...
## CROP image to opaque pixels
on cropIt ft
put the width of img ft into w; put the height of img ft into h
put the maskdata of img ft into mData
put numToByte(0) into
> Ralph wrote:
> I will just have to go pixel by pixel and check
> left, top, right and bottom sides for any non-zero
> RGB and delete rows/columns until one of the sides
> has an RGB that is not zero.
Here is a comparison value for that.
Using javascript from a hidden browser widget autocropping
Thanks All!
I was not totally clear. The area around the visible center is
transparent(not white). I need to do this invisibly in real-time without
user interaction. Luckily all the images are square so I don't have to worry
about keeping the aspect ratio intact. I will just have to go pixel by
On 12/26/18 5:13 PM, Ralph DiMola via use-livecode wrote:
I am downloading various images from a customer with varying unpredictable
amount of white space around the image. I want to make the visible center
portion images the same size. Before I start coding is there any native LC
way or
> Ralph D.wrote
> I am downloading various images from a customer with
> varying unpredictable amount of white space around the
> image. I want to make the visible center portion images
> the same size.
Assuming the white space around is symmetric, at least proportional
to width and height, you
Oh that's a pickle! Nothing native I'm sure. There is no telling from the image
itself that you want "white" to equal "overlap" at least not without a mask of
some sort. So it's going to be a pixel by pixel job, and then hope and pray
that "white" actually means "0,0,0" as opposed to "1,0,0" or
