On Wed, Nov 9, 2011 at 9:28 AM, Hans Birkeland wrote:
> Thanks for the quick reply! :)
>
> This is the query: start n=node(159178) match n-[*1..4]->x return count(*)
Good to know.
The reason you are getting duplicates is because you'll get the same node
in x multiple time - there might be a lo
Oh, and cypher supports streaming (as long as you don't sort/aggregate).
So that won't take up your memory. I would love if you could try that just
using plain java code and iterating over the node-results and provide us with
your performance numbers then.
Please make sure to run the test more
Ah sorry, I should have clarified - in the final application we will want to
retrieve the nodes. The reason we were just returning count(*) for the
tests is that returning a large number of nodes in the web console proved
less than ideal. :)
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Also, support for these heavy nodes with many relationships on them is
being worked some on so that you can get relationship count per
type/direction immediately instead of iterating over them, as well as only
loading relevant relationships instead of all.
In the meantime it would be better to kee
Thanks for the quick reply! :)
This is the query: start n=node(159178) match n-[*1..4]->x return count(*)
Hans
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Hi Hans,
First of - we have so far spent very little time so far making Cypher
awesome from a performance standpoint. Most of the energy has been put into
growing the syntax and expanding the feature set of Cypher.
The next version will hopefully involve a lot of performance work, and that
will c
Hi,
My team has been experimenting with using neo4j for dependency tracking.
For one of our scenarios we have run into performance issues and are
wondering if this is expected given the data, or if we are doing something
wrong.
Our test data consists of ~370k nodes and 4.1M relationships. Some
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