Hi there,
I am using Tomcat 7 and Cocoon 2.1.11.
Question: How do I get the directory of my application as in C:\Program
Files\Apache Software Foundation\Tomcat 7.0\webapps\myapp
I was using this call: System.getProperty(catalina.base)
But it only takes me as far as: C:\Program Files\Apache
You might want to play with javax.servlet.getRealPath() but I read some
comments that it might return null if the war is not exploded.
http://docs.oracle.com/javaee/6/api/index.html?javax/servlet/package-summary.html
-Original Message-
From: Paul Joseph [mailto:pjos...@gmail.com]
But reading your mail twice... Are you actually uploading files inside the
exploded war folder???
Not so nice in my opinion. Not sure if that is wise. Or am I misinterpreting
your use case?
Why not store/ upload the files in a configurable location?
Robby
-Original Message-
From:
Thanks much Robby...Will try the javax.servlet.getRealPath()
Yes, it is inside the exploded war folder...previously it was in a
configurable location but it turned out to be too much of a hassle--so
they decided to make it invisible.
Paul
On 9/14/2012 11:41 AM, Robby Pelssers wrote:
But
On 14 September 2012 18:19, Paul Joseph pjos...@gmail.com wrote:
Thanks much Robby...Will try the javax.servlet.getRealPath()
Yes, it is inside the exploded war folder...previously it was in a
configurable location but it turned out to be too much of a hassle--so they
decided to make it
Right...let me ask the boss.
On 9/14/2012 1:52 PM, Jasha Joachimsthal wrote:
On 14 September 2012 18:19, Paul Joseph pjos...@gmail.com
mailto:pjos...@gmail.com wrote:
Thanks much Robby...Will try the javax.servlet.getRealPath()
Yes, it is inside the exploded war
