hat should work - aggregation will happen.
Andy
Thanks,
Z
From: Andy Seaborne
Sent: Monday, November 16, 2015 5:18 PM
To: users@jena.apache.org
Subject: Re: total triples
On 16/11/15 21:00, Zen 98052 wrote:
Hi Andy,
Apologize for my lacking kn
Andy Seaborne
Sent: Monday, November 16, 2015 5:18 PM
To: users@jena.apache.org
Subject: Re: total triples
On 16/11/15 21:00, Zen 98052 wrote:
> Hi Andy,
> Apologize for my lacking knowledge on Jena codebase, I am still learning at
> slow pace.
>
> I guess the stuff in OpExecutor is
___
From: Andy Seaborne
Sent: Monday, November 9, 2015 2:50 PM
To: users@jena.apache.org
Subject: Re: total triples
On 09/11/15 18:58, Zen 98052 wrote:
Thanks Martynas!
Shouldn't it call graph's size(), which in turn calls graphBaseSize()?
Depends what "it"
0 PM
To: users@jena.apache.org
Subject: Re: total triples
On 09/11/15 18:58, Zen 98052 wrote:
> Thanks Martynas!
> Shouldn't it call graph's size(), which in turn calls graphBaseSize()?
Depends what "it" is. Have you implemented some or all of the algebra
or are you usi
na.apache.org
Subject: Re: total triples
That would only count triples in the default graph and omit triples in
named graphs. To account for them, you would need something like
SELECT (COUNT(*) AS ?no) { { ?s ?p ?o } UNION { GRAPH ?g { ?s ?p ?o } } }
On Mon, Nov 9, 2015 at 3:47 PM, Zen 98052
November 9, 2015 9:52 AM
To: users@jena.apache.org
Subject: Re: total triples
That would only count triples in the default graph and omit triples in
named graphs. To account for them, you would need something like
SELECT (COUNT(*) AS ?no) { { ?s ?p ?o } UNION { GRAPH ?g { ?s ?p ?o } } }
On Mon, Nov
What is the most efficient way to get total number of triples?
Is this query below the only way?
SELECT (COUNT(*) AS ?no) { ?s ?p ?o }
Thanks,
Z
That would only count triples in the default graph and omit triples in
named graphs. To account for them, you would need something like
SELECT (COUNT(*) AS ?no) { { ?s ?p ?o } UNION { GRAPH ?g { ?s ?p ?o } } }
On Mon, Nov 9, 2015 at 3:47 PM, Zen 98052 wrote:
> What is the most efficient way to g
