y experience writing software
for the last 40
> years, that often the poor ignorant fool who has to
maintain your
> software is you, months or years down the road -- so it
pays to make
> your code readable. Nothing makes you feel dumber than
not being able
> to understand your own cod
The Solution is: Using whil:
i = 1
a = 1
while i < 5
disp(i)
a
= a + 1
i = i +1
if a == 3 then
i = i - 1
end
end
Am 2017-05-12
11:15, schrieb Frieder Nikolaisen:
> Hello,
>
> another question to
solve the locomotive stuff, giving you a example with the not im
Hello,
another question to solve the locomotive stuff, giving you
a example with the not implented code.
I don't want to code the same
stuff twice. Thats why I want to jump between lines of code. Is this
possible and how?
P = 200;
DM = 1;
for n = 1:10
if DM == 1 then
if
P > 100 then DM
n your
> P(n,2) * (P(n+1,1)
- P(n,1)) term to find where the battery state of
> charge (I assume
that's what 'batt' is) hits 800.
>
> It'll be complicated. It'll be
prone to error. Proving that it's
> correct will be a pain. But when you
get it working
0 at 17:23 +0200, Frieder Nikolaisen wrote:
Hello,
I did write an example code, but I do not like the time consuming way
I solved the problem. With 50 000 lines in the matrix, it wouldn't be
fun.
How can I avoid using the for-loop?
10, 80;
11, 200
15, 0];
batt = 1000;
ge
- P(n,2) * (P(n+1,1) - P(n,1))
end
disp('n ' +
string(n))
disp('batt ' + string(batt))
disp('gen ' +
string(gen))
end
Am 2017-05-10 17:23, schrieb Frieder Nikolaisen:
>
Hello,
>
> I did write an example code, but I do not like the time
consuming way I
Hello,
I did write an example code, but I do not like the time
consuming way I solved the problem. With 50 000 lines in the matrix, it
wouldn't be fun.
How can I avoid using the for-loop?
10, 80;
11,
200
15, 0];
batt = 1000;
gen = 0;
n = 1
for n=1:5
if P(n,2) > 100
then
if batt > 800
Hello Samuel,
thanks a lot. It works fine.
Best regards
Frieder
Am 2017-05-10 13:33, schrieb sgoug...@free.fr:
> Hello Frieder,
>
>
max(A,B) does it:
> --> max(A,B)
> ans =
> 3.
> 3.
> 2.
>
> Samuel
>
>
- Mail original -
>
> Hello,
>
> I have to matrices: A = [ 1
; 2 ; 2 ]
Hello,
I have to matrices:
A = [1; 2; 2]
B = [3; 3; 1]
I
looking for get matric with having only the larger Elemtns:
C = [3; 3;
2]
Is there function to make to apply functions to eacth element.
C =
[ if A .> B then A else B] elemtwise.
A for loop is to slow.
Thanks
a lot.
Cheers
t;
> Antoine
>
> Le 04/05/2017 à 09:13, Frieder Nikolaisen a
écrit :
>
>> Dear Community,
>>
>> I am using the GUI Builder again
(last time Oktobre 2016), now with Scilab 6.0.0.
>>
>> I started to
Design the interface, generated the GUI. Had the GUI
I restarted the project with the GUI Builder 3.0 for Scilab 5.5. To
now, it runs normal. I attach the working file.
I do not understand
the trouble. I had other problems yesterday, with both versions.
Hopefully it runs now stable.
Am 2017-05-04 09:13, schrieb Frieder
Nikolaisen:
> D
Dear Community,
I am using the GUI Builder again (last time
Oktobre 2016), now with Scilab 6.0.0.
I started to Design the
interface, generated the GUI. Had the GUI run and wanted to reload it.
But:
--> guibuilder
operation -: Warning adding a matrix with the
empty matrix will give an empty
s with the Scilab help.
Greetings
Frieder
Am 2017-03-20 17:53, schrieb Tim Wescott:
> On
Mon, 2017-03-20 at 17:26 +0100, Frieder Nikolaisen wrote:
>
>> Hello, I
do try to read a matrix of floating point numbers from a text file. I
want to have floating point numbers in Sciliab. (I
Am 20.03.2017 um 18:30 schrieb Osvaldo Sergio Farhat de Carvalho:
Hi Frieder,
Try
Koeffizienten_Pfad = uigetfile(["*.txt"],'',"Wählen Sie die Datei
Koeffizienten");
m = fscanfMat(Koeffizienten_Pfad)
disp(B)
Regards,
Osvaldo
-"users" escre
Hello,
I do try to read a matrix of floating point numbers from a
text file. I want to have floating point numbers in Sciliab. (I used
before mgetl which return strings).
I have attached the example text
file and scilab file. The error it says is: read: Wrong number of output
argument(s): 0
ng(M(m)))
>>
end
>>
>> "How can I move the lettering above the plot (or at least to
the bottom, next to the x-axis)?" By data_bounds (see axes_properties in
the help pages) you can enlarge the y-axis beyond the y data span at
will. The y-level of the lettering is con
ettering above the plot (or at least to
the bottom, next to the x-axis)?" By data_bounds (see axes_properties in
the help pages) you can enlarge the y-axis beyond the y data span at
will. The y-level of the lettering is controlled by the input variable
'ybase' (see code above).
>&g
---------
>
> Am 12.10.2016 10:52, schrieb Frieder Nikolaisen:
>
>> Hello,
>>
>> thank you for all the feedback and help. It's really great.
>>
>>
I used the idea of Jens S
Hello,
thank you for all the feedback and help. It's really great.
I used the idea of Jens Simon Strom combined with some help from last
week:
//Datensätze
x1 = (A(:,1) - A(1,1)) * 24 * 3600;
y1 =
A(:,y_1);
y2 = A(:,y_2);
y3 = A(:,y_3);
drawlater()
subplot(3, 1, 1)
co
= color("green");
dd a x-axis by using subplot?_" and your last
example,
>
> Couldn't you add a 4th subplot at the bottom in order to
plot the 2ndx-axis (say by plotting only zeros)?
>
> Regards,
>
>
Rafael
>
> FROM: users [mailto:users-boun...@lists.scilab.org [1]] ON
BEHAL
x3 axis, since it is on the right side // create 2nd x-axis a4 =
newaxes(); c=color("black"); a4.font_color=c; a4.foreground=c;
plot2d(x2, fake_y,c); // for fake_y = 0 creates a line on the x2-axis //
therefore the fake data are not visible a4.children.children.visible =
off; // hide fak
are not visible
a4.children.children.visible = off; // hide fake graph if nesessary
to only show the axes
a4.data_bounds = [min(x2),0;max(x2),1];
a4.axes_visible(2)="off";
a4.filled="off";
a4.x_location="bottom";
a4.margins = [0.2 0.2 0.2 0.1];
drawnow()
2016-10-09
Dear Philipp,
thank you, thats great. I will try it at work on monday. Actually, I do
have three plots sharing a common x axis and having three different y
axis. Why I do want to have two x axis is, to show to different times on
x. Once in secound, once in line of document.
Best regards
Fri
this code, but earlier in the program.
Regards
Am 06.10.2016 15:27, schrieb Clément David:
Hallo Frieder,
Most of this ML readers / writers are not german speaker, could you
please use english next time ?
Thanks,
--
Clément
Le jeudi 06 octobre 2016 à 15:18 +0200, Frieder Nikolaisen a écri
(''), c=c, sizeA=size(A)
before the problem line
if A(c-1,3)==0 then
and you will see what happens there.
Regards
Jens
---
Am 06.10.2016 08:29, schrieb Frieder Nikolaisen:
With the real Code, it's more difficult to predict the first c.
Tha
na.axes_visible(1)="off"; // Masking the x axis
(useless overlay)
na.y_location="right"; // Y axis on the right side
na.children(1).children(1).thickness=2; // Curve thickness
//Secound x axis, by Frieder Nikolaisen supported by Jen
1,3)
If c = 1 then A(0,3) that is not possible since the index start to 1
... no ?
-Message d'origine-
De : users [mailto:users-boun...@lists.scilab.org] De la part de
Frieder Nikolaisen Envoyé : jeudi 6 octobre 2016 08:18 À : Users
mailing list for Scilab Objet : [EXTERNAL]
Hello everybody,
I do have a code, I cannot find the mistake. I get the error:
"if A(c-1,3)==0 then
!--error 21
ungültiger Index.
at line 11 of exec file called by :
exec('M:\CAD\Abteilungen\Praktikanten\Nikolaisen,
Frieder\Fahrdaten\Testprogramm\Archive\test2.sce', -1)
#x27;P in MW' oder 'P [MW]'. I think the diagram
would look quite nice.
Regards
Jens
-------
Am 30.09.2016 13:23, schrieb Frieder Nikolaisen:
Dear Jens,
there is not much to be confused about. I have attached my
Diagramms wi
t you plan to plot.
Regards
Jens
Am 30.09.2016 11:27, schrieb Frieder Nikolaisen:
I did forgott one Point:
My data Looks like:
Drehzahl Cv-DruckRichtungLokbremse anlegen Lokbremse
lösenZugbrem
0.000
0 1 0 1 0 0
...
For beeing used in a secound Programm.
Best regards
Originalnachricht
Betreff: [Scilab-users] plotxxyyy
Datum: 30.09.2016 11:17
Absender: Frieder Nikolaisen
Empfänger: Users mailing list for Scilab
Antwort an: Users
quot;
Best regards
Frieder Nikolaisen
The minimal Code:
//Write your callback for Diagramm here
A=rand(15,50)
//Dieser Code und geistiges Eigentum von Samuel GOUGEON wird geändert
und angepasst von Frieder Nikolaisen (FN), bleibt in seinen Grundzügen
jedoch erhalten
// Scilab ( h
Thank you.
Am 28.09.2016 12:35, schrieb sgoug...@free.fr:
Hello,
I did attach a plot, now 20kB, of a pump from an old exam. The plot
does provide SI dimensions as well as US ones. Thats why there are
three
x-axis and two y-axis.
For this kind of case where
* you want different axes _for t
e are three
x-axis and two y-axis.
Best regards
Frieder Nikolaisen
Am 26.09.2016 18:29, schrieb sgoug...@free.fr:
De: "Frieder Nikolaisen"
.../...
I do use the ScilabHelp, but I cannot find a plotyyy. That isn't the
Demos?
no. To get and use the demos manager, you
my field of engineering.
Best Regards,
Frieder Nikolaisen
Am 26.09.2016 14:18, schrieb sgoug...@free.fr:
Hello,
De: "Frieder Nikolaisen"
Envoyé: Lundi 26 Septembre 2016 13:27:35
Objet: [Scilab-users] Plot with two different y-axis as one plot
Dear Sir or Madam,
I want to print a
legend("Drehzahl",1)
I would even like to have four y-axis, two of both sides in the same
Color as the graph. How to do this?
Best regards
Frieder Nikolaisen
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