Thanks for all the answers.
I feared that there is no way around a loop. During the process batt
(Battery) is charged and discharged. In my example, it is only
discharged. I will code the entire problem with a loop, maybe somebody
knows something to speed up the process with the full problem. (Tim: I
am not a programming pro, a C-function might not be a solution. )
Why do I try avoidng a loop? I do have txt-document with 50 000 to 100
000 lines about a (hybrid-)locomotive shunting process. I do need to
optimize the energy managment. Because I am not mathemtic student, I
have to solve the problem empirical (try and error). The programm has to
run a few hundred times. With a matrix thats no problem, but with
matrixes only, I can only calculate the diesel usage without any battery
energy storage.
Thanks for the checking my code anyway.
Am 10.05.2017 um 20:53 schrieb Amanda Osvaldo:
What it's the equation you need to compute ?
Perhaps I can help.
I think it's possible to compute with something in this way:
map = find (P(:,2) > 100 );
if batt > 800 then
batt = batt - P(map,2) * (P(map+1,1) - P(map,1));
end
On Wed, 2017-05-10 at 17:23 +0200, Frieder Nikolaisen wrote:
Hello,
I did write an example code, but I do not like the time consuming way
I solved the problem. With 50 000 lines in the matrix, it wouldn't be
fun.
How can I avoid using the for-loop?
10, 80;
11, 200
15, 0];
batt = 1000;
gen = 0;
n = 1
for n=1:5
if P(n,2) > 100 then
if batt > 800 then batt = batt - P(n,2) * (P(n+1,1) -
P(n,1))
else
gen = gen + P(n,2) * (P(n+1,1) - P(n,1))
end
else
batt = batt - P(n,2) * (P(n+1,1) - P(n,1))
end
disp('n ' + string(n))
disp('batt ' + string(batt))
disp('gen ' + string(gen))
end
Thanks alot!
Best regards Frieder
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