Hi,
Maybe not everyone heard about it but there is a new way to enhance the
markup and make it more search crawler friendly: http://schema.org . It
seems interesting.
Attila
I created https://issues.apache.org/jira/browse/WICKET-3765 and attached a
quickstart.
I commented out the Form in the quickstart. Just uncomment those lines to
see the bug.
Regarding the strangeness of the Form in the FormComponent: I may be able to
remove the Form. This is an older component th
Hello,
I used to refresh all the components in the listview for each http
transaction.
But now I tried to use the:
setReuseItems(true);
When using a ListView. Documentation says that is a must (but I made it
to work without it).
The problem is that now the objects are serialized and deserial
create a quickstart and we can see if there is an easy fix. at first
glance it seems rather strange to have a form inside a
formcomponentpanel
-igor
On Wed, Jun 1, 2011 at 6:56 PM, Clint Checketts wrote:
> I finally had a chance to create a quickstart and play with it. The issue
> happens wh
default processing = false means do not validate, etc. but, inputs are
preserved. make sure your ajaxsubmitlink is inside the correct form.
you can specify one in its constructor.
-igor
On Thu, Jun 2, 2011 at 4:22 PM, Nelson Segura wrote:
> On the AjaxSubmitLink, correct?
> When I do that, the i
Hi Nelson, the raw input has preference and it remains in the form
component until be converted and set in the form component model. For
your use case you can use a simple AjaxLink targeting just the dynamic
fields panel, not the whole form.
On Thu, Jun 2, 2011 at 8:22 PM, Nelson Segura wrote:
>
On the AjaxSubmitLink, correct?
When I do that, the input of the other fields is lost (which has not been
previously submitted).
How does wicket exactly decides whether to show the model value or the user
raw input?
My Ajax links is refreshing the whole panel.
-Nelson
On Thu, Jun 2, 2011 at 4:14
you want setDefaultFormProcessing(false)
-igor
On Thu, Jun 2, 2011 at 3:41 PM, Nelson Segura wrote:
> I have a form to which I need to add dynamic fields using ajax, whenever the
> user clicks on the "add new input" link.
> I need to preserve the current user input, without actually updating the
I have a form to which I need to add dynamic fields using ajax, whenever the
user clicks on the "add new input" link.
I need to preserve the current user input, without actually updating the
backing models (or at least preserve input that is not completely valid, or
do not show errors if the user a
if you want to reference images from css the images have to live next
to the css file. so if your css is in webapp, the images have to be
based in webapp, but if your css lives in a java package the images
have to live there as well. this way relative urls work.
-igor
On Thu, Jun 2, 2011 at 11:04
Hi ,
I am also looking the same, could you please share the details, if you found
the solution.
regards
dhans
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Hello,
I was referring to a maven snapshot repository from where to have maven
check daily for new builds of the snapshot version.
What I currently do is to manually svn checkout and do mvn install. Not
really a problem but the phrase "If you want to stay recent but don't want
to build yourself, yo
Ah it's ok to use
https://repository.apache.org/content/repositories/snapshots
didn't have an update policy specified(although default is daily) and the
snapshot version was red, but changing it must have forced an IDE reimport.
Apache Nexus - snapshots
https://rep
Hi Pedro.
But how do you get the link's id i.e., "moveC3ToC2"?
I added all the code to the Node and Tree derive classes to so that I could
get the link id.
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Se
You can mount a page to a static path in you Application class. in
Wicket 1.4.x just call mountBookmarkablePage:
//url for asterisk calls
mountBookmarkablePage("/DialPage", DialPage.class);
Under Wicket 1.5 you should call mountPage instead of mountBookmarkablePage.
but I don't know how get th
but I don't know how get the URL for the page?
Wicket generates de URL dinamically right?
How can generates an static URL?
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Hi Mohammad, nice you created the test case. I just would recommend to
don't make any reference from your domains objects (TreeNode) to view
ones (AjaxLink) because they are usually packaged in different places.
Take a look at how I created a similar test:
http://svn.apache.org/repos/asf/wicket/re
Use the strategy pattern (i.e. changing the strategy each time a button
is submitted):
http://en.wikipedia.org/wiki/Strategy_pattern
Sven
On 06/02/2011 07:42 PM, meduolis wrote:
I will update this onClick recursive, need some more dynamic solution
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Hi,
you can consider to attach/remove behaviors to you link. For example :
link = new Link("link"){
@Override
public void onClick() {
}
};
link.add(new AjaxEventBehavior("onclick") {
protected void onEvent(AjaxRequestTarget target) {
I will update this onClick recursive, need some more dynamic solution
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Sure, it's just Java:
add(new Link("myLink") {
public void onClick() {
if (buttonClicked) {
// do something else if button (was) clicked
} else {
// do something here...
}
}
});
add(new Button("myButton") {
public void onSubmit() {
Is there any way to update onClick method for the same link?
Let say I have link
add(new Link("myLink") {
public void onClick() {
// do something here...
}
);
And later, when I click other control I want to update myLink onClick logic
public void onClick() {
// do somethin
Pedro, thanks for your response.
I solved my problem in the following way:
For my derived DefaultMutableTreeNode class I added an Ajax link element:
public class CheckBoxSelectableTreeItem
extends DefaultMutableTreeNode
{
protected AjaxLink clickLink; // for testing the expand/col
Thanks for the quick response.
Well, I want it to stay at the Home Page. How did it go back to loginPage??
Thanks again.
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You submitted the HomePage form. Where do you expect the app to go from there?
-Original Message-
From: msalman [mailto:mohammad_sal...@yahoo.com]
Sent: Thursday, June 02, 2011 11:24 AM
To: users@wicket.apache.org
Subject: WicketTester and the rendered page
I am testing an application th
I am testing an application that starts with a login page. After logging in
the user is taken to the home page.
@Test
public void test()
{
QuickStartApplication app = new QuickStartApplication();
mount your wicket page so it has a well known url which you can call
from the struts app.
-igor
On Thu, Jun 2, 2011 at 8:51 AM, Ivoneta wrote:
> hello everyone
>
> I need some help..
>
> I have an application based on struts... This application has some links,
> and I need this links calls a Wi
hello everyone
I need some help..
I have an application based on struts... This application has some links,
and I need this links calls a Wicket Pageit is possible?
I think that is possible calls ising the url page , but the problem is the
wicket generates the urls dinamically...
How can I
hello everyone
I need some help..
I have an application based on struts... This application has some links,
and I need this links calls a Wicket Pageit is possible?
I think that is possible calls ising the url page , but the problem is the
wicket generates the urls dinamically...
How can I
Merhaba,
I found the problem. My problem was mixing the Wicket and Spring
configurations. I had used both SpringBean and Spring's Autowire mechanisms
in some places...
Now, I modified the code and used only @SpringBean. Everything is working
properly.
2011/6/2 Altuğ Bilgin Altıntaş
> Merhaba izl
Here is the detailspage.html hierarchy
DetailsPage
henry
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here is the DetailsPage hierarchy
//DetailsPage.html
DetailsPage
henry
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Class hierarchy.
On Thu, Jun 2, 2011 at 6:56 AM, James Carman wrote:
> What is DetailsPage's hierarchy?
>
> On Thu, Jun 2, 2011 at 6:02 AM, henry wrote:
>> hi guys am having some issues my code any help will do,am trying to add a
>> link to my datatable
>> firstly i created the DetailPage class
What is DetailsPage's hierarchy?
On Thu, Jun 2, 2011 at 6:02 AM, henry wrote:
> hi guys am having some issues my code any help will do,am trying to add a
> link to my datatable
> firstly i created the DetailPage class
>
> //DetailPage class code
> public DetailsPage(String id , IModel entryModel)
hi guys am having some issues my code any help will do,am trying to add a
link to my datatable
firstly i created the DetailPage class
//DetailPage class code
public DetailsPage(String id , IModel entryModel) {
super(id,entryModel);
Link link = new Link("link"){
@Overr
Hi James,
Using dojo it's a very different approach. The idea of using dojo is to
use everything that dojo gives...
I think it has powerfull features:
* Full support for lots of widget (calendar, hour,
autocomplete text fields, etc).
* Theme suppo
Hi James,
Yes, please, send me a .war. My e-mail has no limit in storage.
gagui...@aguilardelgado.com
El mié, 01-06-2011 a las 16:34 -0400, James Carman escribió:
> On Wed, Jun 1, 2011 at 2:59 PM, Gonzalo Aguilar Delgado
> wrote:
> >
> > Does it took long to program it? Do you think you w
Merhaba izlem;
I think you should look at Proxy-based Approach. Spring and Wicket
integration type is important.
Please visit : https://cwiki.apache.org/WICKET/spring.html.
A.
01 Haziran 2011 20:02 tarihinde İzlem Gözükeleş yazdı:
> Furthermore, I changed the source code of spring framework
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