From: Tim Chase, Wed, October 18, 2006 12:00 pm
>
> > The application is this :version pretty-fier:
> >
> > function! Str_wrap(str, len)
> > return substitute(a:str, '[[:print:]]\{,'.a:len.'}','&\n','g')
> > endfunction
>
> I must be missing something...in your original post, you didn't
> have an
I'm having a mental block, how can I wrap a string via
substitute() ?
The following seems to do the trick for me:
echo substitute(str, '[[:print:]]\{,10}', '&\n', 'g')
This nearly works, but is doubling existing line breaks.
The application is this :version pretty-fier:
function! Str_wra
Steve Hall wrote:
From: Tim Chase, Wed, October 18, 2006 6:46 am
I'm having a mental block, how can I wrap a string via
substitute() ?
The following seems to do the trick for me:
echo substitute(str, '[[:print:]]\{,10}', '&\n', 'g')
This nearly works, but is doubling existing line breaks.
From: Tim Chase, Wed, October 18, 2006 6:46 am
>
> > I'm having a mental block, how can I wrap a string via
> > substitute() ?
>
> The following seems to do the trick for me:
>
> echo substitute(str, '[[:print:]]\{,10}', '&\n', 'g')
This nearly works, but is doubling existing line breaks.
The a
On 10/18/06, Steve Hall <[EMAIL PROTECTED]> wrote:
I'm having a mental block, how can I wrap a string via substitute() ?
I've been trying something like:
let str = "123456789012345678901234567890"
let str = substitute(str, '\n\([[:print:]]\{-10,}\)', '\n\1\n', '')
echo str
to produce:
I'm having a mental block, how can I wrap a string via substitute() ?
I've been trying something like:
let str = "123456789012345678901234567890"
let str = substitute(str, '\n\([[:print:]]\{-10,}\)', '\n\1\n', '')
echo str
to produce:
1234567890
1234567890
1234567890
The following
