Am 06.10.2011 21:25, schrieb Daniel Rocha:
You must not forget the losses due the conversion between the heat
exchangers. If it was 70%, that means around 5KW for the core.
If the heat exchanger is well isolated, it will not loose energy.
It will reduce the temperature, because it has a finite t
On Thu, Oct 6, 2011 at 3:23 PM, Terry Blanton wrote:
> On Thu, Oct 6, 2011 at 3:11 PM, Terry Blanton wrote:
>> "between 3 p.m. till 7 p.m. the temperature average delta has been of
>> 5°C (water input/output) for 0,6 cubic meters per hour"
>
> Back of the envelope, that's 50.3 Mjoules.
or 13.97
You must not forget the losses due the conversion between the heat
exchangers. If it was 70%, that means around 5KW for the core.
2011/10/6 Peter Gluck
> 3000 kcal per hour = 3.49 kW True?
> I am very tired after this day of info-hunting
> Peter
>
>
> On Thu, Oct 6, 2011 at 10:11 PM, Terry Blant
On Thu, Oct 6, 2011 at 3:11 PM, Terry Blanton wrote:
> "between 3 p.m. till 7 p.m. the temperature average delta has been of
> 5°C (water input/output) for 0,6 cubic meters per hour"
Back of the envelope, that's 50.3 Mjoules.
Oh, right. That's calories!
3000 kcal per hour = 3.49 kW True?
I am very tired after this day of info-hunting
Peter
On Thu, Oct 6, 2011 at 10:11 PM, Terry Blanton wrote:
> "between 3 p.m. till 7 p.m. the temperature average delta has been of
> 5°C (water input/output) for 0,6 cubic meters per hour"
>
> According to the hus
On Thu, 2011-10-06 at 15:11 -0400, Terry Blanton wrote:
> "between 3 p.m. till 7 p.m. the temperature average delta has been of
> 5°C (water input/output) for 0,6 cubic meters per hour"
>
> According to the husband of the cute brunette. :-)
This is what I get.
0.6 cubic meters / hour = 600 lite
Well, that means 600,000/3600*5*1W = 833W. That's the old electric
heater hypothesis. Odd coincidence, although there was no input
electricity.
2011/10/6 Terry Blanton
> "between 3 p.m. till 7 p.m. the temperature average delta has been of
> 5°C (water input/output) for 0,6 cubic meters per hour
"between 3 p.m. till 7 p.m. the temperature average delta has been of
5°C (water input/output) for 0,6 cubic meters per hour"
According to the husband of the cute brunette. :-)
T
3.5kW is lower value than what I estimated, therefore it must be false. . .
But anyway, perhaps we can take it as absolute minimum. If then E-Cat
produced about 64 kJ excess heat. That would translate into 3kg ethanol need
to fake the results. Therefore, test is not conclusive!!
However, i still
Where did you find that value?
2011/10/6 Peter Gluck
> See the tweets of the other journalist from
> Italy.
> http://twitter.com/#!/raymond_zreick
>
> It seems the FatCat has worked at
> ~ 3.5 kW.
> Till we will not discover something tricky and
> if this experiment can be repeated with many
> g
See the tweets of the other journalist from
Italy.
http://twitter.com/#!/raymond_zreick
It seems the FatCat has worked at
~ 3.5 kW.
Till we will not discover something tricky and
if this experiment can be repeated with many
generators, it seems this day was a Sweet
Thursday for the Rossi believers
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