On Oct 23, 10:52 pm, ron_m wrote:
> The rows is a dict so if you apply the keys() function you get a list
> of keys or values returns a list of values under the keys.
>
> rows = big_hairy_select_with_joins
>
> for row in rows:
> for table in row.values()
> for field in table.values()
Yes,
A couple of comments that I hope might help.
The rows is a dict so if you apply the keys() function you get a list
of keys or values returns a list of values under the keys.
rows = big_hairy_select_with_joins
for row in rows:
for table in row.values()
for field in table.values()
which is
you can do this:
results = list()
for row in big_long_hairy_select_with_joins_and_stuff
vals=list()
for f in rows.colnames:
vals.append(row[f.split('.')[1])
results.append(dict(id=row[rows.colnames[0].split('.')
[1]],cell=vals))
On Oct 23, 11:08 pm, BigBaaadBob wrote:
> I m
I must be expressing myself poorly. I'm saying that if the dal (and
sql) Row class had a method like this:
def column(self, colname):
(table, field) = colname.split('.')
return self[table][field]
I could do this (which is what jqGrid wants):
results = list()
for row in big_long_hairy_se
Massimo fix a bug in crud.select today in trunk maybe it could help!
crud.select(db.table)
Now reponse to
db.table.field.readable=False
and
db.table.field.represent='some thing'
Richard
On Fri, Oct 22, 2010 at 1:15 PM, BigBaaadBob wrote:
> I'm probably dense, but I don't see how it does.
I'm probably dense, but I don't see how it does.
rows.colnames has strings like 'foo.id' and 'a.name'. But you can't
index into a row with those strings: you can't say r['foo.id'] or
r['a.name']. You have to parse the column name and create code like
r['foo']['id'] and the problem I have with th
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