I'm having an odd issue that maybe someone on the list can shed some
light on. I recently started a new project, and decided to try
Frontbase instead of my usual MySQL. I am having an issue where EOF
is not supplying the pk (id) on insert for one of my EO's. The EO in
question (Diagnosis)
OKay, I finally have the example WO (nhlpm) running
and talking to my postgresql backend.
So my eclipse workspace has only the nhlpm project. I
created a new project (WOApplication) called NewTest.
I right clicked the selected project and selected 'run
as' woapplication.
What runs is the first
Le 08-01-01 à 14:47, Theodore Petrosky a écrit :
OKay, I finally have the example WO (nhlpm) running
and talking to my postgresql backend.
So my eclipse workspace has only the nhlpm project. I
created a new project (WOApplication) called NewTest.
I right clicked the selected project and
Hi,
I had a similiar problem. Did you put the
FrontBasePlugIn.frameworkinto your Frameworks folder and link it into
your Project as Framework.
Regards
Ute
Am 01.01.2008 um 20:36 schrieb Tobias Crawley:
I'm having an odd issue that maybe someone on the list can shed
some light on. I
Ute:
Yes. Its in /Library/Frameworks/ and is linked in the project. Other
inserts work fine - the sql for the Card insert just before the
Diagnosis insert is correct, and I've been able to insert other EO''s
as well, just not Diagnoses.
Tobias
On Jan 1, 2008, at 5:01 PM, ute Hoffmann
Hi!
I find very suspect that the ID of the card and diagnosisCodeId
are the same. My bet is that you have a wrongly modeled relationship
between card and Diagnosis.
Yours
Miguel Arroz
On 2008/01/01, at 23:04, Tobias Crawley wrote:
Ute:
Yes. Its in /Library/Frameworks/ and is
On Jan 1, 2008, at 9:36 AM, Tobias Crawley wrote:
attributes = (
{
allowsNull = Y;
columnName = altDescription;
name = altDescription;
prototypeName = varchar255;
},
{columnName = cardID; name = cardID; prototypeName =
I am a little confused. Here is the line from the
tutorial:
Now run your application (remember to highlight the
project name #64257;rst), and if all goes well you
should see your beautiful data entry page.
-
I am confused about how to run a second project. I
created a second
{columnName = cardID; name = cardID; prototypeName = id; },
How does EOF know to which column in your table to map your id
attribute? Try specifying a columnName value for your id attribute.
prototypeName = id sounds suspiciously like ERPrototypes in Wonder,
which actually defines
Le 08-01-01 à 19:41, Theodore Petrosky a écrit :
I am a little confused. Here is the line from the
tutorial:
Now run your application (remember to highlight the
project name #64257;rst), and if all goes well you
should see your beautiful data entry page.
-
I am confused
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