Hi Imran,
I did try the same, with "test.xsl" alone in the path.
But then it gives me the error :
http://localhost:8080/servlet/test.xsl not found.
Any suggestions to tackle this problem ?
Regards,
Seema Kumar
Datamatics Technologies Ltd.,
(Tel: 8290829 (Ext:619))
----- Original Message -----
From: "Imran Baig" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Tuesday, May 08, 2001 4:53 PM
Subject: Re: Problem using XSL while displaying XML through servlets
> For XSL file don't give any path just use XSL filename. So instead of
using "
> c:\\JavaWebServer2.0\\servlets\\test.xsl\" use "test.xsl".
>
> Baig
>
>
>
>
>
>
> Seema P Kumar <[EMAIL PROTECTED]> on 05/08/2001 03:20:44 PM
>
> Please respond to "A mailing list for discussion about Sun Microsystem's
Java
> Servlet API Technology." <[EMAIL PROTECTED]>
>
> To: [EMAIL PROTECTED]
> cc: (bcc: Imran Baig/CresSoft)
>
> Subject: Problem using XSL while displaying XML through servlets
>
>
>
> Hi all,
>
> I am attempting to display an XML document that uses a XSL style sheet,
> through a servlet. I have placed both the servlet class file and .xsl file
> in the same /servlets directory of JavaWebserver. However, while trying to
> display the servlet the browser throws the following error :
>
> Access is denied.
> Error processing resource 'file://c:\JavaWebServer2.0\servlets\try.xsl'.
>
> I use the following code snippet for the same :
> public void doPost(HttpServletRequest request, HttpServletResponse
response)
> throws ServletException, IOException{
>
> response.setContentType("text/xml");
>
> PrintWriter out = response.getWriter();
> out.println("<?xml version=\"1.0\" standalone=\"yes\" ?>");
> out.println("<?xml-stylesheet type=\"text/xsl\"
> href=\"c:\\JavaWebServer2.0\\servlets\\test.xsl\"?>");
> out.println("<myxml>");
> out.println("<mytag> ...</mytag>");
> out.println("</myxml>");
> }
>
> Somebody please help..
> Thanks in advance..
>
> Seema
>
>
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