Seema,
Have you tried accessing your XSL file directly.
I mean instead of using XML link, type URL of your XSL file directly in
your browser.
For example
http://localhost:8080/servlet/test.xsl
OR
http://localhost/servlet/test.xsl
If you are successful in accessing your XSL file then give that path
accodingly in your servlet.
If still unsuccessful in accessing XSL file then you may copy your XSL file
in directory having read rights.
Baig
Seema P Kumar <[EMAIL PROTECTED]> on 05/08/2001 04:41:13 PM
Please respond to "A mailing list for discussion about Sun Microsystem's Java
Servlet API Technology." <[EMAIL PROTECTED]>
To: [EMAIL PROTECTED]
cc: (bcc: Imran Baig/CresSoft)
Subject: Re: Problem using XSL while displaying XML through servlets
Hi Imran,
I did try the same, with "test.xsl" alone in the path.
But then it gives me the error :
http://localhost:8080/servlet/test.xsl not found.
Any suggestions to tackle this problem ?
Regards,
Seema Kumar
Datamatics Technologies Ltd.,
(Tel: 8290829 (Ext:619))
----- Original Message -----
From: "Imran Baig" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Tuesday, May 08, 2001 4:53 PM
Subject: Re: Problem using XSL while displaying XML through servlets
> For XSL file don't give any path just use XSL filename. So instead of
using "
> c:\\JavaWebServer2.0\\servlets\\test.xsl\" use "test.xsl".
>
> Baig
>
>
>
>
>
>
> Seema P Kumar <[EMAIL PROTECTED]> on 05/08/2001 03:20:44 PM
>
> Please respond to "A mailing list for discussion about Sun Microsystem's
Java
> Servlet API Technology." <[EMAIL PROTECTED]>
>
> To: [EMAIL PROTECTED]
> cc: (bcc: Imran Baig/CresSoft)
>
> Subject: Problem using XSL while displaying XML through servlets
>
>
>
> Hi all,
>
> I am attempting to display an XML document that uses a XSL style sheet,
> through a servlet. I have placed both the servlet class file and .xsl file
> in the same /servlets directory of JavaWebserver. However, while trying to
> display the servlet the browser throws the following error :
>
> Access is denied.
> Error processing resource 'file://c:\JavaWebServer2.0\servlets\try.xsl'.
>
> I use the following code snippet for the same :
> public void doPost(HttpServletRequest request, HttpServletResponse
response)
> throws ServletException, IOException{
>
> response.setContentType("text/xml");
>
> PrintWriter out = response.getWriter();
> out.println("<?xml version=\"1.0\" standalone=\"yes\" ?>");
> out.println("<?xml-stylesheet type=\"text/xsl\"
> href=\"c:\\JavaWebServer2.0\\servlets\\test.xsl\"?>");
> out.println("<myxml>");
> out.println("<mytag> ...</mytag>");
> out.println("</myxml>");
> }
>
> Somebody please help..
> Thanks in advance..
>
> Seema
>
>
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