System.out.println DOES show up in the Java Console of the browser showing the
Applet.... which should be fine for debugging/testing purposes but not for a
production environment...
good luck,
-john
Richard Yee <[EMAIL PROTECTED]> on 09/26/2001 04:03:23 PM
Please respond to "A mailing list for discussion about Sun Microsystem's Java
Servlet API Technology." <[EMAIL PROTECTED]>
To: [EMAIL PROTECTED]
cc: (bcc: Winfrey Y Johnson/IT/VANCPOWER)
Subject: Re: More on downloading a file
Sohalia,
Note that the System.out.println in your applet code is not going to show
up anywhere because the there is no console for the Applet to display.
I'd suggest that you have your applet just post to one of the tomcat
example servlets that will print out the request. Note that there is not
much use in having the applet read the response from the servlet because it
won't be able to write the file to the local disk.
You need to use getAppletContext().showDocument(dataURL); to have the
servlet response handled by the browser.
This code is working fine in my applet although I am using a GET instead of
a POST.
public void actionPerformed(ActionEvent event) {
try {
System.out.println("actionPerformed");
//String query= URLEncoder.encode(inputField.getText());
String query= inputField.getText();
URL currentPage = getCodeBase();
String protocol = currentPage.getProtocol();
String host = currentPage.getHost();
int port = currentPage.getPort();
String urlSuffix = "/myapp/servlet/requestInfo?" + query;
URL dataURL = new URL(protocol, host, port, urlSuffix);
getAppletContext().showDocument(dataURL);
}
catch (MalformedURLException mue) {
}
}
Regards,
Richard
-Richard
At 03:07 PM 9/26/01 -02-30, you wrote:
>Hi, ok i don't get an error anymore (thank you to those who helped me with
>that). I removed the ObjectOutputStream from my code, but now my servlet
>doesnt seems to not be run even tho a connection to is is established.
>(The servletrunner thing where it says the servletname: init thing doesnt
>happen, which is why i assume its not run)
>
>in my applet i call a function
>
>downloadFile(data)
>
>which contains the following code
>
>public void downloadFile(UserData data) throws Exception
>{
> servlet = new URL(webBase, "servlet/FileDownloadServlet");
> Serializable objs[] = { data };
> URLConnection con = servlet.openConnection();
> System.out.println("con open");
> con.setDoInput(true);
> con.setDoOutput(true);
> con.setUseCaches(false);
>
>
>con.setRequestProperty("Content-Type","application/x-www-form-urlencoded");
> ObjectOutputStream out = new
> ObjectOutputStream(con.getOutputStream());
> int numObjects = objs.length;
> String output = "";
> for(int i = 0; i< numObjects; i++)
> {
> out.writeObject(objs[i]);
> output = "done!";
> }
> out.flush();
> out.close();
>}
>
>
>then the servlet is (no database stuff this time, just trying to dl a file
>from /tmp )
>
>public void doPost(HttpServletRequest req, HttpServletResponse resp)
> throws ServletException, IOException
>{
> // Open the I/O streams and connection
> ObjectInputStream in = new ObjectInputStream(req.getInputStream() );
> resp.setContentType("text/html");
> PrintWriter out = resp.getWriter();
> try {
> try {
> //get parameter from applet
> UserData data = (UserData)in.readObject();
> out.println("Content-Disposition: attachment;
>filename="+data.getFileName());
> out.println("Content-Type: application/octet-stream;
>name=/tmp/"+data.getFileName());
> out.println("Content-Location: /tmp/"+data.getFileName());
> out.println("Content-Base: /tmp/"+data.getFileName());
> }
> catch (java.lang.Exception ex){
> ex.printStackTrace ();
> }
> } catch (Exception e) { e.printStackTrace(); }
> in.close();
>}
>
>
>Any suggestions?
>
>Thanks
>sohaila
>
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