To turn on the option to show the java console of the browser and hence see
all messages (System.out.println) your applet prints, you should:
1 - Go to Control Panel;
2 - Double click on Java Plug-in icon;
3 - Select Show Java console
4 - Click Ok.
Hope this helps,
-Leo
> -----Original Message-----
> From: Johnson Winfrey [SMTP:[EMAIL PROTECTED]]
> Sent: Wednesday, September 26, 2001 4:25 PM
> To: [EMAIL PROTECTED]
> Subject: Re: More on downloading a file
>
> System.out.println DOES show up in the Java Console of the browser showing
> the
> Applet.... which should be fine for debugging/testing purposes but not
> for a
> production environment...
>
> good luck,
> -john
>
>
>
>
>
>
> Richard Yee <[EMAIL PROTECTED]> on 09/26/2001 04:03:23 PM
>
> Please respond to "A mailing list for discussion about Sun Microsystem's
> Java
> Servlet API Technology." <[EMAIL PROTECTED]>
>
>
> To: [EMAIL PROTECTED]
> cc: (bcc: Winfrey Y Johnson/IT/VANCPOWER)
>
>
> Subject: Re: More on downloading a file
>
>
>
> Sohalia,
> Note that the System.out.println in your applet code is not going to show
> up anywhere because the there is no console for the Applet to display.
>
> I'd suggest that you have your applet just post to one of the tomcat
> example servlets that will print out the request. Note that there is not
> much use in having the applet read the response from the servlet because
> it
> won't be able to write the file to the local disk.
>
> You need to use getAppletContext().showDocument(dataURL); to have the
> servlet response handled by the browser.
>
> This code is working fine in my applet although I am using a GET instead
> of
> a POST.
>
> public void actionPerformed(ActionEvent event) {
> try {
> System.out.println("actionPerformed");
> //String query= URLEncoder.encode(inputField.getText());
> String query= inputField.getText();
> URL currentPage = getCodeBase();
> String protocol = currentPage.getProtocol();
> String host = currentPage.getHost();
> int port = currentPage.getPort();
> String urlSuffix = "/myapp/servlet/requestInfo?" + query;
> URL dataURL = new URL(protocol, host, port, urlSuffix);
> getAppletContext().showDocument(dataURL);
> }
> catch (MalformedURLException mue) {
> }
> }
>
>
> Regards,
>
> Richard
>
> -Richard
>
>
> At 03:07 PM 9/26/01 -02-30, you wrote:
> >Hi, ok i don't get an error anymore (thank you to those who helped me
> with
> >that). I removed the ObjectOutputStream from my code, but now my servlet
> >doesnt seems to not be run even tho a connection to is is established.
> >(The servletrunner thing where it says the servletname: init thing doesnt
> >happen, which is why i assume its not run)
> >
> >in my applet i call a function
> >
> >downloadFile(data)
> >
> >which contains the following code
> >
> >public void downloadFile(UserData data) throws Exception
> >{
> > servlet = new URL(webBase, "servlet/FileDownloadServlet");
> > Serializable objs[] = { data };
> > URLConnection con = servlet.openConnection();
> > System.out.println("con open");
> > con.setDoInput(true);
> > con.setDoOutput(true);
> > con.setUseCaches(false);
> >
> >
> >con.setRequestProperty("Content-Type","application/x-www-form-urlencoded"
> );
> > ObjectOutputStream out = new
> > ObjectOutputStream(con.getOutputStream());
> > int numObjects = objs.length;
> > String output = "";
> > for(int i = 0; i< numObjects; i++)
> > {
> > out.writeObject(objs[i]);
> > output = "done!";
> > }
> > out.flush();
> > out.close();
> >}
> >
> >
> >then the servlet is (no database stuff this time, just trying to dl a
> file
> >from /tmp )
> >
> >public void doPost(HttpServletRequest req, HttpServletResponse resp)
> > throws ServletException, IOException
> >{
> > // Open the I/O streams and connection
> > ObjectInputStream in = new
> ObjectInputStream(req.getInputStream() );
> > resp.setContentType("text/html");
> > PrintWriter out = resp.getWriter();
> > try {
> > try {
> > //get parameter from applet
> > UserData data = (UserData)in.readObject();
> > out.println("Content-Disposition: attachment;
> >filename="+data.getFileName());
> > out.println("Content-Type: application/octet-stream;
> >name=/tmp/"+data.getFileName());
> > out.println("Content-Location:
> /tmp/"+data.getFileName());
> > out.println("Content-Base: /tmp/"+data.getFileName());
> > }
> > catch (java.lang.Exception ex){
> > ex.printStackTrace ();
> > }
> > } catch (Exception e) { e.printStackTrace(); }
> > in.close();
> >}
> >
> >
> >Any suggestions?
> >
> >Thanks
> >sohaila
> >
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