Evening Ode,
You are trying hard to confuse me. <grin>
>>I use about 32 volts out of a 24 volt transformer to start, then, of
course, the voltage goes down from there as the current gets adjusted to
stay constant.
Are you talking about the load voltage or the power source voltage?
Strangely, the voltage levels off at around 4vdc and conductivity keeps
rising at a more or less linear rate while current stays rock steady.
Trying to draw this changing circuit in my mind.......
As the conductivity rises, the resistance becomes lower, which of course
results in more current draw, unless some other component compensates.
If you have a lot of fancy components in the circuit, like current
limiters, transistors, regulating chips, ect, then the operating
parameters of the circuit is constantly changing, much more than they
would in simple circuit of only the load, the wire, and the source. In
this case, only one thing changes.
In the simple circuit, only a few things that are readily apparent ( to
most of us ) enter in.
One important aspect is the percent regulation of the power supply. Few
are 100 %
In the simple circuit, the ones of us that understand ohms law can see it
working, understand the changes I mentioned above, and not doubt Mr. Ohms.
According to ohms law, that ain't possible. I'm trying to figure out
what's going on.
I think it is possible, and I am tying to understand what is happening
to make it appear that ohms law does not work.
Strangely, the voltage levels off at around 4vdc and conductivity keeps
rising at a more or less linear rate while current stays rock steady.
4 VDC and a current factor, compared to ( 32 volts out of a 24 volt
transformer ) is working with a different load.
By "load" I mean resistance or wattage factor. ( this wattage factor
is something I mentioned a few times in the past. Seems only one person
commented and agreed with me )
A fixed current ( constant current ) will produce less voltage drop
across a lower value of resistance ( load ). The finished mass of CS has a
much lower resistance at the end of the process.
As you stated, the conductivity increases ( = the resistance
decreases ) so the series circuit has changed. Part of the voltage drop
is being dropped some place else in the circuit.
The "Constant Current Circuit" is working in reverse of the CS
conductivity.
As the CS mass changes in conductivity and resistance, the constant current
circuit equals these changes in reverse.
An easy, non technical way to view the constant current circuit is like a
manually controlled potentiometer.
In real time, as the resistance of the CS mass becomes lower (
conductivity increases ) the resistance of the potentiometer ( constant
current circuit ) becomes greater, ( as it is manually operated ) ..... or
else the current would increase.
If one carefully selected the potentiometer and manually controlled it, he
could do the same as the constant current circuit.
Carefully selected above means to know the quantities of the CS mass in the
beginning and end.
( I have done things like this many times. It is very tricky in changing
circuits )
If we view the circuit you are using, and the "equivalent circuit" using
the potentiometer, then the circuit is easier to understand.
Using the equivalent circuit, I think we can see that Ohms Law does still
apply and the phenomena you are seeing is totally possible.
I have some very old messages where we touched on this subject. I stated
some facts and opinions about this same thing.
I got ZERO comments or disagreements. I felt that ever one considered it a
NO ISSUE or thought I was so far off the deep end, they did not want to
discuss it.
Maybe I still am. I look forward to corrections in my analysis above.
Wayne
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