On Mon, Jun 23, 2008 at 3:45 PM, Kenneth Caldwell <[EMAIL PROTECTED]> wrote: > Surely a fair die could have only 4, 6, 8, 12 or 20 faces. > I guess one solution would be to throw three dice consisting of two > octahedrons and a tetrahedron and multiply the results. Is there a more > elegant solution? >
You can have a fair die for any even number. Lots of roleplaying games use ten-sided dice, which are a little like two five-sided pyramids stuck together. If you don't have a d16 handy, you could do something like this: Roll a four-sided die, subtract one, multiply by four, roll a four sided die, add to first number, subtract one. Of course, the more interesting question is WHY!?!?! jml -- SLUG - Sydney Linux User's Group Mailing List - http://slug.org.au/ Subscription info and FAQs: http://slug.org.au/faq/mailinglists.html
