In C++ you do this to set the diffuse ui mapping (should be simple to port
this to python):
diffuseParamDef.GetAttributes().Set(L"{8C80DEF3-1064-11d3-B0B7-00A0C982A112}",
L"{3515CC72-082C-11D0-91DE-00A024C78EE3}");
The GUID "{8C80DEF3-1064-11d3-B0B7-00A0C982A112}" means "ui mapping".
The GUID "{3515CC72-082C-11D0-91DE-00A024C78EE3}" is the XSI GUID for
diffuse.
GUIDs for other shader parameters (like spec etc..) can be found by looking
at the ui mapping lines in material-phong.spdl.
-Nicolas
On Fri, Jul 26, 2013 at 9:13 AM, Vincent Ullmann <
vincent.ullm...@googlemail.com> wrote:
> Becouse it partly fits on this Topic:
>
> Does anyone know how to set the Viewport-Mapping in a
> Python-ShaderDefinition?
>
> In a SPDL-File you can set a it via
> ui "mapping"
>
> Is there a similar function for Python?
>
>
>
> Am 26.07.2013 18:08, schrieb Vladimir Jankijevic:
>
> like this: paramOptions.SetDefaultValue( [0.5, 0.3, 0.2] )
>
>
> On Fri, Jul 26, 2013 at 6:05 PM, Stefano Jannuzzo <
> stefano.jannu...@gmail.com> wrote:
>
>> Hi folks.
>> In a shaderdef define function, I can create a color param and set its
>> default value to a mid gray by
>>
>> paramOptions = XSIFactory.CreateShaderParamDefOptions();
>> paramOptions.SetDefaultValue(0.5);
>> params.AddParamDef("color", siShaderDataTypeColor3, paramOptions);
>>
>> Any idea how to set each channel independently?
>> Thanks. Stefano
>>
>>
>
>
