If you want to do it in Ruby, you can use this script as scaffolding: require 'rsolr' # run `gem install rsolr` to get this solr = RSolr.connect(:url => 'http://ip-10-164-13-204:8983/solr') total = solr.select({:rows => 0})["response"]["numFound"] rows = 100000 query = { :rows => rows, :start => 0 } pages = (total.to_f / rows.to_f).ceil # round up (1..pages).each do |page| query[:start] = (page-1) * rows results = solr.select(query) docs = results[:response][:docs] # Do stuff here # docs.each do |doc| doc[:content] = "IN UR SOLR MESSIN UP UR CONTENT!#{doc[:content]}" end # Add it back in to Solr solr.add(docs) solr.commit end
Scott On Thu, Sep 16, 2010 at 2:27 PM, Shashi Kant <sk...@sloan.mit.edu> wrote: > > Start with a *:*, then the “numFound” attribute of the <result> > element should give you the rows to fetch by a 2nd request. > > > On Thu, Sep 16, 2010 at 4:49 PM, Christopher Gross <cogr...@gmail.com> wrote: > > That will stil just return 10 rows for me. Is there something else in > > the configuration of solr to have it return all the rows in the > > results? > > > > -- Chris > > > > > > > > On Thu, Sep 16, 2010 at 4:43 PM, Shashi Kant <sk...@sloan.mit.edu> wrote: > >> q=*:* > >> > >> On Thu, Sep 16, 2010 at 4:39 PM, Christopher Gross <cogr...@gmail.com> > >> wrote: > >>> I have some queries that I'm running against a solr instance (older, > >>> 1.2 I believe), and I would like to get *all* the results back (and > >>> not have to put an absurdly large number as a part of the rows > >>> parameter). > >>> > >>> Is there a way that I can do that? Any help would be appreciated. > >>> > >>> -- Chris > >>> > >> > >
