>From NFPA 13-2007, 22.4.4.5.1, we are required to, among other things,
adjust the K-Factor. 

Using  the Hazen-Williams friction formula, 62.4 lb/ft3 / 144 in2 = .433
lb/in2/ft(h).

If we have an AF solution at 65.5 lb/ft3, / 144 = .455 lb/in2/ft(h).

If K=5.6, and we assume P=7 PSI.:

7/.433=16.166 ft(h). 7/.455=15.385 ft(h).*

15.385/16.166=.952. sqrt(.952)=.976, x 5.6 = 5.46.

There is a chart in 13 showing a 50% glycerin solution at about -10F
weighing about 15% more than 100% water: 62.4 x 1.15 = 71.76.
71.76/144=.498. 7/.498=14.056 ft(h). 14.056/16.166=.869. sqrt(.869)=.932, x
5.6 = 5.22.

If I had to fab the pipe today and formalize the submittal tomorrow (after
googling centipoises for several hours) I would calc it like it was 'all
wet', using K=5.22.  

* converting PSI to feet of head(h) it is seen that the denser the solution,
the 'shorter' it is. Since v=sqrt(2gh), the shorter it is the slower it is.
Making the adjustment based on "h", we have to take the square root of the
ratio, i.e., (K=Q/sqrtP). If adjusted based on velocity we would use the
ratio itself (square feet=cubic feet per second divided by feet per second):
sqrt(2*32.2*16.166)=32.266 ft/sec.

sqrt(2*32.2*15.385)=31.477 ft/sec.

31.477/32.266=.976.

 

The above is simply the type of thing I enjoy doing and like to share,
hoping it will cause no harm, to be taken or left as one sees fit.

 

thanks,

 

Brad Casterline, NICET IV

Fire Protection Division

 

FSC, Inc.

P: 913-722-3473

[email protected]

www.fsc-inc.com

 

Engineering Solutions for the Built Environment

 

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